Re: [Vo]:graphs of reaction and decay networks
Thank you. Excellent catch. Eric On Wed, Sep 19, 2012 at 10:44 PM, Axil Axil janap...@gmail.com wrote: Where are the tritium and the neutrons? This reaction has two branches that occur with nearly equal probability: D + D→ T+ 1H D + D→ 3He+ n Then 2 1D + 3 1T → 4 2He + 1 0n http://en.wikipedia.org/wiki/Neutron Cheers:Axil On Thu, Sep 20, 2012 at 12:50 AM, David Roberson dlrober...@aol.comwrote: Hi Eric, I made a quick calculation and believe that your balance adds up. The net process is equal to the production of a He4 atom from two deuterons. Each deuteron releases 2.224 MeV to build from parts while a He4 atom releases 28.2933 MeV if constructed from basic parts. So if you start with the two deuterons and end with He4 you get 28.2933 - 2 * 2.224 = 23.8453 MeV. The total released by your two reactions is 23.8 MeV. The numbers appear to correlate. Dave -Original Message- From: Eric Walker eric.wal...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Wed, Sep 19, 2012 11:54 pm Subject: [Vo]:graphs of reaction and decay networks I've put together some graphs of exothermic proton and deuteron capture reaction networks for several materials together with associated decay chains. See: https://docs.google.com/open?id=0BzKtdce19-wySThpSnd3bUxJdDQ A PDF can be obtained by choosing Download from the File menu at the left. If you see any details in error, let me know. There is a fascinating pair of reactions that I haven't completely made sense of yet: 15N + D - 13C + A + 7.7 MeV 13C + D - 15N + γ + 16.1 MeV At face value, it is a catalytic reaction that takes deuterium and yields helium-4. But I'm not able to make sense of the energy balance. it appears to be saying that if you take 15N and add deuterium, you'll get 13C and some energy, and if you take 13C and add deuterium, you'll get 15N and some energy. I've probably messed up the calculation; if not, there's some magic going on there. Eric
Re: [Vo]:graphs of reaction and decay networks
I wrote: Thank you. Excellent catch. My mistake. See page 4. I'm finding it a little hard to translate in my head from 2H and 3H to D and T, but they're at the bottom of the graph. The dark green lines mean X + D. Eric
[Vo]:graphs of reaction and decay networks
I've put together some graphs of exothermic proton and deuteron capture reaction networks for several materials together with associated decay chains. See: https://docs.google.com/open?id=0BzKtdce19-wySThpSnd3bUxJdDQ A PDF can be obtained by choosing Download from the File menu at the left. If you see any details in error, let me know. There is a fascinating pair of reactions that I haven't completely made sense of yet: 15N + D - 13C + A + 7.7 MeV 13C + D - 15N + γ + 16.1 MeV At face value, it is a catalytic reaction that takes deuterium and yields helium-4. But I'm not able to make sense of the energy balance. it appears to be saying that if you take 15N and add deuterium, you'll get 13C and some energy, and if you take 13C and add deuterium, you'll get 15N and some energy. I've probably messed up the calculation; if not, there's some magic going on there. Eric
Re: [Vo]:graphs of reaction and decay networks
Hi Eric, I made a quick calculation and believe that your balance adds up. The net process is equal to the production of a He4 atom from two deuterons. Each deuteron releases 2.224 MeV to build from parts while a He4 atom releases 28.2933 MeV if constructed from basic parts. So if you start with the two deuterons and end with He4 you get 28.2933 - 2 * 2.224 = 23.8453 MeV. The total released by your two reactions is 23.8 MeV. The numbers appear to correlate. Dave -Original Message- From: Eric Walker eric.wal...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Wed, Sep 19, 2012 11:54 pm Subject: [Vo]:graphs of reaction and decay networks I've put together some graphs of exothermic proton and deuteron capture reaction networks for several materials together with associated decay chains. See: https://docs.google.com/open?id=0BzKtdce19-wySThpSnd3bUxJdDQ A PDF can be obtained by choosing Download from the File menu at the left. If you see any details in error, let me know. There is a fascinating pair of reactions that I haven't completely made sense of yet: 15N + D - 13C + A + 7.7 MeV 13C + D - 15N + γ + 16.1 MeV At face value, it is a catalytic reaction that takes deuterium and yields helium-4. But I'm not able to make sense of the energy balance. it appears to be saying that if you take 15N and add deuterium, you'll get 13C and some energy, and if you take 13C and add deuterium, you'll get 15N and some energy. I've probably messed up the calculation; if not, there's some magic going on there. Eric
Re: [Vo]:graphs of reaction and decay networks
Where are the tritium and the neutrons? This reaction has two branches that occur with nearly equal probability:D + D→ T+ 1HD + D→ 3He+ n Then 2 1D + 3 1T → 4 2He + 1 0n http://en.wikipedia.org/wiki/Neutron Cheers:Axil On Thu, Sep 20, 2012 at 12:50 AM, David Roberson dlrober...@aol.com wrote: Hi Eric, I made a quick calculation and believe that your balance adds up. The net process is equal to the production of a He4 atom from two deuterons. Each deuteron releases 2.224 MeV to build from parts while a He4 atom releases 28.2933 MeV if constructed from basic parts. So if you start with the two deuterons and end with He4 you get 28.2933 - 2 * 2.224 = 23.8453 MeV. The total released by your two reactions is 23.8 MeV. The numbers appear to correlate. Dave -Original Message- From: Eric Walker eric.wal...@gmail.com To: vortex-l vortex-l@eskimo.com Sent: Wed, Sep 19, 2012 11:54 pm Subject: [Vo]:graphs of reaction and decay networks I've put together some graphs of exothermic proton and deuteron capture reaction networks for several materials together with associated decay chains. See: https://docs.google.com/open?id=0BzKtdce19-wySThpSnd3bUxJdDQ A PDF can be obtained by choosing Download from the File menu at the left. If you see any details in error, let me know. There is a fascinating pair of reactions that I haven't completely made sense of yet: 15N + D - 13C + A + 7.7 MeV 13C + D - 15N + γ + 16.1 MeV At face value, it is a catalytic reaction that takes deuterium and yields helium-4. But I'm not able to make sense of the energy balance. it appears to be saying that if you take 15N and add deuterium, you'll get 13C and some energy, and if you take 13C and add deuterium, you'll get 15N and some energy. I've probably messed up the calculation; if not, there's some magic going on there. Eric
