王超 wrote:
> yes, but I mean if I have the line like this:
>
> line = """38166 us::Video_Cat::Other; us::Video_Cat::Today Show;
> us::VC_Supplier::bc; 1002::ms://bc.wd.net/a275/video/tdy_is.asf;
> 1003::ms://bc.wd.net/a275/video/tdy_is_.fl;"""
>
> I want to get the part "us::MSNVideo_Cat::Other;
王超 wrote:
> kent:
> Thank you. I got the right results with re.findall('(us::.*?);', line).
>
> I used these codes before:
> >>> TAG_pattern = re.compile(r"(us::.*?)")
> >>> TAG_pattern.findall(line)
> and got the unwanted results 'us::'
That is because .*? will match the empty string. You hav
kent:
Thank you. I got the right results with re.findall('(us::.*?);', line).
I used these codes before:
>>> TAG_pattern = re.compile(r"(us::.*?)")
>>> TAG_pattern.findall(line)
and got the unwanted results 'us::'
Tom:
Thank you. But the number of 'us::' terms varies, and kent's solution works
w
The number of iterms - (us::.*?) - varies.
When I use re.findall with (us::*?), only several 'us::' are extracted.
Daniel
On 9/16/07, Kent Johnson <[EMAIL PROTECTED]> wrote:
>
> 王超 wrote:
> > yes, but I mean if I have the line like this:
> >
> > line = """38166 us::Video_Cat::Other; us::Video_Ca
王超 wrote:
> The number of iterms - (us::.*?) - varies.
>
> When I use re.findall with (us::*?), only several 'us::' are extracted.
I don't understand what is going wrong now. Please show the code, the
data, and tell us what you get and what you want to get.
Here is an example:
Without a group y
王超 wrote:
> hi,
>
> I want to match the regular expression from right to left, such as:
>
> TAG_pattern = re.compile(r"(us::.*) .*(1002|1003).*$")
> TAG_pattern.search(line)
>
> Does the search method support this?
What do you mean match from right to left? If you mean, match an re that
is anc
yes, but I mean if I have the line like this:
line = """38166 us::Video_Cat::Other; us::Video_Cat::Today Show;
us::VC_Supplier::bc; 1002::ms://bc.wd.net/a275/video/tdy_is.asf;
1003::ms://bc.wd.net/a275/video/tdy_is_.fl;"""
I want to get the part "us::MSNVideo_Cat::Other; us::MSNVideo_Cat::Today
S
Yep, looks like it.
>>> line = 'us::blah blah2 1002 blah3'
>>> import re
>>> TAG_pattern = re.compile(r"(us::.*) .*(1002|1003).*$")
>>> if TAG_pattern.search(line):
... print 'we have a match'
...
we have a match
>>>
>>> line2 ='us::blah blah2 1001 blah3'
>>> if TAG_pattern.search(line2):
...
hi,
I want to match the regular expression from right to left, such as:
TAG_pattern = re.compile(r"(us::.*) .*(1002|1003).*$")
TAG_pattern.search(line)
Does the search method support this?
Thanks,
Daniel
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