How di I display a new page on session timeout without requiring the user to do anything?
Hi, I have a requirement that says that, for security purposes, when a session times out, the application must go to a different page so that any data displayed is hidden and that the user must be informed that the session has timed out. In the init method of my Application class, which subclasses AuthenticatedApplication, I have the following line. getApplicationSettings().setPageExpiredErrorPage(SessionTimeoutPage.class); So now, after the session expires, if the user clicks on anything it goes to the SessionTimeoutPage. This is not the behavior I need, so I've done some searching and found some suggestions on using AjaxTimerBehavior to warn a user that a session is about to expire, but nothing that says exactly how to detect an expired session. Also, some people have hinted that Ajax could actually keep the session alive so I'm a little confused about that. Can someone please clarify this and at least point me in the right direction for fulfilling my requirements? Thanks, Bruce
Re: How di I display a new page on session timeout without requiring the user to do anything?
Hi, On Wed, Mar 12, 2014 at 5:09 PM, Bruce Lombardi brlom...@gmail.com wrote: Hi, I have a requirement that says that, for security purposes, when a session times out, the application must go to a different page so that any data displayed is hidden and that the user must be informed that the session has timed out. In the init method of my Application class, which subclasses AuthenticatedApplication, I have the following line. getApplicationSettings().setPageExpiredErrorPage(SessionTimeoutPage.class); So now, after the session expires, if the user clicks on anything it goes to the SessionTimeoutPage. This is not the behavior I need, so I've done some searching and found some suggestions on using AjaxTimerBehavior to warn a user that a session is about to expire, but nothing that says exactly how to detect an expired session. Also, some people have hinted that Ajax could actually keep the session alive so I'm a little confused about that. This is correct. Any request to the server will touch the session and thus will keep it alive. Can someone please clarify this and at least point me in the right direction for fulfilling my requirements? Your best bet is to use JavaScript counter that will count down do document.location.href=anotherUrl; when the counter reaches 0. You will have to reinit the counter with every ajax request - this is easy. Thanks, Bruce
RE: How di I display a new page on session timeout without requiring the user to do anything?
Thanks Martin, for the rapid response. Has anyone done anything like this this? Bruce -Original Message- From: Martin Grigorov [mailto:mgrigo...@apache.org] Sent: Wednesday, March 12, 2014 11:26 AM To: users@wicket.apache.org Subject: Re: How di I display a new page on session timeout without requiring the user to do anything? Hi, On Wed, Mar 12, 2014 at 5:09 PM, Bruce Lombardi brlom...@gmail.com wrote: Hi, I have a requirement that says that, for security purposes, when a session times out, the application must go to a different page so that any data displayed is hidden and that the user must be informed that the session has timed out. In the init method of my Application class, which subclasses AuthenticatedApplication, I have the following line. getApplicationSettings().setPageExpiredErrorPage(SessionTimeoutPage.cl ass); So now, after the session expires, if the user clicks on anything it goes to the SessionTimeoutPage. This is not the behavior I need, so I've done some searching and found some suggestions on using AjaxTimerBehavior to warn a user that a session is about to expire, but nothing that says exactly how to detect an expired session. Also, some people have hinted that Ajax could actually keep the session alive so I'm a little confused about that. This is correct. Any request to the server will touch the session and thus will keep it alive. Can someone please clarify this and at least point me in the right direction for fulfilling my requirements? Your best bet is to use JavaScript counter that will count down do document.location.href=anotherUrl; when the counter reaches 0. You will have to reinit the counter with every ajax request - this is easy. Thanks, Bruce - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
