ist[j], k,i)
j+=1
--- On Tue, 5/13/08, James Hartley <[EMAIL PROTECTED]> wrote:
From: James Hartley <[EMAIL PROTECTED]>
Subject: [Tutor] sorting dictionary keys?
To: tutor@python.org
Date: Tuesday, May 13, 2008, 11:06 AM
I suspect this is a brain-dead question...
Give
On Tue, May 13, 2008 at 7:58 AM, Norman Khine <[EMAIL PROTECTED]> wrote:
> how about this
>
>
> >>> d = { 'a' : 1, 'd' : 2, 'b' : 3, 'c' : 0 }
> >>> for i in sorted(set(d)):
> ... print "%s\t%s" % (i, d[i])
The set() is not needed.
Also to iterate over key, value pairs in order by key you
On Tue, May 13, 2008 at 7:32 AM, Mugund K <[EMAIL PROTECTED]> wrote:
>
> A quick but ugly [brain-dead :-) ]fix would be sorting keys seperately,
> >>> temp = d.keys()
> >>> temp.sort()
> >>> for i in temp:
Not so ugly; before sorted() was introduced (Python 2.4) that would be
the way to do it.
K
how about this
>>> d = { 'a' : 1, 'd' : 2, 'b' : 3, 'c' : 0 }
>>> for i in sorted(set(d)):
... print "%s\t%s" % (i, d[i])
...
a 1
b 3
c 0
d 2
James Hartley wrote:
I suspect this is a brain-dead question...
Given the following code, output is as expected:
$ cat te
On Tue, May 13, 2008 at 7:06 AM, James Hartley <[EMAIL PROTECTED]> wrote:
> But if the keys are sorted, I get an error:
> $ cat test1.py
> d = { 'a' : 1, 'd' : 2, 'b' : 3, 'c' : 0 }
>
> for i in d.keys().sort():
> print "%s\t%s" % (i, d[i])
> $ python test1.py
> Traceback (most recent ca
t;>
Thnx,
Mugund--- On Tue, 5/13/08, James Hartley <[EMAIL PROTECTED]> wrote:
From: James Hartley <[EMAIL PROTECTED]>Subject: [Tutor] sorting dictionary keys?To: tutor@python.orgDate: Tuesday, May 13, 2008, 11:06 AMI suspect this is a brain-dead question...
Given the following co
I suspect this is a brain-dead question...
Given the following code, output is as expected:
$ cat test.py
d = { 'a' : 1, 'd' : 2, 'b' : 3, 'c' : 0 }
for i in d.keys():
print "%s\t%s" % (i, d[i])
$ python test.py
a 1
c 0
b 3
d 2
$
But if the keys are sorted, I get an
