Eric,
Thank you very much for clarification!
Best wishes
Mohammad
On Tue, Aug 3, 2021 at 6:45 PM Eric Shulman wrote:
> On Tuesday, August 3, 2021 at 6:29:11 AM UTC-7 Mohammad wrote:
>
>> <$set name="out" filter="[tag[HelloThere]] [tag[About]] [tag[Platforms]]">
>>> <$list
On Tuesday, August 3, 2021 at 6:29:11 AM UTC-7 Mohammad wrote:
> <$set name="out" filter="[tag[HelloThere]] [tag[About]] [tag[Platforms]]">
>> <$list filter="[enlistbutlast[]]"><$link/> |
>> <$list filter="[enlistlast[]] "><$link/>
>>
>>
>
> Is it possible to use *subfilter* instead of
Very nice solution Eric!
One question:
Best wishes
Mohammad
On Mon, Aug 2, 2021 at 6:02 AM Eric Shulman wrote:
> On Sunday, August 1, 2021 at 9:48:12 AM UTC-7 Atronoush wrote:
>
>> I am sure this has been addressed before but I cannot find it in forum
>> Assume you have a complex filter
Thank you all! Many useful things to learn!
@Eric,
I go with the $set widget solution, for me it is simpler and as you
explained seems to have the better performance!
Cheers
Atro
On Mon, Aug 2, 2021 at 6:02 AM Eric Shulman wrote:
> On Sunday, August 1, 2021 at 9:48:12 AM UTC-7 Atronoush
On Sunday, August 1, 2021 at 9:48:12 AM UTC-7 Atronoush wrote:
> I am sure this has been addressed before but I cannot find it in forum
> Assume you have a complex filter that results in an output containing few
> tiddlers. Then you want to show them with a delimiter e.g. pipe (|)
> One solution
Before you go too far
I added missing ] before the last operator
How do you insert the code view now in Google groups/email.
> <$list filter="[all[current]!is[system]has[one]]
> [all[current]!is[system]has[two]] [all[current]search:text[three]] -[last[]]">
>
> <$link/> | <$list
Oops, I shouldn't comment just before heading to bed. My proposed solution
gives the right string but without the active links. The join operator does
seem like a good place to start though…
Best,
R²
Le dimanche 1 août 2021 à 23:23:13 UTC+2, R² a écrit :
> Hi Atro,
>
> Thanks for posting this.
Hi Atro,
Thanks for posting this. The same issue has been bugging me for a while but
I had never looked into the operators to solve it until now. Simply use the
join operator:
<$list filter="[[foo]] [[bar]] [[tw]] +[join[ | ]]"> <$link/> should
give you what you're looking for, ie. foo | bar
Mario,
These filters are placed inside some other *$list*, I also changed it for
this question. I write the question here in a simpler way
<$list filter="[tag[foo]] [tag[bar]] [tag[tw]]"><$link/> |
The purpose is to generate
Tid One | Tid Two | Tid Three
the above code adds | to the end of
Hi,
I don't understand the purpose. all[current] will only return 1 title. The
currentTiddler. So why do you use [last[]] here?
-mario
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