Still stuck with that.
While this is rendered as expected on w3school try me:
(assuming org_code = 3):
var a ={{=URL('default', 'org_form_load.load/ + org_code + ')}};
alert(a):
{{=URL('default', 'org_form_load.load/3')}}
on web2py it renders:
It appears you are trying to mix Python and Javascript. Note, everything
inside the {{...}} must be Python and gets executed on the server. Adding
the org_code variable must be done in Javascript, so it would be:
var url = '{{=URL('default', 'org_form_load.load')}}';
$.web2py.component(url +
Now I got it... theoython {{ is rendered befor the js
Thanks.
On Wednesday, January 1, 2014 2:22:24 AM UTC+2, Anthony wrote:
It appears you are trying to mix Python and Javascript. Note, everything
inside the {{...}} must be Python and gets executed on the server. Adding
the org_code
The form is not accepted when it is first created, so you will always get
that error message. Instead, you want:
elif form.errors:
response.flash = 'There was an error..'
Anthony
On Monday, December 30, 2013 10:21:58 AM UTC-5, Avi A wrote:
Hi,
I have this on the view:
div
Thanks,
It solved the error getting after the form is loaded into the page,
but still nothing happen if I submit the form.
This is what I do:
if form.process().accepted:
response.flash = 'Success!'
elif form.errors:
response.flash = 'response errors'
On Monday, December
The form won't get submitted to the org_form_load action, but instead will
get submitted to the action of the parent page. You have to trap the form
submission and submit back to the org_form_load action. Rather than using
the ajax() function to load a form, you're better off loading the form
Thanks. I will look into it.
Happy new year! and thanks for all the awesome support!
On Monday, December 30, 2013 7:47:48 PM UTC+2, Anthony wrote:
The form won't get submitted to the org_form_load action, but instead will
get submitted to the action of the parent page. You have to trap the
How is the name (input value) is passed in this component template/case?
(i click the code and the form won't load into the page.).
On Monday, December 30, 2013 7:49:32 PM UTC+2, Avi A wrote:
Thanks. I will look into it.
Happy new year! and thanks for all the awesome support!
On Monday,
Oops, sorry. You'll need to do something more sophisticated. Create an
onkeyup handler that retrieves the value in the input and appends it to the
URL of the form action (i.e., /default/org_form_load.load/some_name). Then
call $.web2py.component() with that URL, and in the org_form_load action,
ok thanks.
On Monday, December 30, 2013 8:24:04 PM UTC+2, Anthony wrote:
Oops, sorry. You'll need to do something more sophisticated. Create an
onkeyup handler that retrieves the value in the input and appends it to the
URL of the form action (i.e., /default/org_form_load.load/some_name).
It works only till the alert...
script
function insert_component(org_code)
{
alert(org_code);
$.web2py.component('%s', 'org_form_target'); % URL('default',
'org_form_load.load/org_code');
}
/script
On Monday, December 30, 2013 8:27:00 PM UTC+2, Avi A wrote:
ok thanks.
On Monday, December
$.web2py.component('%s', 'org_form_target'); % URL('default',
'org_form_load.load/org_code');
is actually Python code that generates Javascript, so you cannot use it as
you are using it. Instead, I would create the url variable separately:
function insert_component(org_code)
{
alert(org_code);
I was in the direction in one of the tries...
Thanks.
On Monday, December 30, 2013 11:17:44 PM UTC+2, Anthony wrote:
$.web2py.component('%s', 'org_form_target'); % URL('default',
'org_form_load.load/org_code');
is actually Python code that generates Javascript, so you cannot use it as
you
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