Thanks for the help Igor! I was sure I had already tried to add the
friends = new HashSetUser(); line to my constructor and that it didn't
work. Apparently I screwed up somehow, because it is working after all.
Regards,
Linda
Linda van der Pal wrote:
I've created a quickstart and attached it
I've found where the problem is residing, but I'm still not quite sure
what the problem is. So I've used the quickstart to make a small project
that reproduces the bug. Can anyone tell me what the procedure is to
make this into an actual quickstart that I can pass around? I can make
some
generate an archetype with maven, cmd line is here
wicket.apache.org/quickstart
after you are done
mvn clean
zip the dir
attach to a jira
-igor
On Tue, Jun 9, 2009 at 1:40 AM, Linda van der
Pallvd...@heritageagenturen.nl wrote:
I've found where the problem is residing, but I'm still not quite
Well it's unlikely to be a bug in Wicket (not that I was expecting one).
When I tried to make a quickstart, the quickstart didn't show the error.
It worked as I expected in the first place. So now I'm off to hunt for
the bug in my original code.
Thanks for all the help!
Linda.
Igor Vaynberg
What does the converter of that component that is bound to the set
create? It seems to me that that doesnt create a set object but only a
user?? And then not a set of users is the argument but the user itself
so bang you get that exception you have..
On 04/06/2009, Igor Vaynberg
That is very strange, as this is the code in the domain model:
public SetUser getFriends() {
return friends;
}
public void setFriends(final SetUser friends) {
this.friends = friends;
}
So I don't see why it would recognize the getter, but not the setter.
Linda
Igor Vaynberg wrote:
need to see more of the stacktrace
-igor
This is the entire stacktrace that is shown:
WicketMessage: Error calling method: public void
nl.lunaris.bookdb.model.database.User.setFriends(java.util.Set) on
object: User: Test
Root cause:
I tried setting the model of a ListMultipleChoice to a HashSet (by using
a CompoundPropertyModel and the id of the HashSet). The list of possible
choices was an ArrayList. It shows my selected choices nicely. But I'm
getting an error when I want to save the data. So I'm guessing the LMC
need to see more of the stacktrace
-igor
On Wed, Jun 3, 2009 at 6:45 AM, Linda van der Pal
lvd...@heritageagenturen.nl wrote:
I tried setting the model of a ListMultipleChoice to a HashSet (by using a
CompoundPropertyModel and the id of the HashSet). The list of possible
choices
