Hi Serge,
Thanks for the suggestion. I did find another method that also works via a
for-loop:
e.g.
x=[1 2 3 4 5];y=[0 1.1 1.5 1.6 2.4 4.1 4.7 5 5.7];for k=1:length(x)
[val,idx]=min(abs(y-x(k)));
xx(k)=y(idx);end
Lester
On Thu, 2 Jun 2022 at 11:37, Steer Serge wrote:
> If A and B are not
Hi all,
Is it possible to use one vector to find only those closest values in
another vector with a tolerance limit?
A=[2 3 4 5 6]; // source array
B=[0.25 1.2 2.01 5.2 7.4 9.3 10.6 ]; // target array to find closest values
to A
So in the example above, the closest values would be 2.01 and 5.2
