Hallo Claus,
would you like to explain, why you thought of images as input?
I worked a little in the field of finding lines/edges in noisy images and a
cumsum approach crossed my way some years ago.
So maybe here, there is something to learn for me?
Best Regards,
Philipp
Am Mo., 7. Feb. 202
Le 07/02/2022 à 20:28, Claus Futtrup a écrit :
Hi Samuel, and all Scilabers
Entertaining response from Samuel!
It's about knowing that the cumsum function exist. :-)
I googled Scilab cumsum and found old docs that it was part of
elementary matrix operations
(https://help.scilab.org/doc/6.0.0
Hi Samuel, and all Scilabers
Entertaining response from Samuel!
It's about knowing that the cumsum function exist. :-)
I googled Scilab cumsum and found old docs that it was part of
elementary matrix operations
(https://help.scilab.org/doc/6.0.0/en_US/cumsum.html), but in Scilab
6.1.1 this i
Heinz,
It isn't clear what you need, I don't underastand the relationship
between EE and E.
Except for the first 0 in E, it seems that each consecutive number n is
repeated n+1 times up to the number indicated by the first component of
EE. Is this what you are looking for?
This is a simpl
Hi Heinz
I notice that the E-vector is longer than the largest numberin the
EE-vector. What decides the length of the E-vector?
I was thinking length(EE) = 3 gives the highest number in the E-vector,
and that e.g. max(EE) = 8 would be the length of the E-vector (but it's
not ...), such that
Hello Heinz,
Le 07/02/2022 à 18:35, Heinz Nabielek a écrit :
Sorry, colleagues - please help, I have just a mental blockade.
Given vector EE= [3 5 8]
I want to create a stepwise increasing vector E= [0 0 1 1 2 2 2 3 3 3 3]
And would need a system that works for much larger numbers
Pro
