Hi Serge, Thanks for the suggestion. I did find another method that also works via a for-loop: e.g.
x=[1 2 3 4 5];y=[0 1.1 1.5 1.6 2.4 4.1 4.7 5 5.7];for k=1:length(x) [val,idx]=min(abs(y-x(k))); xx(k)=y(idx);end Lester On Thu, 2 Jun 2022 at 11:37, Steer Serge <serge.st...@laposte.net> wrote: > If A and B are not too big you can proceed as follow: > E=abs(ones(B')*A-B'*ones(A)) > > [i,j]=ind2sub(find(E<=0.3),size(E)); > Serge > > Le 02/06/2022 à 10:17, Lester Anderson a écrit : > > Hi all, > > Is it possible to use one vector to find only those closest values in > another vector with a tolerance limit? > > A=[2 3 4 5 6]; // source array > B=[0.25 1.2 2.01 5.2 7.4 9.3 10.6 ]; // target array to find closest > values to A > > So in the example above, the closest values would be 2.01 and 5.2 in B, > all other values excluded. Arrays are not going to be the same size! > Hopefully I have explained it well enough. > > Thanks > Lester > > > _______________________________________________ > users mailing > listusers@lists.scilab.orghttp://lists.scilab.org/mailman/listinfo/users > > >
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