Hello and thank you for your answers.
I'm sorry for my late answer but I couldn't work on that issue before.
Here is what I've done in the end:
(I used this document in particular:
http://tomcat.apache.org/tomcat-7.0-doc/proxy-howto.html)
1) Here is what I added to "httpd.conf" (Apache configura
Windows IP Firewall (WIPFW) is an open source project that claims to give
similar features to iptables, but I've not used it.
On 11/10/11 1:04 AM, "Léa Massiot" wrote:
>
>Thank you all for your answers.
>
>@Mark
>Yes indeed fundamentally three operations...
>1. I guess you can only have one ROO
Hi Léa
Here are some links I've used to setup tomcat and apache together
http://tomcat.apache.org/connectors-doc/reference/apache.html
http://tomcat.apache.org/connectors-doc/webserver_howto/apache.html
http://sysadminlinux.com/cms/en/node/32 (although it's for linux most
should be good for win
On Mon, Oct 10, 2011 at 16:04, Léa Massiot wrote:
[...]
>
> I'm interested in Francis' proposal... please can you give me more details?
> Thanks!
I will but in private, this is getting offtopic ;)
--
Francis Galiegue
ONE2TEAM
Ingénieur système
Mob : +33 (0) 683 877 875
Tel : +33 (0) 178 945 552
Thank you all for your answers.
@Mark
Yes indeed fundamentally three operations...
1. I guess you can only have one ROOT WebApp not several...
It's not ok for me, I have several WebApps I want to treat that way.
@Francis
Francis wrote:
> Apache and configure a vhost with proxying
That looks pr
On Mon, Oct 10, 2011 at 14:01, Mark Thomas wrote:
[...]
>>
>> C (and C++ and many others) has seteuid() and fork(), Java doesn't.
>> Apache starts as root, binds to port 80 (therefore opens an fd on it),
>> then forks. The fd is inherited by the child, which calls seteuid().
>> Then the parent exi
On 10/10/2011 12:59, Francis GALIEGUE wrote:
> On Mon, Oct 10, 2011 at 13:50, Darryl Lewis wrote:
>> Something I've always wondered about, but never figured out, is how does
>> apache run as 'apache user' or 'nobody' and work on a port below 1024, but
>> Tomcat can't?
>> Anyone got a simple explan
>> - Presently, to access my WebApp first page, I have to type in the
>>following
>> URL in a browser:
>> http://hostname-or-ip:8080/my-webapp/
>> - Instead, I wish I could type in a URL such as:
>> http://my-webapp/
>> Is it possible?
>> How?
&g
On Mon, Oct 10, 2011 at 13:50, Darryl Lewis wrote:
> Something I've always wondered about, but never figured out, is how does
> apache run as 'apache user' or 'nobody' and work on a port below 1024, but
> Tomcat can't?
> Anyone got a simple explanation?
>
C (and C++ and many others) has seteuid()
ebapp/
>> - Instead, I wish I could type in a URL such as:
>> http://my-webapp/
>> Is it possible?
>> How?
>>
>> And by the way, I don't know what's the name of such an operation. I
>>used
>> the expression "URL simplification"..
I could type in a URL such as:
> http://my-webapp/
> Is it possible?
> How?
>
> And by the way, I don't know what's the name of such an operation. I used
> the expression "URL simplification"...
>
> Thank you for pointing me in the right direction!
Ther
[...]
>
> What I use:
> -A PREROUTING -p tcp -m tcp --dport 80 -j REDIRECT --to-ports 8080
>
You're forgetting "-t nat" before -A. REDIRECT is a target only valid
from the nat table.
--
Francis Galiegue
ONE2TEAM
Ingénieur système
Mob : +33 (0) 683 877 875
Tel : +33 (0) 178 945 552
f...@one2team
> You can also do it with iptables, converting any port 80 request to 8080.
> The user types in http://mywebapp but gets redirected to
> http://hostname:8080
+1
What I use:
-A PREROUTING -p tcp -m tcp --dport 80 -j REDIRECT --to-ports 8080
M
-
You can also do it with iptables, converting any port 80 request to 8080.
The user types in http://mywebapp but gets redirected to
http://hostname:8080
On 10/10/11 8:01 PM, "Francis GALIEGUE" wrote:
>On Mon, Oct 10, 2011 at 10:56, Léa Massiot wrote:
>>
>> Hello,
>>
>> Thank you for reading my
On Mon, Oct 10, 2011 at 10:56, Léa Massiot wrote:
>
> Hello,
>
> Thank you for reading my post. Here is my question:
>
> - Presently, to access my WebApp first page, I have to type in the following
> URL in a browser:
> http://hostname-or-ip:8080/my-webapp/
> - Instead, I wish I could type in a UR
, I don't know what's the name of such an operation. I used
the expression "URL simplification"...
Thank you for pointing me in the right direction!
Best regards,
--
Léa
--
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