Re: Show source problem using AbstractAjaxTimerBehavior

[Muro Copenhagen]

Well that explains it.

Ok, thanks for the tip Igor and Jeremy...

Best Regards

On Mon, Nov 16, 2009 at 10:57 PM, Jeremy Thomerson <
jer...@wickettraining.com> wrote:

> Or use the web developer tools in FF and use "view generated source".
>
> --
> Jeremy Thomerson
> http://www.wickettraining.com
>
>
>
> On Mon, Nov 16, 2009 at 9:42 AM, Igor Vaynberg  >wrote:
>
> > source only shows the initial load, not the changes made via ajax
> > executed javascript. use firebug to view the actual dom structure.
> >
> > -igor
> >
> > On Mon, Nov 16, 2009 at 6:16 AM, Muro Copenhagen 
> > wrote:
> > > Hi,
> > >
> > > I am using the wicket AbstractAjaxTimerBehavior, that checks if a job i
> > have
> > > executed has finished.
> > >
> > > When it has finished, i have a link i want to display.
> > >
> > > I have also added an attribut modifier to the link, that will add a
> > > javascript onclick to the link.
> > >
> > > My problem is that the changes made inside the
> AbstractAjaxTimerBehavior
> > is
> > > not shown when i use show source.
> > >
> > > But it actually displays the changes on the web page.
> > >
> > > How come it displays the changes, but i can't see the changes when i
> use
> > > show source ?
> > > Can i force wicket/the browser to auto render/display the changes when
> > the
> > > timer has finished.
> > >
> > > My concern is that the javascript i have added to the link will not be
> > > triggered, since it is not shown on the source.
> > >
> > > Here is a snapshot of my code:
> > >
> > >// senere link tracking
> > >link.add(new AttributeModifier("onclick", true, new
> > > Model("webTracking.trackEvent('test');")));
> > >final AsyncronEventExecuter e = new AsyncronEventExecuter(...);
> > >
> > >add(new AbstractAjaxTimerBehavior(Duration.milliseconds(1000)) {
> > >   protected void onTimer(final AjaxRequestTarget target) {
> > >if (e.isFinished()) {
> > >   stop();
> > >  target.addComponent(link.setVisible(true));
> > > }
> > >   }
> > >
> > >
> > > Thanks in advance
> > >
> > > Best Regards
> > > Muro
> > >
> >
> > -
> > To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
> > For additional commands, e-mail: users-h...@wicket.apache.org
> >
> >
>

Re: Show source problem using AbstractAjaxTimerBehavior

[Jeremy Thomerson]

Or use the web developer tools in FF and use "view generated source".

--
Jeremy Thomerson
http://www.wickettraining.com



On Mon, Nov 16, 2009 at 9:42 AM, Igor Vaynberg wrote:

> source only shows the initial load, not the changes made via ajax
> executed javascript. use firebug to view the actual dom structure.
>
> -igor
>
> On Mon, Nov 16, 2009 at 6:16 AM, Muro Copenhagen 
> wrote:
> > Hi,
> >
> > I am using the wicket AbstractAjaxTimerBehavior, that checks if a job i
> have
> > executed has finished.
> >
> > When it has finished, i have a link i want to display.
> >
> > I have also added an attribut modifier to the link, that will add a
> > javascript onclick to the link.
> >
> > My problem is that the changes made inside the AbstractAjaxTimerBehavior
> is
> > not shown when i use show source.
> >
> > But it actually displays the changes on the web page.
> >
> > How come it displays the changes, but i can't see the changes when i use
> > show source ?
> > Can i force wicket/the browser to auto render/display the changes when
> the
> > timer has finished.
> >
> > My concern is that the javascript i have added to the link will not be
> > triggered, since it is not shown on the source.
> >
> > Here is a snapshot of my code:
> >
> >// senere link tracking
> >link.add(new AttributeModifier("onclick", true, new
> > Model("webTracking.trackEvent('test');")));
> >final AsyncronEventExecuter e = new AsyncronEventExecuter(...);
> >
> >add(new AbstractAjaxTimerBehavior(Duration.milliseconds(1000)) {
> >   protected void onTimer(final AjaxRequestTarget target) {
> >if (e.isFinished()) {
> >   stop();
> >  target.addComponent(link.setVisible(true));
> > }
> >   }
> >
> >
> > Thanks in advance
> >
> > Best Regards
> > Muro
> >
>
> -
> To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
> For additional commands, e-mail: users-h...@wicket.apache.org
>
>

Re: Show source problem using AbstractAjaxTimerBehavior

[Igor Vaynberg]

source only shows the initial load, not the changes made via ajax
executed javascript. use firebug to view the actual dom structure.

-igor

On Mon, Nov 16, 2009 at 6:16 AM, Muro Copenhagen  wrote:
> Hi,
>
> I am using the wicket AbstractAjaxTimerBehavior, that checks if a job i have
> executed has finished.
>
> When it has finished, i have a link i want to display.
>
> I have also added an attribut modifier to the link, that will add a
> javascript onclick to the link.
>
> My problem is that the changes made inside the AbstractAjaxTimerBehavior is
> not shown when i use show source.
>
> But it actually displays the changes on the web page.
>
> How come it displays the changes, but i can't see the changes when i use
> show source ?
> Can i force wicket/the browser to auto render/display the changes when the
> timer has finished.
>
> My concern is that the javascript i have added to the link will not be
> triggered, since it is not shown on the source.
>
> Here is a snapshot of my code:
>
>            // senere link tracking
>        link.add(new AttributeModifier("onclick", true, new
> Model("webTracking.trackEvent('test');")));
>        final AsyncronEventExecuter e = new AsyncronEventExecuter(...);
>
>        add(new AbstractAjaxTimerBehavior(Duration.milliseconds(1000)) {
>           protected void onTimer(final AjaxRequestTarget target) {
>                if (e.isFinished()) {
>                   stop();
>                      target.addComponent(link.setVisible(true));
>                 }
>           }
>
>
> Thanks in advance
>
> Best Regards
> Muro
>

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Show source problem using AbstractAjaxTimerBehavior

[Muro Copenhagen]

Hi,

I am using the wicket AbstractAjaxTimerBehavior, that checks if a job i have
executed has finished.

When it has finished, i have a link i want to display.

I have also added an attribut modifier to the link, that will add a
javascript onclick to the link.

My problem is that the changes made inside the AbstractAjaxTimerBehavior is
not shown when i use show source.

But it actually displays the changes on the web page.

How come it displays the changes, but i can't see the changes when i use
show source ?
Can i force wicket/the browser to auto render/display the changes when the
timer has finished.

My concern is that the javascript i have added to the link will not be
triggered, since it is not shown on the source.

Here is a snapshot of my code:

// senere link tracking
link.add(new AttributeModifier("onclick", true, new
Model("webTracking.trackEvent('test');")));
final AsyncronEventExecuter e = new AsyncronEventExecuter(...);

add(new AbstractAjaxTimerBehavior(Duration.milliseconds(1000)) {
   protected void onTimer(final AjaxRequestTarget target) {
if (e.isFinished()) {
   stop();
  target.addComponent(link.setVisible(true));
 }
   }


Thanks in advance

Best Regards
Muro