Re: Locating WebAppConfig file in embedded tomcat
Am 2015-04-28 12:10, schrieb benrog:
Hi
we use an embedded Tomcat and are trying to update from version 7.0.40
to
7.0.61. The the embedded tomcat instance starts up fine and our webapp
is
also running. However we get the following warning:
Apr 28, 2015 8:58:58 AM org.apache.catalina.startup.Tomcat
getWebappConfigFileFromJar
WARNING: Unable to determine web application context.xml webapp-name
java.io.FileNotFoundException: webapp-name (System cannot find file)
at java.util.zip.ZipFile.open(Native Method)
at java.util.zip.ZipFile.init(ZipFile.java:215)
at java.util.zip.ZipFile.init(ZipFile.java:145)
at java.util.jar.JarFile.init(JarFile.java:153)
at java.util.jar.JarFile.init(JarFile.java:117)
at
org.apache.catalina.startup.Tomcat.getWebappConfigFileFromJa
r(Tomcat.java:1162)
at
org.apache.catalina.startup.Tomcat.getWebappConfigFile(Tomca
t.java:1140)
at
org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:543)
at
org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:524)
at
org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:206)
(Notice, that webapp-name is not the actual name and System cannot
find
file is a translation of the original German message)
Our start-up process looks like this:
this.tomcat = new Tomcat();
this.tomcat.setBaseDir(.);
this.tomcat.getHost().setAutoDeploy(false);
this.tomcat.getHost().setDeployOnStartup(false);
this.tomcat.setPort(port);
final StandardContext webAppCtx = (StandardContext)
this.tomcat.addWebapp(/weppapp-name, webapp-name);
Here parameters should be context and the base path
The directory structure looks like this, while working directory is
Application-Home: /Application-Home/webapps/webapp-name
We noticed that in
Tomcat.getWebappConfigFileFromJar(Tomcat.java:1162),
there is the following code:
protected URL getWebappConfigFile(String path, String url) {
File docBase = new File(path);
if (docBase.isDirectory()) {
return getWebappConfigFileFromDirectory(docBase, url);
} else {
return getWebappConfigFileFromJar(docBase, url);
}
}
The parameter path is webapp-name and the parameter url is
/webapp-name. With the working dir being Application-Home, new
File(path) will resolve to /Application-Home/webapp-name, which does
not exist. Hence, Tomcat is proceeding to load the config file from a
jar
file, which leads to the warning mentioned above.
My questions are:
- What are the correct parameters for Tomcat.addWebapp(String
contextPath,
String docBase)?
first parameter is the context of your web app and the 2nd parameter is
the
base directory/absolute path
Using the absolute path did the trick. The following code does not
produce a warning anymore and the context.xml is attempted to be loaded
from a directory and not a jar file:
final StandardContext webAppCtx = (StandardContext)
this.tomcat.addWebapp(/webapp-name,
Paths.get(this.tomcat.getHost().getAppBase(),
webapp-name).toAbsolutePath().toString());
- Is there a special working directory expected, while using an
embedded
Tomcat?
2015-04-28 15:06 GMT+05:30 Benjamin Rogge tom...@benjamin-rogge.de:
Hello,
we use an embedded Tomcat and are trying to update from version 7.0.40
to
7.0.61. The the embedded tomcat instance starts up fine and our webapp
is
also running. However we get the following warning:
Apr 28, 2015 8:58:58 AM org.apache.catalina.startup.Tomcat
getWebappConfigFileFromJar
WARNING: Unable to determine web application context.xml webapp-name
java.io.FileNotFoundException: webapp-name (System cannot find file)
at java.util.zip.ZipFile.open(Native Method)
at java.util.zip.ZipFile.init(ZipFile.java:215)
at java.util.zip.ZipFile.init(ZipFile.java:145)
at java.util.jar.JarFile.init(JarFile.java:153)
at java.util.jar.JarFile.init(JarFile.java:117)
at
org.apache.catalina.startup.Tomcat.getWebappConfigFileFromJar(Tomcat.java:1162)
at
org.apache.catalina.startup.Tomcat.getWebappConfigFile(Tomcat.java:1140)
at
org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:543)
at
org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:524)
at
org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:206)
(Notice, that webapp-name is not the actual name and System cannot
find
file is a translation of the original German message)
Our start-up process looks like this:
this.tomcat = new Tomcat();
this.tomcat.setBaseDir(.);
this.tomcat.getHost().setAutoDeploy(false);
this.tomcat.getHost().setDeployOnStartup(false);
this.tomcat.setPort(port);
final StandardContext webAppCtx = (StandardContext)
this.tomcat.addWebapp(/weppapp-name, webapp-name);
The directory structure looks like this, while working directory is
Application-Home: /Application-Home/webapps/webapp-name
We noticed that in
Locating WebAppConfig file in embedded tomcat
Hello,
we use an embedded Tomcat and are trying to update from version 7.0.40
to 7.0.61. The the embedded tomcat instance starts up fine and our
webapp is also running. However we get the following warning:
Apr 28, 2015 8:58:58 AM org.apache.catalina.startup.Tomcat
getWebappConfigFileFromJar
WARNING: Unable to determine web application context.xml webapp-name
java.io.FileNotFoundException: webapp-name (System cannot find file)
at java.util.zip.ZipFile.open(Native Method)
at java.util.zip.ZipFile.init(ZipFile.java:215)
at java.util.zip.ZipFile.init(ZipFile.java:145)
at java.util.jar.JarFile.init(JarFile.java:153)
at java.util.jar.JarFile.init(JarFile.java:117)
at
org.apache.catalina.startup.Tomcat.getWebappConfigFileFromJar(Tomcat.java:1162)
at
org.apache.catalina.startup.Tomcat.getWebappConfigFile(Tomcat.java:1140)
at org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:543)
at org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:524)
at org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:206)
(Notice, that webapp-name is not the actual name and System cannot
find file is a translation of the original German message)
Our start-up process looks like this:
this.tomcat = new Tomcat();
this.tomcat.setBaseDir(.);
this.tomcat.getHost().setAutoDeploy(false);
this.tomcat.getHost().setDeployOnStartup(false);
this.tomcat.setPort(port);
final StandardContext webAppCtx = (StandardContext)
this.tomcat.addWebapp(/weppapp-name, webapp-name);
The directory structure looks like this, while working directory is
Application-Home: /Application-Home/webapps/webapp-name
We noticed that in Tomcat.getWebappConfigFileFromJar(Tomcat.java:1162),
there is the following code:
protected URL getWebappConfigFile(String path, String url) {
File docBase = new File(path);
if (docBase.isDirectory()) {
return getWebappConfigFileFromDirectory(docBase, url);
} else {
return getWebappConfigFileFromJar(docBase, url);
}
}
The parameter path is webapp-name and the parameter url is
/webapp-name. With the working dir being Application-Home, new
File(path) will resolve to /Application-Home/webapp-name, which does
not exist. Hence, Tomcat is proceeding to load the config file from a
jar file, which leads to the warning mentioned above.
My questions are:
- What are the correct parameters for Tomcat.addWebapp(String
contextPath, String docBase)?
- Is there a special working directory expected, while using an embedded
Tomcat?
Thanks in advance for any support,
Benjamin Rogge
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Re: Locating WebAppConfig file in embedded tomcat
Hi
we use an embedded Tomcat and are trying to update from version 7.0.40 to
7.0.61. The the embedded tomcat instance starts up fine and our webapp is
also running. However we get the following warning:
Apr 28, 2015 8:58:58 AM org.apache.catalina.startup.Tomcat
getWebappConfigFileFromJar
WARNING: Unable to determine web application context.xml webapp-name
java.io.FileNotFoundException: webapp-name (System cannot find file)
at java.util.zip.ZipFile.open(Native Method)
at java.util.zip.ZipFile.init(ZipFile.java:215)
at java.util.zip.ZipFile.init(ZipFile.java:145)
at java.util.jar.JarFile.init(JarFile.java:153)
at java.util.jar.JarFile.init(JarFile.java:117)
at org.apache.catalina.startup.Tomcat.getWebappConfigFileFromJa
r(Tomcat.java:1162)
at org.apache.catalina.startup.Tomcat.getWebappConfigFile(Tomca
t.java:1140)
at org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:543)
at org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:524)
at org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:206)
(Notice, that webapp-name is not the actual name and System cannot find
file is a translation of the original German message)
Our start-up process looks like this:
this.tomcat = new Tomcat();
this.tomcat.setBaseDir(.);
this.tomcat.getHost().setAutoDeploy(false);
this.tomcat.getHost().setDeployOnStartup(false);
this.tomcat.setPort(port);
final StandardContext webAppCtx = (StandardContext)
this.tomcat.addWebapp(/weppapp-name, webapp-name);
Here parameters should be context and the base path
The directory structure looks like this, while working directory is
Application-Home: /Application-Home/webapps/webapp-name
We noticed that in Tomcat.getWebappConfigFileFromJar(Tomcat.java:1162),
there is the following code:
protected URL getWebappConfigFile(String path, String url) {
File docBase = new File(path);
if (docBase.isDirectory()) {
return getWebappConfigFileFromDirectory(docBase, url);
} else {
return getWebappConfigFileFromJar(docBase, url);
}
}
The parameter path is webapp-name and the parameter url is
/webapp-name. With the working dir being Application-Home, new
File(path) will resolve to /Application-Home/webapp-name, which does
not exist. Hence, Tomcat is proceeding to load the config file from a jar
file, which leads to the warning mentioned above.
My questions are:
- What are the correct parameters for Tomcat.addWebapp(String contextPath,
String docBase)?
first parameter is the context of your web app and the 2nd parameter is the
base directory/absolute path
- Is there a special working directory expected, while using an embedded
Tomcat?
2015-04-28 15:06 GMT+05:30 Benjamin Rogge tom...@benjamin-rogge.de:
Hello,
we use an embedded Tomcat and are trying to update from version 7.0.40 to
7.0.61. The the embedded tomcat instance starts up fine and our webapp is
also running. However we get the following warning:
Apr 28, 2015 8:58:58 AM org.apache.catalina.startup.Tomcat
getWebappConfigFileFromJar
WARNING: Unable to determine web application context.xml webapp-name
java.io.FileNotFoundException: webapp-name (System cannot find file)
at java.util.zip.ZipFile.open(Native Method)
at java.util.zip.ZipFile.init(ZipFile.java:215)
at java.util.zip.ZipFile.init(ZipFile.java:145)
at java.util.jar.JarFile.init(JarFile.java:153)
at java.util.jar.JarFile.init(JarFile.java:117)
at
org.apache.catalina.startup.Tomcat.getWebappConfigFileFromJar(Tomcat.java:1162)
at
org.apache.catalina.startup.Tomcat.getWebappConfigFile(Tomcat.java:1140)
at org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:543)
at org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:524)
at org.apache.catalina.startup.Tomcat.addWebapp(Tomcat.java:206)
(Notice, that webapp-name is not the actual name and System cannot find
file is a translation of the original German message)
Our start-up process looks like this:
this.tomcat = new Tomcat();
this.tomcat.setBaseDir(.);
this.tomcat.getHost().setAutoDeploy(false);
this.tomcat.getHost().setDeployOnStartup(false);
this.tomcat.setPort(port);
final StandardContext webAppCtx = (StandardContext)
this.tomcat.addWebapp(/weppapp-name, webapp-name);
The directory structure looks like this, while working directory is
Application-Home: /Application-Home/webapps/webapp-name
We noticed that in Tomcat.getWebappConfigFileFromJar(Tomcat.java:1162),
there is the following code:
protected URL getWebappConfigFile(String path, String url) {
File docBase = new File(path);
if (docBase.isDirectory()) {
return getWebappConfigFileFromDirectory(docBase, url);
} else {
return getWebappConfigFileFromJar(docBase, url);
}
}
The parameter path is
