I was struck by how close the Fermi velocity is to your MHz-m, and wondered
if
there might be a connection?
My velocity is 1/2 the velocity of the ground state of hydrogen.
The darn thing about my velocity is that I can compute the energy levels of
the
hydrogen atom, the energy of the
I believe that the coherence length is equal to the downshifted Compton
wavelength.
Do you have a formula for this, and how does it differ from the definition of
the De Broglie wavelength?
BTW, did you notice the Fermi velocity?
Regards,
Robin van Spaandonk
The Fermi velocities are
In reply to [EMAIL PROTECTED]'s message of Wed, 27 Feb 2008 11:39:41 EST:
Hi Frank,
[snip]
BTW, did you notice the Fermi velocity?
[snip]
The Fermi velocities are quite high.
I was struck by how close the Fermi velocity is to your MHz-m, and wondered if
there might be a connection?
[snip]
I
Bose Condensate? , AFAIK, they form just above absolute zero. Why were you
expecting one to form?
Good comment. A Bose condensate of electrons only forms at low
temperatures. I was attempting to form a Bose condensate of protons (also
known as an
inverse condensate). The thermal
In reply to [EMAIL PROTECTED]'s message of Sat, 23 Feb 2008 11:34:12 EST:
Hi Frank,
[snip]
Bose Condensate? , AFAIK, they form just above absolute zero. Why were you
expecting one to form?
Good comment. A Bose condensate of electrons only forms at low
temperatures. I was attempting to
Assuming your coherence length is at least proportional to the De Broglie
wavelength (L_DB) and
L_DB = h/p and
p = sqrt(2*m*E) where E = kinetic energy, we get
L_DB = h/(sqrt(2*m*E)) .
Since, as you state above, the energy is the same irrespective of type of
particle, we see that L_DB is
In reply to [EMAIL PROTECTED]'s message of Sat, 23 Feb 2008 18:16:41 EST:
Hi Frank,
[snip]
Assuming your coherence length is at least proportional to the De Broglie
wavelength (L_DB) and
L_DB = h/p and
p = sqrt(2*m*E) where E = kinetic energy, we get
L_DB = h/(sqrt(2*m*E)) .
Since, as you
Robin van Spaandonk wrote:
In reply to [EMAIL PROTECTED]'s message of Fri, 22 Feb 2008 11:34:05 EST:
Hi Frank,
[snip]
The intent of the experiment was to form a Bose condensate of deuterons by
increasing the strength of the phonons that bind the condensate. I believe
that my 1.094
I am home on a short break between contracts. I have conducted another
experiment. I placed a 26 gauge palladium wire in a heavy water electrolysis
cell (the wire was from surperpure chemicals Inc.) The anode was a nickel
wire (which dissolved and was replaced ).
I applied 9 volts
[EMAIL PROTECTED] wrote:
The intent of the experiment was to form a Bose condensate of
deuterons by increasing the strength of the phonons that bind the
condensate. I believe that my 1.094 megahertz-meter relationship
describes the frequency of the binding phonons.
Bose Condensate? ,
In reply to [EMAIL PROTECTED]'s message of Fri, 22 Feb 2008 11:34:05 EST:
Hi Frank,
[snip]
The intent of the experiment was to form a Bose condensate of deuterons by
increasing the strength of the phonons that bind the condensate. I believe
that my 1.094 megahertz-meter relationship
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