Re: [xwiki-users] Implement Jsontool.serialize in groovy
Hi Thomas, I instantiate the jsonbuilder as follows in the example yet returned
to previous error that was not allow adding elements in my "json" method. "Add
()".
I have also realized by placing the method within an array as criuado test
("data.projetos [i]. Id.add ()").
{{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name and
obj.className = 'E-nova.E-novaClass'";def listProjetos =
services.query.hql(hql0).execute();def i = 0;def data = new
groovy.json.JsonBuilder();data = ["totalprojetos":
listProjetos.size(),"projetos": [ id: "", tag: "", label: "", size: "", color:
"", x: "", y : "" ],"edges":[ id: "", source: "", target: "" ]];
for(item in listProjetos){ def hql = "select distinct list from BaseObject as
obj, DBStringListProperty as prop join prop.list list where
obj.className='XWiki.TagClass' and obj.id=prop.id.id and prop.id.name='tags'
and obj.name ='$item' ";def tag = services.query.hql(hql).execute(); i = i + 1;
data.projetos.id.add()=1; data.projetos.tag.add()="tags";
data.projetos.label.add()="Label do projeto"; data.projetos.size.add()=5;
data.projetos.color.add()="#696969"; data.projetos.x.add()=1;
data.projetos.y.add()= 1;}
def json = new groovy.json.JsonBuilder(data)println
json.toPrettyString(){{/groovy}}
Atenciosamente,
Eduardo Abritta
e-mail: eduardo.abri...@outlook.com | cel: (32)8472-9631
> From: eduardo.abri...@outlook.com
> To: users@xwiki.org
> Date: Mon, 30 Jun 2014 15:23:37 -0300
> Subject: Re: [xwiki-users] Implement Jsontool.serialize in groovy
>
> I'm trying to implement a function that told me but I can not add the data
> online, I can only add one. How do I do that?
{{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name and
obj.className = 'E-nova.E-novaClass'";def listProjetos =
services.query.hql(hql0).execute();def i = 0;def data = new
groovy.json.JsonBuilder();data = ["totalprojetos":
listProjetos.size(),"projetos": [ id: "", tag: "",
label: "", size: "", color: "",
x: "", y : ""],"edges":[id: "",
source: "",target: ""]];
for(item in listProjetos){ def hql = "select distinct list from BaseObject as
obj, DBStringListProperty as prop join prop.list list where
obj.className='XWiki.TagClass' and obj.id=prop.id.id and prop.id.name='tags'
and obj.name ='$item' ";def tag = services.query.hql(hql).execute(); i = i + 1;
data.projetos.id=1; data.projetos.tag="tags"; data.projetos.label="Label do
projeto"; data.projetos.size=5; data.projetos.color="#696969";
data.projetos.x=1; data.projetos.y= 1;}
def json = new groovy.json.JsonBuilder(data)println
json.toPrettyString(){{/groovy}}
> Atenciosamente,
> Eduardo Abritta
> e-mail: eduardo.abri...@outlook.com | cel: (32)8472-9631
>
>
>
> > Date: Fri, 27 Jun 2014 11:51:47 +0200
> > From: thomas.morta...@xwiki.com
> > To: users@xwiki.org
> > Subject: Re: [xwiki-users] Implement Jsontool.serialize in groovy
> >
> > You should probably use JsonBuilder which is the standard tool to
> > manipulate JSON in Groovy.
> >
> > On Fri, Jun 27, 2014 at 10:33 AM, Clemens Klein-Robbenhaar
> > wrote:
> > >
> > > The velocity tools are not automatically created for groovy scripts
> > > The closest you can get is to create them manually in your script, like:
> > >
> > > def jsontool = new org.xwiki.velocity.tools.JSONTool()
> > >
> > > I feel there should be a better way to do that, but it works this way.
> > > (it is likely that using groovy.json.JsonBuilder() works, too, but I have
> > > not tried)
> > >
> > > Clemens
> > >
> > > On 06/24/2014 09:21 PM, Eduardo Abritta wrote:
> > >> Hello Sirs,
> > >> I need to implement the function "jsontool.serialize" in the code below,
> > >> groovy, and I do not understand the error that is accusing, can help me
> > >> solve this?
> > >> {{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name
> > >> and obj.className = 'E-nova.E-novaClass'";def listProjetos =
> > >> services.query.hql(hql0).execute();def json = ['totalprojetos':
> > >> listProjetos.size(),
Re: [xwiki-users] Implement Jsontool.serialize in groovy
I'm trying to implement a function that told me but I can not add the data
online, I can only add one. How do I do that?
{{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name and
obj.className = 'E-nova.E-novaClass'";def listProjetos =
services.query.hql(hql0).execute();def i = 0;def data = new
groovy.json.JsonBuilder();data = ["totalprojetos":
listProjetos.size(),"projetos": [ id: "", tag: "",
label: "", size: "", color: "",
x: "", y : ""],"edges":[id: "",
source: "",target: ""]];
for(item in listProjetos){ def hql = "select distinct list from BaseObject as
obj, DBStringListProperty as prop join prop.list list where
obj.className='XWiki.TagClass' and obj.id=prop.id.id and prop.id.name='tags'
and obj.name ='$item' ";def tag = services.query.hql(hql).execute();i =
i + 1;data.projetos.id=1;data.projetos.tag="tags";
data.projetos.label="Label do projeto";data.projetos.size=5;
data.projetos.color="#696969";data.projetos.x=1;data.projetos.y= 1;}
def json = new groovy.json.JsonBuilder(data)println
json.toPrettyString(){{/groovy}}
Atenciosamente,
Eduardo Abritta
e-mail: eduardo.abri...@outlook.com | cel: (32)8472-9631
> Date: Fri, 27 Jun 2014 11:51:47 +0200
> From: thomas.morta...@xwiki.com
> To: users@xwiki.org
> Subject: Re: [xwiki-users] Implement Jsontool.serialize in groovy
>
> You should probably use JsonBuilder which is the standard tool to
> manipulate JSON in Groovy.
>
> On Fri, Jun 27, 2014 at 10:33 AM, Clemens Klein-Robbenhaar
> wrote:
> >
> > The velocity tools are not automatically created for groovy scripts
> > The closest you can get is to create them manually in your script, like:
> >
> > def jsontool = new org.xwiki.velocity.tools.JSONTool()
> >
> > I feel there should be a better way to do that, but it works this way.
> > (it is likely that using groovy.json.JsonBuilder() works, too, but I have
> > not tried)
> >
> > Clemens
> >
> > On 06/24/2014 09:21 PM, Eduardo Abritta wrote:
> >> Hello Sirs,
> >> I need to implement the function "jsontool.serialize" in the code below,
> >> groovy, and I do not understand the error that is accusing, can help me
> >> solve this?
> >> {{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name
> >> and obj.className = 'E-nova.E-novaClass'";def listProjetos =
> >> services.query.hql(hql0).execute();def json = ['totalprojetos':
> >> listProjetos.size(), 'projetos':[1000] , 'edges':[1000] ];def i = 0;
> >> for(item in listProjetos){def hql = "select distinct list from
> >> BaseObject as obj, DBStringListProperty as prop join prop.list list where
> >> obj.className='XWiki.TagClass' and obj.id=prop.id.id and
> >> prop.id.name='tags' and obj.name ='$item' ";def tag =
> >> services.query.hql(hql).execute();i = i + 1;
> >> json.projetos.add({id: xwiki.getDocument(item).getName()})}
> >> jsontool.serialize(json);
> >> {{/groovy}}
> >> Ty.
> >> Atenciosamente,
> >> Eduardo Abritta
> >> e-mail: eduardo.abri...@outlook.com | cel: (32)8472-9631
> >>
> >>
> >> ___
> >> users mailing list
> >> users@xwiki.org
> >> http://lists.xwiki.org/mailman/listinfo/users
> >>
> >
> >
> > ___
> > users mailing list
> > users@xwiki.org
> > http://lists.xwiki.org/mailman/listinfo/users
>
>
>
> --
> Thomas Mortagne
> ___
> users mailing list
> users@xwiki.org
> http://lists.xwiki.org/mailman/listinfo/users
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Re: [xwiki-users] Implement Jsontool.serialize in groovy
You should probably use JsonBuilder which is the standard tool to
manipulate JSON in Groovy.
On Fri, Jun 27, 2014 at 10:33 AM, Clemens Klein-Robbenhaar
wrote:
>
> The velocity tools are not automatically created for groovy scripts
> The closest you can get is to create them manually in your script, like:
>
> def jsontool = new org.xwiki.velocity.tools.JSONTool()
>
> I feel there should be a better way to do that, but it works this way.
> (it is likely that using groovy.json.JsonBuilder() works, too, but I have not
> tried)
>
> Clemens
>
> On 06/24/2014 09:21 PM, Eduardo Abritta wrote:
>> Hello Sirs,
>> I need to implement the function "jsontool.serialize" in the code below,
>> groovy, and I do not understand the error that is accusing, can help me
>> solve this?
>> {{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name and
>> obj.className = 'E-nova.E-novaClass'";def listProjetos =
>> services.query.hql(hql0).execute();def json = ['totalprojetos':
>> listProjetos.size(), 'projetos':[1000] , 'edges':[1000] ];def i = 0;
>> for(item in listProjetos){def hql = "select distinct list from
>> BaseObject as obj, DBStringListProperty as prop join prop.list list where
>> obj.className='XWiki.TagClass' and obj.id=prop.id.id and prop.id.name='tags'
>> and obj.name ='$item' ";def tag = services.query.hql(hql).execute();
>> i = i + 1;
>> json.projetos.add({id: xwiki.getDocument(item).getName()})}
>> jsontool.serialize(json);
>> {{/groovy}}
>> Ty.
>> Atenciosamente,
>> Eduardo Abritta
>> e-mail: eduardo.abri...@outlook.com | cel: (32)8472-9631
>>
>>
>> ___
>> users mailing list
>> users@xwiki.org
>> http://lists.xwiki.org/mailman/listinfo/users
>>
>
>
> ___
> users mailing list
> users@xwiki.org
> http://lists.xwiki.org/mailman/listinfo/users
--
Thomas Mortagne
___
users mailing list
users@xwiki.org
http://lists.xwiki.org/mailman/listinfo/users
Re: [xwiki-users] Implement Jsontool.serialize in groovy
The velocity tools are not automatically created for groovy scripts
The closest you can get is to create them manually in your script, like:
def jsontool = new org.xwiki.velocity.tools.JSONTool()
I feel there should be a better way to do that, but it works this way.
(it is likely that using groovy.json.JsonBuilder() works, too, but I have not
tried)
Clemens
On 06/24/2014 09:21 PM, Eduardo Abritta wrote:
> Hello Sirs,
> I need to implement the function "jsontool.serialize" in the code below,
> groovy, and I do not understand the error that is accusing, can help me solve
> this?
> {{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name and
> obj.className = 'E-nova.E-novaClass'";def listProjetos =
> services.query.hql(hql0).execute();def json = ['totalprojetos':
> listProjetos.size(), 'projetos':[1000] , 'edges':[1000] ];def i = 0;
> for(item in listProjetos){def hql = "select distinct list from BaseObject
> as obj, DBStringListProperty as prop join prop.list list where
> obj.className='XWiki.TagClass' and obj.id=prop.id.id and prop.id.name='tags'
> and obj.name ='$item' ";def tag = services.query.hql(hql).execute();i
> = i + 1;
> json.projetos.add({id: xwiki.getDocument(item).getName()})}
> jsontool.serialize(json);
> {{/groovy}}
> Ty.
> Atenciosamente,
> Eduardo Abritta
> e-mail: eduardo.abri...@outlook.com | cel: (32)8472-9631
>
>
> ___
> users mailing list
> users@xwiki.org
> http://lists.xwiki.org/mailman/listinfo/users
>
___
users mailing list
users@xwiki.org
http://lists.xwiki.org/mailman/listinfo/users
[xwiki-users] Implement Jsontool.serialize in groovy
Hello Sirs,
I need to implement the function "jsontool.serialize" in the code below,
groovy, and I do not understand the error that is accusing, can help me solve
this?
{{groovy}}def hql0 = ", BaseObject as obj where doc.fullName = obj.name and
obj.className = 'E-nova.E-novaClass'";def listProjetos =
services.query.hql(hql0).execute();def json = ['totalprojetos':
listProjetos.size(), 'projetos':[1000] , 'edges':[1000] ];def i = 0;
for(item in listProjetos){ def hql = "select distinct list from BaseObject
as obj, DBStringListProperty as prop join prop.list list where
obj.className='XWiki.TagClass' and obj.id=prop.id.id and prop.id.name='tags'
and obj.name ='$item' ";def tag = services.query.hql(hql).execute();i =
i + 1;
json.projetos.add({id: xwiki.getDocument(item).getName()})}
jsontool.serialize(json);
{{/groovy}}
Ty.
Atenciosamente,
Eduardo Abritta
e-mail: eduardo.abri...@outlook.com | cel: (32)8472-9631
___
users mailing list
users@xwiki.org
http://lists.xwiki.org/mailman/listinfo/users
