David Roberson dlrober...@aol.com wrote:
Finally, the leakage power entering the water from the pump has to be
determined since it has a significant effect upon the total calculation.
Even though it is on continuously, it is impossible to achieve an accurate
calculation without its influence
See:
http://www.wired.co.uk/news/archive/2015-01/30/cold-fusion-energy-advances-2015
New type of chemical bonddiscovered
http://www.sciencealert.com/new-type-of-chemical-bond-discovered
Move over, covalent and ionic bonds, there’s a new chemical bond in town,
and it loves to shake things up.
It’s taken decades to nail down, but researchers in Canada have finally
identified a
David Roberson dlrober...@aol.com wrote:
Do you have information about where the ambient temperature was during
this long time period?
For the entire 28 hours it is:
Average 16.67°C, min 15.93°C, max 17.30°C
The difference between the ambient and water settles to a much larger value
than
another link
Isotope effect produces new type of chemical bond
http://www.rsc.org/chemistryworld/2014/10/isotope-effect-produces-new-type-chemical-bond
quote In the early 1980s it was proposed that in certain transition
states consisting of a very light atom sandwiched between two heavy
Jed,
Do you have information about where the ambient temperature was during this
long time period? I and my simulation would expect the temperature to remain
constant after enough time has elapsed when the only heating source is the pump
and the ambient remains constant. If we know the
Bob Cook frobertc...@hotmail.com wrote:
All measurements should be accomplished with as much precision
as possible, since adiabatic calorimetry is not possible without adiabatic
conditions.
You mean it is not perfectly insulated. No system is. When the level of
heat is very small, such as
Dear Readers,
I regret that I cannot offer you just now the up-to-dated Parkhomov paper
but it is under way. However please read this:
http://egooutpeters.blogspot.ro/2015/01/lenr-race-first-remove-obstacles.html
and let's think together - but for Science'sake NOT do groupthink!
Peter
--
Dr.
I wrote:
If I were trying to do calorimetry based on the difference between the
cooling water and the air, the answer would be inaccurate to the point of
being useless. Fortunately, I need only compare the cooling water at the
start of the test to the end of the test.
We did, in fact, try
I would say that the thermal energy from the pump which is added to the
circulating water in the Mizuno experiment should be driven by the differential
temperature between the body of the pump and the circulating water. In
addition the differential temperature between the pump body and the
And . . . Here is definitive proof of what I say.
It happens that Mizuno sent me a large data set which includes about 35
hours where nothing was happening. He left the computer running, and he
left the heating on so the ambient temperature was reasonably stable. I see
it was especially stable
I agree that the pump power is not going to screw up the calculations as long
as it is constant. It looks like just any other constant signal that will be
subtracted off by your technique.
The same protection is given to the errors in ambient measurements such as an
offset. Once you hold
David Roberson dlrober...@aol.com wrote:
I do not get anywhere near to the 3 to 1 excess power out over input power
that is reported. I am seeing a 1.25 ratio instead of 3.0 or so.
Oh, I think you did see the 3 to 1 excess, and the 6:1 as well. Keep
looking! Look at Table 1.
You got
Sorry about the late response to this important posting. I was diverted by
many interruptions and lost track of where I was before they arose. You have
made so many interesting points that I may fail to address them all properly,
and if that happens please send them back for another run. :-)
My model is able to take modest ambient variations into account and subtract
their effect from the measured coolant temperature. This is not too difficult
since the external time constant is so large. It also is able to handle pump
leakage power very well. It turns out that the ambient can
Using that delta we would have 2 watts of excess heat leaking into the system.
My method of determining the .67 was not using a static measurement. I did
trust your number of 41000 joules per degree C. as being accurate. Once that
value is pegged, the time domain response follows an RC time
Hi,
I have updated http://rvanspaa.freehostia.com/LiHy4-.pdf to take account of
actual size of Li ions, at each stage, after removing electrons.
Regards,
Robin van Spaandonk
http://rvanspaa.freehostia.com/project.html
This is an ongoing project I suppose. I will check the Oct 20 data again, but
I believe I got roughly the same amount of excess. That seems too good to be
true.
What do you mean by considering that the reactor vessel is capturing 60% of the
heat? Are you referring to the idea that the water
David Roberson dlrober...@aol.com wrote:
Using that delta we would have 2 watts of excess heat leaking into the
system.
From the pump? That is plausible. ~1.5 W from the mechanical work of the
impeller, and ~0.5 W from motor heat conduction.
However, I hope you now agree that this will not
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