)println
json.toPrettyString(){{/groovy}}
Atenciosamente,
Eduardo Abritta
e-mail: eduardo.abri...@outlook.com | cel: (32)8472-9631
From: eduardo.abri...@outlook.com
To: users@xwiki.org
Date: Mon, 30 Jun 2014 15:23:37 -0300
Subject: Re: [xwiki-users] Implement Jsontool.serialize in groovy
I'm
json.toPrettyString(){{/groovy}}
Atenciosamente,
Eduardo Abritta
e-mail: eduardo.abri...@outlook.com | cel: (32)8472-9631
Date: Fri, 27 Jun 2014 11:51:47 +0200
From: thomas.morta...@xwiki.com
To: users@xwiki.org
Subject: Re: [xwiki-users] Implement Jsontool.serialize in groovy
You should probably use
The velocity tools are not automatically created for groovy scripts
The closest you can get is to create them manually in your script, like:
def jsontool = new org.xwiki.velocity.tools.JSONTool()
I feel there should be a better way to do that, but it works this way.
(it is likely that using
You should probably use JsonBuilder which is the standard tool to
manipulate JSON in Groovy.
On Fri, Jun 27, 2014 at 10:33 AM, Clemens Klein-Robbenhaar
c.robbenh...@espresto.com wrote:
The velocity tools are not automatically created for groovy scripts
The closest you can get is to create them
Hello Sirs,
I need to implement the function jsontool.serialize in the code below,
groovy, and I do not understand the error that is accusing, can help me solve
this?
{{groovy}}def hql0 = , BaseObject as obj where doc.fullName = obj.name and
obj.className = 'E-nova.E-novaClass';def listProjetos
