On Tue, 19 Feb 2008, Jed Rothwell wrote:
Mark Goldes wrote:
I wrote to Bill asking if he had banned me, as I do not believe he
accepts the possibility of our magnetic devices or superconductors
being genuine.
He never answered.
Message never received. Eskimo.com appears to be having more
Howdy Jones,
Back in the '80's, Roger was CEO of GM and drove the last vestige of sanity
at GM into the ground like a tent stake. While we were sleeping an entire
piece of what we knew of as America was destroyed... by economic
terrorists, our real enemies.
When the Dime Box saloon starts
Vo-
Four part video and interviews with the late James
Patterson; includes assorted figures like George Miley
were put up on YouTube yesterday.
Well done. This is a must-see for the LENR crowd even
if you already caught some of the 12 year-old original
footage-
Pt 1 is here:
Bose Condensate? , AFAIK, they form just above absolute zero. Why were you
expecting one to form?
Good comment. A Bose condensate of electrons only forms at low
temperatures. I was attempting to form a Bose condensate of protons (also
known as an
inverse condensate). The thermal
In reply to [EMAIL PROTECTED]'s message of Sat, 23 Feb 2008 11:34:12 EST:
Hi Frank,
[snip]
Bose Condensate? , AFAIK, they form just above absolute zero. Why were you
expecting one to form?
Good comment. A Bose condensate of electrons only forms at low
temperatures. I was attempting to
On Sat, 23 Feb 2008, Jones Beene wrote:
Well done. This is a must-see for the LENR crowd even
if you already caught some of the 12 year-old original
footage-
Pt 1 is here: http://www.youtube.com/watch?v=eUQfYw_HEJs
Always take time to link such online discoveries to stumbleupon.com.
My own
Assuming your coherence length is at least proportional to the De Broglie
wavelength (L_DB) and
L_DB = h/p and
p = sqrt(2*m*E) where E = kinetic energy, we get
L_DB = h/(sqrt(2*m*E)) .
Since, as you state above, the energy is the same irrespective of type of
particle, we see that L_DB is
Jones,
My understanding is that as clever as the Patterson cell was, there was
something in the beads that was important to the success. When the supply of
beads was used up, the effect vanished. This has happened before, in other
industries. At one time Motorola offer to buy him out but his
- Original Message -
From: Robin van Spaandonk [EMAIL PROTECTED]
To: vortex-l@eskimo.com
Sent: Friday, February 22, 2008 5:37 PM
Subject: Re: [Vo]:Parksie gets it wrong yet again
In reply to Stephen A. Lawrence's message of Fri, 22 Feb 2008
16:48:17 -0500:
Hi,
[snip]
I haven't
In reply to [EMAIL PROTECTED]'s message of Sat, 23 Feb 2008 18:16:41 EST:
Hi Frank,
[snip]
Assuming your coherence length is at least proportional to the De Broglie
wavelength (L_DB) and
L_DB = h/p and
p = sqrt(2*m*E) where E = kinetic energy, we get
L_DB = h/(sqrt(2*m*E)) .
Since, as you
Robin van Spaandonk wrote:
In reply to [EMAIL PROTECTED]'s message of Fri, 22 Feb 2008 11:34:05 EST:
Hi Frank,
[snip]
The intent of the experiment was to form a Bose condensate of deuterons by
increasing the strength of the phonons that bind the condensate. I believe
that my 1.094
_Pat Bailey sent me this
www.thephoenixlights.net http://www.harkinstheatres.com/
_
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