I've been studying the scheduler, but I think it fails in one of the
things I need:
The web page must be updated as the process is being done
i.e. if the scheduler is doiing some background task, I need to update
the web page with the progress of the task, but I don't find how to do
it with the
you must save somewhere in your long_time_consuming_function() the
progress and let the page show that.
If you manage that function outside web2py (using the scheduler or not),
you need something readable by your page and writeable by the external
process. A record on the db, a file,
Niphlod Thanks very much , your learn by trial application has been
gold for me. Catched!!
2013/2/2 Niphlod niph...@gmail.com:
you must save somewhere in your long_time_consuming_function() the
progress and let the page show that.
If you manage that function outside web2py (using the
You can also use Redis Queue
http://rochacbruno.com.br/web2py-and-redis-queue/
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All that you ask can be done using the scheduler except that your app does
not start the process, but submits a request to the scheduler. The
scheduler runs the app when a worker is available. This is to prevent
spikes in resource utilization when multiple processes start. The task can
Thanks for your advice Massimo, but
does the scheduler start inmediately when no worker has been used before?
2013/2/1 Massimo Di Pierro massimo.dipie...@gmail.com:
All that you ask can be done using the scheduler except that your app does
not start the process, but submits a request to the
yes. If the worker is not busy it starts the task immediately. You can also
have more than one worker.
On Friday, 1 February 2013 11:10:11 UTC-6, José Luis Redrejo Rodríguez
wrote:
Thanks for your advice Massimo, but
does the scheduler start inmediately when no worker has been used before?
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