Re: Cannot get current page from AjaxPagingNavigator

2010-11-10 Thread vp143

I got it working with the following code- thanks Pedro and JC

final Label currentPage = new Label(currentPage, new Model());
currentPage.setOutputMarkupId(true);
add(currentPage);

final AjaxPagingNavigator pagination = new
AjaxPagingNavigator(navigator, dataList) {
@Override
protected void onAjaxEvent(AjaxRequestTarget target) {
target.addComponent(currentPage);
super.onAjaxEvent(target);
}
};
add(pagination);

LoadableDetachableModel model = new LoadableDetachableModel() {
public Object load(){
return pagination.getPageable().getCurrentPage() + 1;
}
};
currentPage.setDefaultModel(model);

It had to be written like this because the model needs pagination which
would not have been initialised if written as an inner class when creating
the label.
Please let me know if anyone finds a better way of writing it.

Many thanks again
Vishal
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Re: Cannot get current page from AjaxPagingNavigator

2010-11-10 Thread jcgarciam

I would change:
  final Label currentPage = new Label(currentPage, new Model());

to this:
Label currentPage = new Label(currentPage, new LoadableDetachableModel(){
 public Object load(){
  return pagination.getPageable().getCurrentPage() + 1;

}

});

and then just remove the last part:
  currentPage.setDefaultModel(model);

On Wed, Nov 10, 2010 at 5:19 AM, vp143 [via Apache Wicket] 
ml-node+3035648-2145298352-65...@n4.nabble.comml-node%2b3035648-2145298352-65...@n4.nabble.com
 wrote:

 I got it working with the following code- thanks Pedro and JC

 final Label currentPage = new Label(currentPage, new Model());
 currentPage.setOutputMarkupId(true);
 add(currentPage);

 final AjaxPagingNavigator pagination = new
 AjaxPagingNavigator(navigator, dataList) {
 @Override
 protected void onAjaxEvent(AjaxRequestTarget target) {
 target.addComponent(currentPage);
 super.onAjaxEvent(target);
 }
 };
 add(pagination);

 LoadableDetachableModel model = new LoadableDetachableModel() {
 public Object load(){
 return pagination.getPageable().getCurrentPage() + 1;
 }
 };
 currentPage.setDefaultModel(model);

 It had to be written like this because the model needs pagination which
 would not have been initialised if written as an inner class when creating
 the label.
 Please let me know if anyone finds a better way of writing it.

 Many thanks again
 Vishal

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Work smarter, not harder!.

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Re: Cannot get current page from AjaxPagingNavigator

2010-11-10 Thread jcgarciam

Ohh sorry, now that i read your code carefully i see you have a case of the
Chicken and the Egg!! :)

On Wed, Nov 10, 2010 at 11:30 AM, Juan Carlos Garcia jcgarc...@gmail.comwrote:

 I would change:
   final Label currentPage = new Label(currentPage, new Model());

 to this:
 Label currentPage = new Label(currentPage, new LoadableDetachableModel(){
  public Object load(){
   return pagination.getPageable().getCurrentPage() + 1;


 }

 });

 and then just remove the last part:
   currentPage.setDefaultModel(model);

 On Wed, Nov 10, 2010 at 5:19 AM, vp143 [via Apache Wicket] 
 ml-node+3035648-2145298352-65...@n4.nabble.comml-node%2b3035648-2145298352-65...@n4.nabble.com
  wrote:

 I got it working with the following code- thanks Pedro and JC

 final Label currentPage = new Label(currentPage, new Model());
 currentPage.setOutputMarkupId(true);
 add(currentPage);

 final AjaxPagingNavigator pagination = new
 AjaxPagingNavigator(navigator, dataList) {
 @Override
 protected void onAjaxEvent(AjaxRequestTarget target) {
 target.addComponent(currentPage);
 super.onAjaxEvent(target);
 }
 };
 add(pagination);

 LoadableDetachableModel model = new LoadableDetachableModel() {
 public Object load(){
 return pagination.getPageable().getCurrentPage() + 1;
 }
 };
 currentPage.setDefaultModel(model);

 It had to be written like this because the model needs pagination which
 would not have been initialised if written as an inner class when creating
 the label.
 Please let me know if anyone finds a better way of writing it.

 Many thanks again
 Vishal

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 --
 Sincerely,
 JC (http://www.linkedin.com/in/jcgarciam)
 Work smarter, not harder!.




-- 
Sincerely,
JC (http://www.linkedin.com/in/jcgarciam)
Work smarter, not harder!.

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Re: Cannot get current page from AjaxPagingNavigator

2010-11-09 Thread jcgarciam

You are using an static model, which only knows about the value by the time
of construction. Use a dynamic model

i.e: (make sure you define pagination as final)

 Label currentPage = new Label(currentPage, new LoadableDetachableModel(){
 public Object load(){

 return pagination.getPageable().getCurrentPage();
}

});


On Tue, Nov 9, 2010 at 1:04 PM, vp143 [via Apache Wicket] 
ml-node+3034524-366758351-65...@n4.nabble.comml-node%2b3034524-366758351-65...@n4.nabble.com
 wrote:

 Hi all,

 For some reason I cannot get the current page number. This is the relevant
 part of my code:



 PageableListView dataList = new PageableListView(dataList, results, 10) {


 protected void populateItem(ListItem item) {

 ..

 }

 }



 AjaxPagingNavigator pagination = new
 AjaxPagingNavigator(navigator, dataList);

 add(pagination);



 Label currentPage = new Label(currentPage,
 pagination.getPageable().getCurrentPage() + );

 currentPage.setOutputMarkupId(true);

 add(currentPage);



 currentPage always returns 0.

 I have also tried PagingNavigator with similar results.



 Can anyone tell me what I have missed?



 Regards



 Vishal



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JC (http://www.linkedin.com/in/jcgarciam)
Work smarter, not harder!.

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Re: Cannot get current page from AjaxPagingNavigator

2010-11-09 Thread Pedro Santos
Use an dinamic model, ex:

Label currentPage = new Label(currentPage, new
AbstractReadOnlyModelString() {
public String getObject() {
return pagination.getPageable().getCurrentPage();
}
});

On Tue, Nov 9, 2010 at 2:04 PM, Vishal Popat vishal.po...@cipriati.co.ukwrote:

 Hi all,

 For some reason I cannot get the current page number. This is the relevant
 part of my code:



 PageableListView dataList = new PageableListView(dataList, results, 10) {

protected void populateItem(ListItem item) {

..

 }

}



AjaxPagingNavigator pagination = new
 AjaxPagingNavigator(navigator, dataList);

add(pagination);



Label currentPage = new Label(currentPage,
 pagination.getPageable().getCurrentPage() + );

currentPage.setOutputMarkupId(true);

add(currentPage);



 currentPage always returns 0.

 I have also tried PagingNavigator with similar results.



 Can anyone tell me what I have missed?



 Regards



 Vishal




-- 
Pedro Henrique Oliveira dos Santos


Re: Cannot get current page from AjaxPagingNavigator

2010-11-09 Thread vp143

Thank you both for your responses- I totally forgot about it being dynamic.

However, I have tried both code snippets above but still no luck.
I printed the current page within the load() method which prints 0 only on
first load. No message is printed when the page numbers from
AjaxPagingNavigator are clicked on.

Any thoughts?
Vishal
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Re: Cannot get current page from AjaxPagingNavigator

2010-11-09 Thread Pedro Santos
I think you need to implement the AjaxPagingNavigator#onAjaxEvent method and
add the currentPage component on target.

On Tue, Nov 9, 2010 at 4:20 PM, vp143 vishal.po...@cipriati.co.uk wrote:


 Thank you both for your responses- I totally forgot about it being dynamic.

 However, I have tried both code snippets above but still no luck.
 I printed the current page within the load() method which prints 0 only on
 first load. No message is printed when the page numbers from
 AjaxPagingNavigator are clicked on.

 Any thoughts?
 Vishal
 --
 View this message in context:
 http://apache-wicket.1842946.n4.nabble.com/Cannot-get-current-page-from-AjaxPagingNavigator-tp3034524p3034840.html
 Sent from the Users forum mailing list archive at Nabble.com.

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-- 
Pedro Henrique Oliveira dos Santos