The sources are just for our IDE (Eclipse) to link these sources to the
binaries.
Because the wiquery repository is maven2 compatible, I've changed the
resolver configuration in my ivysettings.xml to ibiblio:
I assume only this resolver can downoad all jars (sources, docs) from the
repository if
Not currently but over the last few days we have been implementing new features
for a new release of our web app and one of those is to include the canonical
link element.
I think it's really important for SEO.
-Original Message-
From: Francois Meillet [mailto:qq...@gmail.com]
Now , i am changing browser language from IE. I am able to get
message from properties file for label and another things. But i am still
unable to show above alert message in different languages. Can you solve
this problem. Please reply soon.
Typically, you would do this by
On Tue, Mar 6, 2012 at 8:30 PM, eugenebalt eugeneb...@yahoo.com wrote:
Thanks. But we don't have Request Params, we have a binary Request Stream
with Adobe's FDF.
In HTTP, you can do request.getInputStream() to get it, can you do the same
in Wicket?
This is how POST parameters are being read
Looks like serialization problem.
Does anybody know how it works?
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hi again
Can you help me with this? I'm really stuck with this problem...
thanks
Rebecca
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On Wed, Mar 7, 2012 at 2:41 PM, rebecca rivka.shis...@gmail.com wrote:
hi again
Can you help me with this? I'm really stuck with this problem...
Show us your AjaxCallDecorator.
thanks
Rebecca
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I used exactly the one in Apache Wicket Cookbook:
BlockingDecorator.java:
public class BlockingDecorator implements IAjaxCallDecorator
{
private static final String latch=var
locked=this.hasAttribute('data-wicket-blocked'); +
if (locked) { return false; }+
What exactly do you do in #onClick/onSubmit() ?
I guess you set a new page as response, or at least remove all links
which still point to the current page which is untouched and no more
reachable.
On Wed, Mar 7, 2012 at 3:26 PM, rebecca rivka.shis...@gmail.com wrote:
I used exactly the one in
can't you put your resources to DB ?? then you will have quick access and
it will be secure?
pozdrawiam
Paweł Kamiński
kami...@gmail.com
pkaminski@gmail.com
__
in onSubmit of the AjaxSubmitLink i do:
getSession.untouch(firstPage);
getSession.clear();
setResponsePaeg(new myNextPage());
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OK, then remove the 'reset' part of the AjaxCallDecorator. You don't
need to re-enable the link at all.
If you have more links on the page then you need to put a veil on the
whole page, not just disable a single link.
On Wed, Mar 7, 2012 at 4:33 PM, rebecca rivka.shis...@gmail.com wrote:
in
I already tried removing the reset code - didn't work.
By veil you mean something like the jquery plugin blockUi?
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Could someone help me understand what the error below means ? I have copied
the relevant code below, what is wrong with it. I believe I have followed
guidelines for wicket 1.5
Mar 07, 2012 8:48:43 AM
org.apache.wicket.request.resource.ResourceReferenceRegi
stry addDefaultResourceReference
On Wed, Mar 7, 2012 at 4:53 PM, rebecca rivka.shis...@gmail.com wrote:
I already tried removing the reset code - didn't work.
Put some console.log() to see what happens in JS.
By veil you mean something like the jquery plugin blockUi?
Yes
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thanks Martin - I'll try the veil and report later
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Thank you Martin.
I think it is an issue of absolutePath.
In
private final ResourceReference mouseOverMenuCss = new
CssResourceReference(getClass(),
/css/mouseovermenu.css);
the
The problem is at $2 in web.components.PageHeaderComponent$2
This is an inner anonymous class which name may vary.
Just use a stable class name and make sure the resource is next to the
.class file.
On Wed, Mar 7, 2012 at 5:34 PM, grazia grazia.russolass...@gmail.com wrote:
Thank you Martin.
I
Hello,
I've got a REST service which is behind a Wicket Session Filter (due to the
need to obtain the wicket current session at the service), and this REST
service is being periodically hit by a Flash client (embedded in wicket
page)
At this REST service I've got a method that retrieves the wicket
I am adding a shared resource to my app, and I need to reference a file which
resides under /WebContent.
Our app code structure is this:
The /src folder has all the HTML/Java's for Wicket.
The /WebContent has all the images, CSS, and other resources. I need to
reference one of these resources
Hi,
I have a form with a list of FormComponentPanels for phone numbers.
Currently, adding a new phone number to the list involves an ajax
request to add a new FormComponentPanel instance to the form and then
another request to submit the form.
Is there a way to achieve this without the
see how ContextImage does it
-igor
On Wed, Mar 7, 2012 at 10:45 AM, eugenebalt eugeneb...@yahoo.com wrote:
I am adding a shared resource to my app, and I need to reference a file which
resides under /WebContent.
Our app code structure is this:
The /src folder has all the HTML/Java's for
Anybody any idea?
On Tue, 6 Mar 2012 22:17:10 +0100
Andre Schütz andre-p...@gmx.de wrote:
Hi,
I tested my application and checked for the renderCount variable. I made a
breakpoint and checked the variable in the Debugger. Surprisingly, the
renderCount variable was not increased and
Alle mercoledì 07 marzo 2012, mukesh kumar ha scritto:
Thanks for it. But i am still confused. So, can you write some line of code
for alert message of JS file.
Thanks !
You could use visural
http://wicket.visural.net/examples/dialog
If you learn to use it, you will use also other tools
what is the resource is not next to the .class file, but in a specific
directory external to the app, say in tomcat/webapps/css ? Is there another
wicket API I should use ?
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I mean that if you accept identifiers of external resources as parameters
(e.g. database primary keys), it is your responsibility to verify that the
authenticated user is authorized to access/modify that external resource.
Frameworks protect session data, but not such external resources.
On Wed,
Hi,
The debug statement in your page's constructor wont show anything. At
this time the page is not rendered yet and the value will be the
initial one - 0.
You need to put a breakpoint at org.apache.wicket.Page#renderPage()
and see why it is being incremented second time.
Or just create a ticket
Hi,
One way to accomplish this is to submit to a page, not to a Form, and
handle the request parameters manually.
But this way it wont be Ajax anymore and you'll go to a new page.
Additionally you will lose the form validation.
On Wed, Mar 7, 2012 at 9:52 PM, Bertrand Guay-Paquet
See org.apache.wicket.markup.html.IHeaderResponse#renderCSSReference(String)
On Thu, Mar 8, 2012 at 12:09 AM, grazia grazia.russolass...@gmail.com wrote:
what is the resource is not next to the .class file, but in a specific
directory external to the app, say in tomcat/webapps/css ? Is there
Hi,
Put the Button in a Toolbar. See DefaultDataTable's code, it shows how
to add toolbars.
I guess the easiest way for you is to re-create the complete DataTable
with the new columns after pressing the button.
Otherwise also check DataView and GridView components. They are more
flexible than
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