Tomcat Security and Struts
Tomcat 6Struts 1.3 OS: MacOS X - Leopard Hi, I am trying to make sure my app requires a login. So I configured the following in my deployment descriptor: security-constraint web-resource-collection web-resource-nameadmin/web-resource-name url-pattern*.do/url-pattern http-methodPOST/http-method /web-resource-collection auth-constraint role-namemember/role-name /auth-constraint user-data-constraint transport-guaranteeCONFIDENTIAL/transport-guarantee /user-data-constraint /security-constraint login-config auth-methodFORM/auth-method form-login-config form-login-page/WEB-INF/JSP/login.jsp/form-login-page form-error-page/WEB-INF/JSP/loginError.jsp/form-error-page /form-login-config /login-config However, when I follow the links in my app the login page doesn't come in. Any ideas as to what I am doing wrong? Thanks.
Re: Tomcat Security and Struts
You are right: I just fixed this mistake - added security-role role-namemember/role-name /security-role into my web.xml However, when I try to access my URL the browser gives me the following message: Data Transfer Interrupted On Wed, Apr 22, 2009 at 10:26 AM, Caldarale, Charles R chuck.caldar...@unisys.com wrote: From: Mighty Tornado [mailto:mighty.torn...@gmail.com] Subject: Tomcat Security and Struts I am trying to make sure my app requires a login. So I configured the following in my deployment descriptor: security-constraint web-resource-collection web-resource-nameadmin/web-resource-name url-pattern*.do/url-pattern http-methodPOST/http-method /web-resource-collection auth-constraint role-namemember/role-name /auth-constraint user-data-constraint transport-guaranteeCONFIDENTIAL/transport-guarantee /user-data-constraint /security-constraint login-config auth-methodFORM/auth-method form-login-config form-login-page/WEB-INF/JSP/login.jsp/form-login-page form-error-page/WEB-INF/JSP/loginError.jsp/form-error-page /form-login-config /login-config Where is your security-role section? - Chuck THIS COMMUNICATION MAY CONTAIN CONFIDENTIAL AND/OR OTHERWISE PROPRIETARY MATERIAL and is thus for use only by the intended recipient. If you received this in error, please contact the sender and delete the e-mail and its attachments from all computers. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Tomcat Security and Struts
I think the following might be a problem. When I access the application I get this error in the browser:Firefox can't establish a connection to the server at localhost:8443 But Tomcat is supposed to listen on port 8080 - and it has been for my app, until I put in the security feature. any way around this? On Wed, Apr 22, 2009 at 1:05 PM, Caldarale, Charles R chuck.caldar...@unisys.com wrote: From: André Warnier [mailto:a...@ice-sa.com] Subject: Re: Tomcat Security and Struts Maybe this : if the login page itself contains a link to a gif located in the same area, trying to load that gif will also hit the authentication bit, and trigger another login page, before the first even finishes displaying ? Of course; I was thinking basic authentication, not form. - Chuck THIS COMMUNICATION MAY CONTAIN CONFIDENTIAL AND/OR OTHERWISE PROPRIETARY MATERIAL and is thus for use only by the intended recipient. If you received this in error, please contact the sender and delete the e-mail and its attachments from all computers. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Tomcat Security and Struts
How can I make the request to port 8443 actually succeed? On Wed, Apr 22, 2009 at 2:40 PM, Hassan Schroeder hassan.schroe...@gmail.com wrote: On Wed, Apr 22, 2009 at 11:16 AM, Mighty Tornado mighty.torn...@gmail.com wrote: I think the following might be a problem. When I access the application I get this error in the browser:Firefox can't establish a connection to the server at localhost:8443 But Tomcat is supposed to listen on port 8080 - and it has been for my app, until I put in the security feature. any way around this? Er, way around? You're *telling* it to use an SSL connection: user-data-constraint transport-guaranteeCONFIDENTIAL/transport-guarantee /user-data-constraint If you don't want it to, don't do that. Pretty simple, really. :-) -- Hassan Schroeder hassan.schroe...@gmail.com - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
javax.naming.NamingException: Cannot create resource instance
JVM: 1.5.0_16Tomcat: 6.0.16 2 OS: Mac OS X Leopard Hi, I defined the following context.xml under META-INF: ?xml version=1.0 encoding=UTF-8? Context path=/Household docBase=Household debug=5 reloadable=true crossContext=true Resource auth=Container description=DB Connection name=jdbc/vhousehold type=javax.sql.DataSource password=vhousehold driverClassName=com.mysql.jdbc.Driver maxIdle=2 maxWait=5000 validationQuery=/* PING */ SELECT 1; username=vhousehold url=jdbc:mysql://localhost:3306/vhousehold maxActive=4/ /Context In web.xml I have the following: resource-ref descriptionConnection Pool/description res-ref-namejdbc/vhousehold/res-ref-name res-typejavax.sql.Datasource/res-type res-authContainer/res-auth /resource-ref I try to get this data source in my application using the following code: DataSource ds = (DataSource)initContext.lookup( java:/comp/env/jdbc/vhousehold); and it fails. This is the exception I get: javax.naming.NamingException: Cannot create resource instance at org.apache.naming.factory.ResourceFactory.getObjectInstance(ResourceFactory.java:143) at javax.naming.spi.NamingManager.getObjectInstance(NamingManager.java:304) at org.apache.naming.NamingContext.lookup(NamingContext.java:793) at org.apache.naming.NamingContext.lookup(NamingContext.java:140) at org.apache.naming.NamingContext.lookup(NamingContext.java:781) at org.apache.naming.NamingContext.lookup(NamingContext.java:140) at org.apache.naming.NamingContext.lookup(NamingContext.java:781) at org.apache.naming.NamingContext.lookup(NamingContext.java:153) at org.apache.naming.SelectorContext.lookup(SelectorContext.java:137) at javax.naming.InitialContext.lookup(InitialContext.java:351) at com.vhousehold.dao.RandomPhraseDAO.getPhrases(RandomPhraseDAO.java:60) at com.vhousehold.model.RandomPhraseModel.getRandomPhrase(RandomPhraseModel.java:19) at com.vhousehold.servlet.VHController.doPost(VHController.java:52) at com.vhousehold.servlet.VHController.doGet(VHController.java:35) at javax.servlet.http.HttpServlet.service(HttpServlet.java:617) at javax.servlet.http.HttpServlet.service(HttpServlet.java:717) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:286) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:845) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:583) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:447) at java.lang.Thread.run(Thread.java:613) Any suggestions as to what I am doing wrong? Thanks.
Re: javax.naming.NamingException: Cannot create resource instance
I added the same entry to context.xml under $CATALINA/conf and it did work. Could there be something else wrong? On Mon, Apr 6, 2009 at 12:30 PM, Pid p...@pidster.com wrote: Mighty Tornado wrote: JVM: 1.5.0_16Tomcat: 6.0.16 2 OS: Mac OS X Leopard Hi, I defined the following context.xml under META-INF: ?xml version=1.0 encoding=UTF-8? Context path=/Household docBase=Household debug=5 reloadable=true crossContext=true Resource auth=Container description=DB Connection name=jdbc/vhousehold type=javax.sql.DataSource password=vhousehold driverClassName=com.mysql.jdbc.Driver maxIdle=2 maxWait=5000 validationQuery=/* PING */ SELECT 1; username=vhousehold url=jdbc:mysql://localhost:3306/vhousehold maxActive=4/ /Context In web.xml I have the following: resource-ref descriptionConnection Pool/description res-ref-namejdbc/vhousehold/res-ref-name res-typejavax.sql.Datasource/res-type res-authContainer/res-auth /resource-ref I try to get this data source in my application using the following code: DataSource ds = (DataSource)initContext.lookup( java:/comp/env/jdbc/vhousehold); and it fails. This is the exception I get: javax.naming.NamingException: Cannot create resource instance at org.apache.naming.factory.ResourceFactory.getObjectInstance(ResourceFactory.java:143) at javax.naming.spi.NamingManager.getObjectInstance(NamingManager.java:304) at org.apache.naming.NamingContext.lookup(NamingContext.java:793) at org.apache.naming.NamingContext.lookup(NamingContext.java:140) at org.apache.naming.NamingContext.lookup(NamingContext.java:781) at org.apache.naming.NamingContext.lookup(NamingContext.java:140) at org.apache.naming.NamingContext.lookup(NamingContext.java:781) at org.apache.naming.NamingContext.lookup(NamingContext.java:153) at org.apache.naming.SelectorContext.lookup(SelectorContext.java:137) at javax.naming.InitialContext.lookup(InitialContext.java:351) at com.vhousehold.dao.RandomPhraseDAO.getPhrases(RandomPhraseDAO.java:60) at com.vhousehold.model.RandomPhraseModel.getRandomPhrase(RandomPhraseModel.java:19) at com.vhousehold.servlet.VHController.doPost(VHController.java:52) at com.vhousehold.servlet.VHController.doGet(VHController.java:35) at javax.servlet.http.HttpServlet.service(HttpServlet.java:617) at javax.servlet.http.HttpServlet.service(HttpServlet.java:717) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:286) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:845) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:583) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:447) at java.lang.Thread.run(Thread.java:613) Any suggestions as to what I am doing wrong? You've added the path and docBase attributes to your META-INF/context.xml. Don't do that. Are the credentials you're using for the database correct? p Thanks. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
a href to another JSP
Hi, I have an index.jsp page with 3 links to other JSP's. These links don't seem to work. I get the 404 error. Do I have to register the JSP's somewhere similarly to how I create servlet mappings? in the href attribute I tried passing along both relative path - sine all my JSP's are in one directory called JSP under the app root so I wrote something like ./mission.jsp And I also tried giving the absolute path - /JSP/mission.jsp - no luck. Thanks.
Re: Restarting Tomcat from Ant
This worked:
target name=start-tomcat
exec os=Mac OS X executable=/bin/sh
arg line=${TOMCAT}/bin/startup.sh /
/exec
/target
On Fri, Apr 3, 2009 at 7:19 AM, Gregor Schneider rc4...@googlemail.comwrote:
How about
exec dir=${TOMCAT}/bin/ executable=./shutdown.sh /
Rgds
Gregor
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Restarting Tomcat from Ant
Hi, I currently copy the Application files to CATALINA_HOME/webapps from Ant, and then run shutdown and startup. Is there a way to also restart the server from Ant? Thanks,
Re: Restarting Tomcat from Ant
I tried the following Chuck,
target name=stop-tomcat
exec dir=${TOMCAT}/bin/ executable=shutdown.sh /
/target
but it tells me that the script cannot be found
On Thu, Apr 2, 2009 at 2:21 PM, Caldarale, Charles R
chuck.caldar...@unisys.com wrote:
From: Mighty Tornado [mailto:mighty.torn...@gmail.com]
Subject: Restarting Tomcat from Ant
Is there a way to also restart the server
from Ant?
Why don't you just use the startup and shutdown scripts that come with
Tomcat? If you want to call them from within an ant script, use the exec
task.
- Chuck
THIS COMMUNICATION MAY CONTAIN CONFIDENTIAL AND/OR OTHERWISE PROPRIETARY
MATERIAL and is thus for use only by the intended recipient. If you received
this in error, please contact the sender and delete the e-mail and its
attachments from all computers.
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Re: DataSource from Context files - doesn't work
Additional info:
I get the following exception in the log when I start the server up:
== localhost.2009-03-03.log ==
at
org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at
org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at
org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128)
at
org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
at
org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at
org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:286)
at
org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:845)
at
org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:583)
at
org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:447)
at java.lang.Thread.run(Thread.java:613)
I use the following code to get the connection:
InitialContext ic = new InitialContext();
if(ic == null)
{
System.out.println(context not found);
}
DataSource ds =
(DataSource)ic.lookup(java:comp/env/jdbc/vhousehold);
if(ds == null)
{
System.out.println(DataSource not found);
}
conn = ds.getConnection();
stat = conn.createStatement();
rs = stat.executeQuery(SELECT * FROM family_member );
On Tue, Mar 31, 2009 at 9:36 PM, Mighty Tornado mighty.torn...@gmail.comwrote:
Hi I placed the following in context.xml in META-INF.
But the result set is null, what's wrong with my set up?Can anybody please
advise?
?xml version=1.0 encoding=UTF-8?
Context
Resource
auth=Container
description=DB Connection
name=jdbc/vhousehold
type=javax.sql.DataSource
password=vhousehold
driverClassName=com.mysql.jdbc.Driver
maxIdle=2
maxWait=5000
validationQuery=select * from family_member;
username=vhousehold
url=jdbc:mysql://localhost:3306/vhousehold
maxActive=4/
/Context
Thanks,
Ramy.
Re: DataSource from Context files - doesn't work
Where can I obtain it?
The exception that I posted is the only exception that showed up following
tail -f *
On Wed, Apr 1, 2009 at 6:04 AM, Gregor rc4...@googlemail.com wrote:
your log is useless.
please post the complete stacktrace incl. the type of the exception
rds
gregor
Am 01.04.2009 um 11:57 schrieb Mighty Tornado mighty.torn...@gmail.com:
Additional info:
I get the following exception in the log when I start the server up:
== localhost.2009-03-03.log ==
at
org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at
org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at
org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128)
at
org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
at
org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at
org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:286)
at
org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:845)
at
org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:583)
at
org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:447)
at java.lang.Thread.run(Thread.java:613)
I use the following code to get the connection:
InitialContext ic = new InitialContext();
if(ic == null)
{
System.out.println(context not found);
}
DataSource ds =
(DataSource)ic.lookup(java:comp/env/jdbc/vhousehold);
if(ds == null)
{
System.out.println(DataSource not found);
}
conn = ds.getConnection();
stat = conn.createStatement();
rs = stat.executeQuery(SELECT * FROM family_member );
On Tue, Mar 31, 2009 at 9:36 PM, Mighty Tornado mighty.torn...@gmail.com
wrote:
Hi I placed the following in context.xml in META-INF.
But the result set is null, what's wrong with my set up?Can anybody
please
advise?
?xml version=1.0 encoding=UTF-8?
Context
Resource
auth=Container
description=DB Connection
name=jdbc/vhousehold
type=javax.sql.DataSource
password=vhousehold
driverClassName=com.mysql.jdbc.Driver
maxIdle=2
maxWait=5000
validationQuery=select * from family_member;
username=vhousehold
url=jdbc:mysql://localhost:3306/vhousehold
maxActive=4/
/Context
Thanks,
Ramy.
-
To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org
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Re: DataSource from Context files - doesn't work
No Exception there. Even after I restart the server and call the Servlet
that is supposed to retrieve the DB data.
On Wed, Apr 1, 2009 at 6:24 AM, Yassine elas...@users.sourceforge.netwrote:
catalina.out
On Wed, Apr 1, 2009 at 12:17 PM, Mighty Tornado
mighty.torn...@gmail.com wrote:
I have the following files in the logs directory:
admin.2009-04-01.log
catalina.out
localhost.2009-04-01.log
catalina.2009-04-01.log
host-manager.2009-04-01.log
manager.2009-04-01.log
Which one of them should I VI or LESS to find the complete stack trace
for
the exception?
Also, is there something obviously wrong with my context definition or
reference? I followed the Tomcat online tutorial to define them.
Also, previously a regular JDBC code with the same parameters was able to
access the DB and retrieve the data correctly.
Thank you all.
On Wed, Apr 1, 2009 at 6:09 AM, Yassine elas...@users.sourceforge.net
wrote:
don't tail -f
use less and copy the part containing the exception from its beginning
to the end.
On Wed, Apr 1, 2009 at 12:07 PM, Mighty Tornado
mighty.torn...@gmail.com wrote:
Where can I obtain it?
The exception that I posted is the only exception that showed up
following
tail -f *
On Wed, Apr 1, 2009 at 6:04 AM, Gregor rc4...@googlemail.com wrote:
your log is useless.
please post the complete stacktrace incl. the type of the exception
rds
gregor
Am 01.04.2009 um 11:57 schrieb Mighty Tornado
mighty.torn...@gmail.com
:
Additional info:
I get the following exception in the log when I start the server up:
== localhost.2009-03-03.log ==
at
org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at
org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at
org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128)
at
org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
at
org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at
org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:286)
at
org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:845)
at
org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:583)
at
org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:447)
at java.lang.Thread.run(Thread.java:613)
I use the following code to get the connection:
InitialContext ic = new InitialContext();
if(ic == null)
{
System.out.println(context not found);
}
DataSource ds =
(DataSource)ic.lookup(java:comp/env/jdbc/vhousehold);
if(ds == null)
{
System.out.println(DataSource not found);
}
conn = ds.getConnection();
stat = conn.createStatement();
rs = stat.executeQuery(SELECT * FROM family_member );
On Tue, Mar 31, 2009 at 9:36 PM, Mighty Tornado
mighty.torn...@gmail.com
wrote:
Hi I placed the following in context.xml in META-INF.
But the result set is null, what's wrong with my set up?Can anybody
please
advise?
?xml version=1.0 encoding=UTF-8?
Context
Resource
auth=Container
description=DB Connection
name=jdbc/vhousehold
type=javax.sql.DataSource
password=vhousehold
driverClassName=com.mysql.jdbc.Driver
maxIdle=2
maxWait=5000
validationQuery=select * from family_member;
username=vhousehold
url=jdbc:mysql://localhost:3306/vhousehold
maxActive=4/
/Context
Thanks,
Ramy.
-
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--
--
Yassine Elassad
Bonn, Germany.
Fon : +49 228 97629355
Mobile : +49 157 74519666
PEACE :
( P ) Positive ( E ) Energy ( A ) Always ( C ) Correct ( E ) Errors.
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--
--
Yassine Elassad
Bonn, Germany.
Fon : +49 228 97629355
Mobile : +49 157 74519666
PEACE :
( P ) Positive ( E ) Energy ( A ) Always ( C ) Correct ( E ) Errors.
-
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For additional commands, e-mail: users-h...@tomcat.apache.org
Re: DataSource from Context files - doesn't work
guess it was an old exception. no new ones in the logs. But I am doing something wrong with the way I define the data source and hand it to Tomcat for handling. Any suggestions as to how I can find out where the mistake is? On Wed, Apr 1, 2009 at 6:36 AM, Gregor Schneider rc4...@googlemail.comwrote: On Wed, Apr 1, 2009 at 12:07 PM, Mighty Tornado mighty.torn...@gmail.com wrote: Where can I obtain it? You wrote before: I get the following exception in the log when I start the server up: == localhost.2009-03-03.log == at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at so in that log there should be the complete stacktrace of the exception including it's type. Unfortunately my apps are working like charm, so I ain't got an example to cpy and post here... *cough* Rgds Gregor @ Yassine: Availabe for a chat via Google? I got your shirts, remeber... ;) -- just because your paranoid, doesn't mean they're not after you... gpgp-fp: 79A84FA526807026795E4209D3B3FE028B3170B2 gpgp-key available @ http://pgpkeys.pca.dfn.de:11371 @ http://pgp.mit.edu:11371/ - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: DataSource from Context files - doesn't work
I have the following files in the logs directory:
admin.2009-04-01.log
catalina.out
localhost.2009-04-01.log
catalina.2009-04-01.log
host-manager.2009-04-01.log
manager.2009-04-01.log
Which one of them should I VI or LESS to find the complete stack trace for
the exception?
Also, is there something obviously wrong with my context definition or
reference? I followed the Tomcat online tutorial to define them.
Also, previously a regular JDBC code with the same parameters was able to
access the DB and retrieve the data correctly.
Thank you all.
On Wed, Apr 1, 2009 at 6:09 AM, Yassine elas...@users.sourceforge.netwrote:
don't tail -f
use less and copy the part containing the exception from its beginning
to the end.
On Wed, Apr 1, 2009 at 12:07 PM, Mighty Tornado
mighty.torn...@gmail.com wrote:
Where can I obtain it?
The exception that I posted is the only exception that showed up
following
tail -f *
On Wed, Apr 1, 2009 at 6:04 AM, Gregor rc4...@googlemail.com wrote:
your log is useless.
please post the complete stacktrace incl. the type of the exception
rds
gregor
Am 01.04.2009 um 11:57 schrieb Mighty Tornado mighty.torn...@gmail.com
:
Additional info:
I get the following exception in the log when I start the server up:
== localhost.2009-03-03.log ==
at
org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at
org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at
org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128)
at
org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
at
org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at
org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:286)
at
org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:845)
at
org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:583)
at
org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:447)
at java.lang.Thread.run(Thread.java:613)
I use the following code to get the connection:
InitialContext ic = new InitialContext();
if(ic == null)
{
System.out.println(context not found);
}
DataSource ds =
(DataSource)ic.lookup(java:comp/env/jdbc/vhousehold);
if(ds == null)
{
System.out.println(DataSource not found);
}
conn = ds.getConnection();
stat = conn.createStatement();
rs = stat.executeQuery(SELECT * FROM family_member );
On Tue, Mar 31, 2009 at 9:36 PM, Mighty Tornado
mighty.torn...@gmail.com
wrote:
Hi I placed the following in context.xml in META-INF.
But the result set is null, what's wrong with my set up?Can anybody
please
advise?
?xml version=1.0 encoding=UTF-8?
Context
Resource
auth=Container
description=DB Connection
name=jdbc/vhousehold
type=javax.sql.DataSource
password=vhousehold
driverClassName=com.mysql.jdbc.Driver
maxIdle=2
maxWait=5000
validationQuery=select * from family_member;
username=vhousehold
url=jdbc:mysql://localhost:3306/vhousehold
maxActive=4/
/Context
Thanks,
Ramy.
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Re: DataSource from Context files - doesn't work
Trying to put in some logging statements. Can anyone suggest where System.out prints to? I don't see it in any of the logs. On Wed, Apr 1, 2009 at 8:47 AM, Christopher Schultz ch...@christopherschultz.net wrote: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Ramy, (Hey! I found my original message. Here's a bit more detail on the validationQuery) On 3/31/2009 9:36 PM, Mighty Tornado wrote: Hi I placed the following in context.xml in META-INF. But the result set is null, what's wrong with my set up? Can anybody please advise? As others have suggested, your exception does not include the important part: what actually happened. We only got a piece of what happened. You say that it's an old exception so maybe it's unrelated. Let's take a look at your configuration: validationQuery=select * from family_member; Yikes! A complete table-scan for each validation query? I would recommend something like /* PING */ SELECT 1 where the database doesn't have to do any work to fulfill the query. Remember, the validation query just checks to see if communication with the database is still working. It's not intended to return any actual data. Other than that, your configuration looks good. It appears to be working, so you're probably fine. (See my other message with comments on your code) - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.9 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAknTYkYACgkQ9CaO5/Lv0PArVwCeNrLv9Z57uFqpM6i9c4OU4AmD sJYAoK6l6VD93NAjvDEhxkBPWDtJDk0T =mdTH -END PGP SIGNATURE- - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
DataSource from Context files - doesn't work
Hi I placed the following in context.xml in META-INF. But the result set is null, what's wrong with my set up?Can anybody please advise? ?xml version=1.0 encoding=UTF-8? Context Resource auth=Container description=DB Connection name=jdbc/vhousehold type=javax.sql.DataSource password=vhousehold driverClassName=com.mysql.jdbc.Driver maxIdle=2 maxWait=5000 validationQuery=select * from family_member; username=vhousehold url=jdbc:mysql://localhost:3306/vhousehold maxActive=4/ /Context Thanks, Ramy.
Tomcat Data sources and connection pools
Hi, A couple of questions regarding Tomcat 6 Data Sources. 1. I used WebLogic previously and there you had to configure connection pools and then create data sources and link them to connection pools. Is the process the same in Tomcat? 2. From what I understand I need to create the data source definition in the Context element of an xml file. Which xml file is it? Thanks.
Re: Tomcat Data sources and connection pools
So do I understand this correctly? Tomcat will read the context.xml file in the META-INF directory and get the data source from there? I also added a resource ref in my web.xml because that's what various tutorials suggest. After that is done, how do I obtain a connection? and one more question, is it correct to make a DAO a singleton? Thanks, On Sun, Mar 22, 2009 at 7:57 PM, Caldarale, Charles R chuck.caldar...@unisys.com wrote: From: Mighty Tornado [mailto:mighty.torn...@gmail.com] Subject: Tomcat Data sources and connection pools 1. I used WebLogic previously and there you had to configure connection pools and then create data sources and link them to connection pools. You can manage the pool yourself, but it's certainly easier if you let Tomcat do it. The doc is here: http://tomcat.apache.org/tomcat-6.0-doc/jndi-datasource-examples-howto.html 2. From what I understand I need to create the data source definition in the Context element of an xml file. Which xml file is it? You can define the data source in a Context file if you want it available only to one webapp, or as a GlobalResource if you want it available to all webapps. A Context element describes the Tomcat-specific configuration for a webapp; it is normally located within the webapp at META-INF/context.xml, or you can also put it at conf/Catalina/[host]/[appName].xml if you want to keep it outside of the webapp's .war file or directory. (For compatibility with older Tomcat versions, you can also put it in conf/server.xml, but that's strongly discouraged these days.) Doc is here: http://tomcat.apache.org/tomcat-6.0-doc/config/context.html Do not use the path of docBase attributes when using one of the standard location for your Context element and webapp. - Chuck THIS COMMUNICATION MAY CONTAIN CONFIDENTIAL AND/OR OTHERWISE PROPRIETARY MATERIAL and is thus for use only by the intended recipient. If you received this in error, please contact the sender and delete the e-mail and its attachments from all computers. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Testing DB before creating Connection Pools
Hi, I am encountering a problem when trying to test JDBC connection to my database before I hand it over to the container. I get the No suitable driver exception wen trying to run the test main class in Eclipse, even though I added the mysql connector jar to the build path in the project. Thanks,
Newline doesn't work
Silly question. I wrote a servlet that gets init params from the web.xml and stuffs them into the request which is the displayed by JSP. But when I try to make it a string with newline characters it still prints everything in one line - like newline characters turn into regular space characters. This is the code: String newline = System.getProperty(line.separator); String rName = getServletConfig().getInitParameter(rName); String kName = getServletConfig().getInitParameter(kName); result += Family Members + newline; result += rName + newline; result += kName + newline; I tried \n, and '\n' as well. Thanks.
Re: Newline doesn't work
Thank you all. The answers were very valuable and I got the thing to work. On Wed, Mar 18, 2009 at 1:41 PM, Ilya Kazakevich kazakev...@devexperts.comwrote: Mighty, Here is good and small HTML tutorial, which I advice you to read: http://www.w3schools.com/html/default.asp -Original Message- From: Caldarale, Charles R [mailto:chuck.caldar...@unisys.com] Sent: Wednesday, March 18, 2009 7:41 PM To: Tomcat Users List Subject: RE: Newline doesn't work From: Mighty Tornado [mailto:mighty.torn...@gmail.com] Subject: Newline doesn't work But when I try to make it a string with newline characters it still prints everything in one line - like newline characters turn into regular space characters. That's the way HTML works. You need to separate lines by p or br; experiment with both to see which is more to your liking. - Chuck THIS COMMUNICATION MAY CONTAIN CONFIDENTIAL AND/OR OTHERWISE PROPRIETARY MATERIAL and is thus for use only by the intended recipient. If you received this in error, please contact the sender and delete the e-mail and its attachments from all computers. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Console Output
Hi, I am running Tomcat on Mac OS X. How can I see output on the console of the command line? For example, if I would like to put System.out statements in the code and would like to see them on the console. Thanks,
Can't use J2EE libraries in Eclipse
Hi, I am working on Mac OS X. I have the latest version of Tomcat, and Eclipse Europa. Mac OS X did not come with J2EE. I downloaded J2EE with GlassFish from Sun. Set it up by running the setup shell script. Unfortunately the directory structure is very different now, I am guessing the J2EE is inside GlassFish somewhere. I need to set it up in Eclipse to be able to compile Servlets and the like. and I cannot find the right Jars. 1. Could somebody point me to where the jars are now within GlassFish so I can add them to Eclipse? 2. Is there a way to install J2EE without this GlassFish stuff, just alongside the J2SE? Thank you.
Re: Can't use J2EE libraries in Eclipse
Thanks, I resolved this issue by having Eclipse use the Tomcat SDK. Unfortunately I now have a different problem with my initial app. I have an HTML page - index.html which asks the user to select one of two values from a dropdown and then click a Submit button. It's a regular HTML form using POST request. I have a context in my server.xml, I have a servlet mapped in web.xml. I have the servlet class compiled and in the deployment dir under webapps in tomcat directory. However, when I hit the submit button on the HTML, nothing happens. not sure where I went wrong. On Sun, Mar 1, 2009 at 8:56 AM, supareno reno.rkc...@free.fr wrote: Mighty, you need to add to your classpath project the servlet.api to compile servlet tomcat6.0.x/lib/servlet-api.api (right click on the projet - build path/configure build path choose librairy/ add external jar) in glassfish v2, it is in glassfish/lib/javaee.jar now with javaee5, i'm not sure that is possible to download the ee sdk separeted from glassfish it was possible with j2ee 1.4 hope this help supareno Hi, I am working on Mac OS X. I have the latest version of Tomcat, and Eclipse Europa. Mac OS X did not come with J2EE. I downloaded J2EE with GlassFish from Sun. Set it up by running the setup shell script. Unfortunately the directory structure is very different now, I am guessing the J2EE is inside GlassFish somewhere. I need to set it up in Eclipse to be able to compile Servlets and the like. and I cannot find the right Jars. 1. Could somebody point me to where the jars are now within GlassFish so I can add them to Eclipse? 2. Is there a way to install J2EE without this GlassFish stuff, just alongside the J2SE? Thank you. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: Can't use J2EE libraries in Eclipse
Here is what I have: HTML form action=GetInfo.do method=post p Please Choose Info: /p select name=InfoSelect option value=MembersFamily Members/option option value=TimeTime/option /select /form input type=submit web.xml === welcome-file-list welcome-file/HTML/index.html/welcome-file /welcome-file-list servlet servlet-nameGetInfo/servlet-name servlet-classcom.Household.servlet.GetInfo/servlet-class /servlet servlet-mapping servlet-nameGetInfo/servlet-name url-pattern/GetInfo.do/url-pattern /servlet-mapping On Sun, Mar 1, 2009 at 7:31 PM, Martin Gainty mgai...@hotmail.com wrote: you need to identify a program that submit will post to as in this example form method=POST action='chat' name=loginForm input type=hidden name=action value=login/ Nickname: input type=text name=nickname/ /form where the contents of web.xml map chat to submit its contents to ChatServlet servlet-mapping servlet-nameChatServlet/servlet-name url-pattern/jsp/chat/chat/url-pattern /servlet-mapping where ChatServlet maps to the ChatServlet class located in /WEB-INF/classes/chat/ChatServlet servlet servlet-nameChatServlet/servlet-name servlet-classchat.ChatServlet/servlet-class /servlet Martin __ Disclaimer and confidentiality note Everything in this e-mail and any attachments relates to the official business of Sender. This transmission is of a confidential nature and Sender does not endorse distribution to any party other than intended recipient. Sender does not necessarily endorse content contained within this transmission. Date: Sun, 1 Mar 2009 19:02:03 -0500 Subject: Re: Can't use J2EE libraries in Eclipse From: mighty.torn...@gmail.com To: users@tomcat.apache.org Thanks, I resolved this issue by having Eclipse use the Tomcat SDK. Unfortunately I now have a different problem with my initial app. I have an HTML page - index.html which asks the user to select one of two values from a dropdown and then click a Submit button. It's a regular HTML form using POST request. I have a context in my server.xml, I have a servlet mapped in web.xml. I have the servlet class compiled and in the deployment dir under webapps in tomcat directory. However, when I hit the submit button on the HTML, nothing happens. not sure where I went wrong. On Sun, Mar 1, 2009 at 8:56 AM, supareno reno.rkc...@free.fr wrote: Mighty, you need to add to your classpath project the servlet.api to compile servlet tomcat6.0.x/lib/servlet-api.api (right click on the projet - build path/configure build path choose librairy/ add external jar) in glassfish v2, it is in glassfish/lib/javaee.jar now with javaee5, i'm not sure that is possible to download the ee sdk separeted from glassfish it was possible with j2ee 1.4 hope this help supareno Hi, I am working on Mac OS X. I have the latest version of Tomcat, and Eclipse Europa. Mac OS X did not come with J2EE. I downloaded J2EE with GlassFish from Sun. Set it up by running the setup shell script. Unfortunately the directory structure is very different now, I am guessing the J2EE is inside GlassFish somewhere. I need to set it up in Eclipse to be able to compile Servlets and the like. and I cannot find the right Jars. 1. Could somebody point me to where the jars are now within GlassFish so I can add them to Eclipse? 2. Is there a way to install J2EE without this GlassFish stuff, just alongside the J2SE? Thank you. - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org _ Express your personality in color! Preview and select themes for Hotmail®. http://www.windowslive-hotmail.com/LearnMore/personalize.aspx?ocid=TXT_MSGTX_WL_HM_express_032009#colortheme
Fwd: J2EE on Mac
Hi, I installed Tomcat on my mac OS X and it's running. I also have Eclipse Europa. Now I don't think I have J2EE installed - How do I do it? I went to Sun's website and it gave me an archive with GlassFish which I don't need. Can somebody please tell me where I can download the latest J2EE for Mac? What I need to do to compile servlets with it in Eclipse? Thank you.
Re: sending smtp mail failure
I have ZoneAlarm running, but normally Zone Alarm notifies me if a program from within is trying to access the internet and let's me block it or let it go. Is it possible that ZA is blocking not my request to connect to the smtp server but the server's reply? On 4/19/07, Christopher Schultz [EMAIL PROTECTED] wrote: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 MT, Mighty Tornado wrote: It was churning for a long time and still didn't manage to send the email. But it left me this exception: [snip] Caused by: javax.mail.MessagingException: Could not connect to SMTP host: smtp.gmail.com, port: 465, response: -1 - From the command-line on your server, can you telnet to smtp.gmail.com:465? I'm wondering if you have a firewall that won't allow you to make that connection. I heeded your advice and tried setting up Outlook Express for gmail server. This is the message that I got: The connection to the server has failed. Account: 'smtp.google.com', Server: 'smtp.google.com', Protocol: SMTP, Port: 25, Secure(SSL): No, Socket Error: 10060, Error Number: 0x800CCC0E So, it looks like this isn't a problem specific to Java. I'm guessing that you are being blocked somewhere. Microsoft Windows versions since 2000 (at least) have had software firewalls built into them that you can easily configure. You may also have another firewall on your network between you and google's SMTP server. If that's the case, you'll have to change the configuration of the firewall(s) to allow communication. - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.7 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org iD8DBQFGJ2z19CaO5/Lv0PARAhw7AJ0eEUTkWPr0SJkAOysnoUHAWqb7FACeItA9 Z2wwl1/F8zG5/ahCnAdNIMY= =1Ll0 -END PGP SIGNATURE- - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: sending smtp mail failure
It was churning for a long time and still didn't manage to send the email. But it left me this exception: org.apache.commons.mail.EmailException: Sending the email to the following serve r failed : smtp.gmail.com:465 at org.apache.commons.mail.Email.sendMimeMessage(Email.java:873) at org.apache.commons.mail.Email.send(Email.java:898) at TimeTravelMailer.sendMessage(TimeTravelMailer.java:29) at CreateAccountServlet.doPost(CreateAccountServlet.java:12) at javax.servlet.http.HttpServlet.service(HttpServlet.java:710) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter (Appl icationFilterChain.java:269) at org.apache.catalina.core.ApplicationFilterChain.doFilter (ApplicationF ilterChain.java:188) at org.apache.catalina.core.StandardWrapperValve.invoke (StandardWrapperV alve.java:210) at org.apache.catalina.core.StandardContextValve.invoke (StandardContextV alve.java:174) at org.apache.catalina.core.StandardHostValve.invoke( StandardHostValve.j ava:127) at org.apache.catalina.valves.ErrorReportValve.invoke( ErrorReportValve.j ava:117) at org.apache.catalina.core.StandardEngineValve.invoke (StandardEngineVal ve.java:108) at org.apache.catalina.connector.CoyoteAdapter.service( CoyoteAdapter.jav a:151) at org.apache.coyote.http11.Http11Processor.process( Http11Processor.java :870) at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.p rocessConnection(Http11BaseProtocol.java:665) at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket (PoolTcpEndpo int.java:528) at org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt (LeaderFol lowerWorkerThread.java:81) at org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run (ThreadP ool.java:685) at java.lang.Thread.run(Thread.java:619) Caused by: javax.mail.MessagingException: Could not connect to SMTP host: smtp.g mail.com, port: 465, response: -1 at com.sun.mail.smtp.SMTPTransport.openServer(SMTPTransport.java :1270) at com.sun.mail.smtp.SMTPTransport.protocolConnect( SMTPTransport.java:37 0) at javax.mail.Service.connect(Service.java:297) at javax.mail.Service.connect(Service.java:156) at javax.mail.Service.connect(Service.java:105) at javax.mail.Transport.send0(Transport.java:168) at javax.mail.Transport.send(Transport.java:98) at org.apache.commons.mail.Email.sendMimeMessage(Email.java:863) ... 19 more On 4/17/07, Johnny Kewl [EMAIL PROTECTED] wrote: Ha ha now you need to read up on threads and background processing Very good description in the java tutorial from sun. The browser will wait so u need to start the email as a background process. The browser will come back instantly, and depending on what u doing, you will have to log the error messages, and possibly allow the user to see a report via the browser. enjoy - Original Message - From: Mighty Tornado [EMAIL PROTECTED] To: Tomcat Users List users@tomcat.apache.org Sent: Tuesday, April 17, 2007 2:35 AM Subject: Re: sending smtp mail failure Thanks for the input, I was able to actually send email from Outlook Express after changing port numbers and changing the host name to smtp.gmail.com instead of smtp.google.com. Now I encountered a different problem - when I attempt to send an email from a servlet running on my local XP machine it looks like it is doing something but the green bar in the browser doesn't progress, it is there but stays white. And no exceptions thrown. Just sitting there not proceeding to the next page. Like it is trying to send an email but it is taking a year. On 4/16/07, Len Popp [EMAIL PROTECTED] wrote: That's a timeout error. I was able to send an email thru smtp.google.com using Outlook Express, with no timeout error, so it looks like there's something wrong with either your email settings or your connection to gmail.com (firewall or something). Google has a troubleshooter program to diagnose POP SMTP setup problems: http://mail.google.com/support/bin/answer.py?answer=44769 -- Len On 4/16/07, Mighty Tornado [EMAIL PROTECTED] wrote: I heeded your advice and tried setting up Outlook Express for gmail server. This is the message that I got: The connection to the server has failed. Account: 'smtp.google.com', Server: 'smtp.google.com', Protocol: SMTP, Port: 25, Secure(SSL): No, Socket Error: 10060, Error Number: 0x800CCC0E On 4/15/07, Johnny Kewl [EMAIL PROTECTED] wrote: Here is a little framework that u can play with MimeMessage msg = new MimeMessage(session); msg.setFrom(new InternetAddress(from)); msg.addRecipient(Message.RecipientType.TO, new InternetAddress(to)); msg.setSubject(subject); msg.setSentDate(new Date()); // ADD TEXT
Re: sending smtp mail failure
Thanks for responding,
there something wrong with my code?
This is my code:
import java.util.*;
import java.io.*;
import javax.mail.*;
import javax.mail.internet.*;
import javax.activation.*;
public class TimeTravelMailer
{
public void sendMessage()
{
String to = [EMAIL PROTECTED];
String from = [EMAIL PROTECTED];
String host = smtp.google.com;
String message = This is a test;
Properties props = new Properties();
props.put(mail.smtp.host, host);
Session session = Session.getInstance(props);
try
{
Transport bus = session.getTransport(smtp);
bus.connect(host, [EMAIL PROTECTED], [EMAIL PROTECTED]);
Message msg = new MimeMessage(session);
msg.setFrom(new InternetAddress(from));
InternetAddress[] address = {new InternetAddress(to)};
msg.setRecipients(Message.RecipientType.TO, address);
msg.setRecipients(Message.RecipientType.CC,
InternetAddress.parse(to, true));
msg.setRecipients(Message.RecipientType.BCC,
InternetAddress.parse(to, false));
msg.setSubject(Test E-Mail through Java);
msg.setSentDate(new Date());
msg.setText(message);
msg.saveChanges();
bus.sendMessage(msg, address);
bus.close();
}
catch(Exception ex)
{
ex.printStackTrace();
}
}
}
On 4/7/07, Johnny Kewl [EMAIL PROTECTED] wrote:
Easiest way is to setup a normal email program and see what the error
messages are.
If the machine doesnt have core mailing engines installed, it will
probably
tell you.
If you on windows, try Outlook express, detailed messages will probably
point you in right direction.
Code should look something like this
public boolean prepareConnection(String smtpHost){
this.smtpHost = smtpHost;
fSessionInited = true;
try{
java.util.Properties properties = System.getProperties();
properties.put(mail.smtp.host, smtpHost);
session = Session.getInstance(properties,null);
} catch(Exception e) {
fSessionInited = false;
}
return fSessionInited;
}
- Original Message -
From: Mighty Tornado [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, April 06, 2007 7:30 AM
Subject: sending smtp mail failure
Hi,
I set up a small web app and the servlet is supposed to send an email
using
JavaMail. But I am getting exceptions - Connection Timed out every time.
I
am using Gmail as an smtp server to bounce emails off. How can I avoid
the
Connection Timed out exception? Could it be because of my firewall? If
so,
which process should I permission?
Thank you,
MT
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To start a new topic, e-mail: [EMAIL PROTECTED]
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
sending smtp mail failure
Hi, I set up a small web app and the servlet is supposed to send an email using JavaMail. But I am getting exceptions - Connection Timed out every time. I am using Gmail as an smtp server to bounce emails off. How can I avoid the Connection Timed out exception? Could it be because of my firewall? If so, which process should I permission? Thank you, MT
