Re: [Wien] Position of Atoms in AFM calculation.

2015-05-06 Thread Abed Reg
Dear Murugan

I'm also working on the antiferromagnetic calculation and for the materials
that have high symmetry like cubic systems, we do not need to use supercell
function to do that like the examples of Cr and NiO.

The antiferromagnetic structure of your material is linked below:

Good luck
-- 
Mr: A.Reggad
Laboratoire de Génie Physique
Université Ibn Khaldoun - Tiaret
Algerie


DyPdBi-afm.struct
Description: Binary data
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Re: [Wien] Position of Atoms in AFM calculation.

2015-05-06 Thread Fecher, Gerhard
It seems that this is simply a structure in space group  P1 (1)
but why not using a structure with higher symmetry for an afm calculation ?
As I told already before, the symmetry will depend on for what type of AFM 
order you like to calculate.

Some time ago, Pablo gave already a struct file in a different symmetry (not 
the original ICSD structure), I assume it was AFM I (tetragonal Space group P 
-4m2 (115))

For an initial fcc lattice, as the Heusler compounds adopt, I guess that a AFM 
II set-up in space group R 3m (160) trigonal, might also be realistic.

The number of symmetry operations (6) in the trigonal case is not much less 
compared to the tetragonal variant (8),

Because of the Nd you may wish to use LDA+U as well as spin-orbit interaction, 
and the latter may also change the symmetry depending on the choice of the 
quantisation axis.

Ciao
Gerhard

DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
I think the problem, to be quite honest with you,
is that you have never actually known what the question is.


Dr. Gerhard H. Fecher
Institut of Inorganic and Analytical Chemistry
Johannes Gutenberg - University
55099 Mainz
and
Max Planck Institute for Chemical Physics of Solids
01187 Dresden

Von: wien-boun...@zeus.theochem.tuwien.ac.at 
[wien-boun...@zeus.theochem.tuwien.ac.at] im Auftrag von Abed Reg 
[jazai...@gmail.com]
Gesendet: Mittwoch, 6. Mai 2015 15:47
An: wien@zeus.theochem.tuwien.ac.at
Betreff: Re: [Wien] Position of Atoms in AFM calculation.

Dear Murugan

I'm also working on the antiferromagnetic calculation and for the materials 
that have high symmetry like cubic systems, we do not need to use supercell 
function to do that like the examples of Cr and NiO.

The antiferromagnetic structure of your material is linked below:

Good luck
--
Mr: A.Reggad
Laboratoire de Génie Physique
Université Ibn Khaldoun - Tiaret
Algerie


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Re: [Wien] Position of Atoms in AFM calculation.

2015-05-03 Thread 白英良



 

-- Origin message --
From:Víctor_Lua~na Cabal vic...@fluor.quimica.uniovi.es
To:A Mailing list for WIEN2k users wien@zeus.theochem.tuwien.ac.at
Subject:Re: [Wien] Position of Atoms in AFM calculation.
Date:2015-05-01 22:16:44On Fri, May 01, 2015 at 06:08:28PM +0530, Murugan 
Sundareswari wrote:
 Thanks a lot.its is not frustating, but it is confusing, each one of you
 have given different answer.it will take time for me to do calculation.i
 will definetly come back with some more doubts please help me like this
 thanks all

Pablo,

1) Lev Kantorovich (or Kantorovitch) from King's College London
has a long tradition working on contact microscopies from
a theoretical point of view.

2) His webpage is

https://www.kcl.ac.uk/nms/depts/physics/people/academicstaff/kantorovich.aspx

3) Some of the codes useful for your purpose can be found on
http://www.mth.kcl.ac.uk/~lev/codes/index.html

Good international labor day,___
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Re: [Wien] Position of Atoms in AFM calculation.

2015-05-01 Thread Víctor Luaña Cabal
On Fri, May 01, 2015 at 06:08:28PM +0530, Murugan Sundareswari wrote:
 Thanks a lot.its is not frustating, but it is confusing, each one of you
 have given different answer.it will take time for me to do calculation.i
 will definetly come back with some more doubts please help me like this
 thanks all

Pablo,

1) Lev Kantorovich (or Kantorovitch) from King's College London
   has a long tradition working on contact microscopies from
   a theoretical point of view.

2) His webpage is

https://www.kcl.ac.uk/nms/depts/physics/people/academicstaff/kantorovich.aspx

3) Some of the codes useful for your purpose can be found on
   http://www.mth.kcl.ac.uk/~lev/codes/index.html

Good international labor day,
 Dr. Víctor Luaña
--
 .  .Research is to see what everybody else has seen, and to
/ `' \   think what nobody else has thought-- Albert Szent-Gyorgi
   /(o)(o)\  
  /`. \/ .'\  Lo mediocre es peor que lo bueno, pero también es peor
 /   '`'`   \ que lo malo, porque la mediocridad no es un grado, es una
 |  \'`'`/  | actitud -- Jorge Wasenberg, 2015
 |  |'`'`|  | (Mediocre is worse than good, but it is also worse than
  \/`'`'`'\/  bad, because mediocrity is not a grade, it is an attitude)
===(((==)))==+=
! Dr.Víctor Luaña, in silico chemist  prof. ! 
! Departamento de Química Física y Analítica ! 
! Universidad de Oviedo, 33006-Oviedo, Spain ! 
! e-mail:   vic...@fluor.quimica.uniovi.es   ! 
! phone: +34-985-103491  fax: +34-985-103125 ! 
++
 GroupPage : http://azufre.quimica.uniovi.es/
 (being reworked)
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Re: [Wien] Position of Atoms in AFM calculation.

2015-05-01 Thread Fecher, Gerhard
DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
I think the problem, to be quite honest with you,
is that you have never actually known what the question is.

Ciao Gerhard
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Re: [Wien] Position of Atoms in AFM calculation.

2015-05-01 Thread delamora

Here I am sending the structure from the ICSD (Find it)
*.struct-orig
with F symmetry
After using supercell and you get a P symmetry, then you differentiate two Dy 
as Dy1 and two as Dy2;
*.struct-P
with sgroup it will change to tetragonal;
*.struct
this structure crystallographically speaking is B, but since the two Dy have 
different spin orientations then magnetically speaking it is P.
If I am not wrong then you can go from Dy1 to Dy2 by shifting by 1/2,1/2,1/2 as 
with Cr. 
The only difference is that in in Cr you have a cubic cell.

The other possibility is to expand in the 1,1,1 direction, but there you have 
the problem that 1,1,1 planes are 3 instead of two and this process is more 
complicated.

By the way, if Víctor Luaña Cabal sends you a letter from polonium do not 
open it, it may be radiactive!!! Sorry, it is a joke.

De: wien-boun...@zeus.theochem.tuwien.ac.at 
wien-boun...@zeus.theochem.tuwien.ac.at en nombre de Víctor Luaña Cabal 
vic...@fluor.quimica.uniovi.es
Enviado: viernes, 1 de mayo de 2015 09:16 a. m.
Para: A Mailing list for WIEN2k users
Cc: Victor Luaña
Asunto: Re: [Wien] Position of Atoms in AFM calculation.

On Fri, May 01, 2015 at 06:08:28PM +0530, Murugan Sundareswari wrote:
 Thanks a lot.its is not frustating, but it is confusing, each one of you
 have given different answer.it will take time for me to do calculation.i
 will definetly come back with some more doubts please help me like this
 thanks all

Pablo,

1) Lev Kantorovich (or Kantorovitch) from King's College London
   has a long tradition working on contact microscopies from
   a theoretical point of view.

2) His webpage is

https://www.kcl.ac.uk/nms/depts/physics/people/academicstaff/kantorovich.aspx

3) Some of the codes useful for your purpose can be found on
   http://www.mth.kcl.ac.uk/~lev/codes/index.html

Good international labor day,
 Dr. Víctor Luaña
--
 .  .Research is to see what everybody else has seen, and to
/ `' \   think what nobody else has thought-- Albert Szent-Gyorgi
   /(o)(o)\
  /`. \/ .'\  Lo mediocre es peor que lo bueno, pero también es peor
 /   '`'`   \ que lo malo, porque la mediocridad no es un grado, es una
 |  \'`'`/  | actitud -- Jorge Wasenberg, 2015
 |  |'`'`|  | (Mediocre is worse than good, but it is also worse than
  \/`'`'`'\/  bad, because mediocrity is not a grade, it is an attitude)
===(((==)))==+=
! Dr.Víctor Luaña, in silico chemist  prof. !
! Departamento de Química Física y Analítica !
! Universidad de Oviedo, 33006-Oviedo, Spain !
! e-mail:   vic...@fluor.quimica.uniovi.es   !
! phone: +34-985-103491  fax: +34-985-103125 !
++
 GroupPage : http://azufre.quimica.uniovi.es/
 (being reworked)
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DyPdBi.struct-orig
Description: DyPdBi.struct-orig


DyPdBi.struct-P
Description: DyPdBi.struct-P


DyPdBi.struct
Description: DyPdBi.struct
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Re: [Wien] Position of Atoms in AFM calculation.

2015-05-01 Thread Fecher, Gerhard
Dear Pablo you are wrong
Below you find that Murugan uses for the AFM set up

Dy 1 (000) and Dy2 (0.5,0.5,0.5 )
Pd(0.25,0.25,0.25) Bi (0.75,0.75,0.75) .

put it in space group 216 and use XCrysden to see the result, it is NOT DyPdSb
try what happens if you don't name Dy 1 and 2 but leave it open in the 
structure generator
I think the symmetry will be changed to F m-3m (225) instead of  F -43m (216).

For an so called half-Heusler structure you will find different types of AFM 
order that are described in different space groups (or say better that result 
in diferent symmetries)
fort example if Nd is the atom where the magnetic moments couple 
antiferromagnetically than you may have
AFM-I   == P -4m2 (113)
AFM-II  ==  R 3m (160)
AFM-III == I -42d (122)

Now, before asking what is the correct structure, one needs to think about what 
one likes to do.





Ciao
Gerhard

DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
I think the problem, to be quite honest with you,
is that you have never actually known what the question is.


Dr. Gerhard H. Fecher
Institut of Inorganic and Analytical Chemistry
Johannes Gutenberg - University
55099 Mainz
and
Max Planck Institute for Chemical Physics of Solids
01187 Dresden

Von: wien-boun...@zeus.theochem.tuwien.ac.at 
[wien-boun...@zeus.theochem.tuwien.ac.at] im Auftrag von delamora 
[delam...@unam.mx]
Gesendet: Donnerstag, 30. April 2015 17:31
An: A Mailing list for WIEN2k users
Cc: gtavizon
Betreff: Re: [Wien] Position of Atoms in AFM calculation.

Gerhard,
No, Murugan is right, it is DyPdBi
Although I found in the structure base find it
a=b=c=6.643
Dy: 0,0,0
Pd: 3/4,3/4,3/4
Bi: 1/2,1/2,1/2 and Murugan has 1/4,1/4,1/4
In terms of frustration this difference does not make a difference, since Bi is 
magnetically neutral.
Saludos

Pablo

De: wien-boun...@zeus.theochem.tuwien.ac.at 
wien-boun...@zeus.theochem.tuwien.ac.at en nombre de Fecher, Gerhard 
fec...@uni-mainz.de
Enviado: jueves, 30 de abril de 2015 10:05 a. m.
Para: A Mailing list for WIEN2k users
Asunto: Re: [Wien] Position of Atoms in AFM calculation.

No. its wrong
now you have Dy2PdBi instead of DyPdBi

you need to make a suitable supercell, or use a P instead of a F cell and 
distinguish the Dy atoms in a suitable way such that you can set spins of 
opposite direction
you also will need LDA+U, otherwise the Nd 4f states will appear at the Fermi 
energy

A description of different types of AFM order in Heusler compounds are given in 
the Landolt Börnstein (I don't remember the issue)

Ciao
Gerhard

DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
I think the problem, to be quite honest with you,
is that you have never actually known what the question is.


Dr. Gerhard H. Fecher
Institut of Inorganic and Analytical Chemistry
Johannes Gutenberg - University
55099 Mainz
and
Max Planck Institute for Chemical Physics of Solids
01187 Dresden

Von: wien-boun...@zeus.theochem.tuwien.ac.at 
[wien-boun...@zeus.theochem.tuwien.ac.at] im Auftrag von Murugan Sundareswari 
[sundare65w...@gmail.com]
Gesendet: Donnerstag, 30. April 2015 15:42
An: A Mailing list for WIEN2k users
Betreff: [Wien] Position of Atoms in AFM calculation.

Dear wien 2k users
 I am working on the compound DyPdBi. this compound is anti ferromagnetic upto 
3.5K(experimental report). crystal structure is MgAgAs  (216) .Dy (0,0,0),
Pd (0.75,0.75,0.75) and Bi(0.25,0.25,0.25)
I performed PBEsol calculation  for above mentioned positions without 
considering AFM.  I plotted band and DOS.
 Now i want to do AFM calculation again. I followed the steps given ,before 
trying with new compound i did for Cr, NiO.
 In my structure file   for AFM calculation the position of each compound is as 
follows
Dy 1 (000) and Dy2 (0.5,0.5,0.5 )
Pd(0.25,0.25,0.25) Bi (0.75,0.75,0.75) . Am i correct . i am not sure of the 
positions.
some one please confirm or correct me.
Thanks in advance.












9
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Re: [Wien] Position of Atoms in AFM calculation.

2015-05-01 Thread delamora
Dear Gerhard,
Sorry for my rudeness, I did not want to offend you.
What I see in the ICSD is that there is only DyPdBi reported (see below), and 
it is 
Dysprosium Palladium Bismuthide (1/1/1)
There there is only one Dy in this structure, so we are talking about two 
different compounds.
My apologies again and thanks for your reply about Hubbard U, 
I will look into it later.
Saludos

Pablo

--
*data for   ICSD #616637
Coll Code   616637
Rec  Date   2012/02/01
Chem Name   Dysprosium Palladium Bismuthide (1/1/1)
Structured  Dy Pd Bi
Sum Bi1 Dy1 Pd1
ANX NOP
D(calc) 10.83
Title   Mg Ag As - type phases in the ternary systems of rare earths with 
palladium and bismuth
Author(s)   Marazza, R.;Rossi, D.;Ferro, R.
Reference   Gazzetta Chimica Italiana
(1980), 110, 357
Unit Cell   6.643(2) 6.643(2) 6.643(2) 90.0 90.0 90.0
Vol 293.15
Z   4
Space Group F -4 3 m
SG Number   216
Cryst Sys   cubic
Pearson cF12
Wyckoff c b a
Red CellF  4.697 4.697 4.697 60 60 60 73.288
Trans Red   0.500 0.500 0.000 / 0.000 0.500 0.500 / 0.500 0.000 0.500
CommentsAtom positions estimated by editor, not refined
Cell and Type only determined by the author(s). Coordinates 
estimated by the editor in analogy to isotypic compounds. 
Metals formula record: Bi Dy Pd (z = 4) F4-3M
Metals structure type Ag As Mg
Structure type : AlLiSi
X-ray diffraction from single crystal 
No R value given in the paper.
At least one temperature factor missing in the paper.
Atom  #   OX   SITE  x   y   z   SOF  H 
 Bi   1  +04 a   0   0   0  1. 0
 Dy   1  +04 b   0.5 0.5 0.51. 0
 Pd   1  +04 c   0.250.250.25   1. 0
Std. Notes  Transformation Method: Tidy
Multiple transformations possible, first one selected
Std. Cell   6.643 6.643 6.643 90 90 90
Std. Vol.   293.15
Std. Z  4
Std. SG F4-3M
Std. Atom
Atom  #   OX   SITE  x   y   z   SOF 
 Bi   1  +04 a   0   0   0  1.
 Dy   1  +04 b   .5  .5  .5 1.
 Pd   1  +04 c   .25 .25 .251.
*end forICSD #616637



De: wien-boun...@zeus.theochem.tuwien.ac.at 
wien-boun...@zeus.theochem.tuwien.ac.at en nombre de Fecher, Gerhard 
fec...@uni-mainz.de
Enviado: viernes, 1 de mayo de 2015 12:50 p. m.
Para: A Mailing list for WIEN2k users
Asunto: Re: [Wien] Position of Atoms in AFM calculation.

DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
I think the problem, to be quite honest with you,
is that you have never actually known what the question is.

Ciao Gerhard
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Re: [Wien] Position of Atoms in AFM calculation.

2015-05-01 Thread Murugan Sundareswari
Thanks a lot.its is not frustating, but it is confusing, each one of you
have given different answer.it will take time for me to do calculation.i
will definetly come back with some more doubts please help me like this
thanks all
On Apr 30, 2015 9:01 PM, delamora delam...@unam.mx wrote:

 Gerhard,
 No, Murugan is right, it is DyPdBi
 Although I found in the structure base find it
 a=b=c=6.643
 Dy: 0,0,0
 Pd: 3/4,3/4,3/4
 Bi: 1/2,1/2,1/2 and Murugan has 1/4,1/4,1/4
 In terms of frustration this difference does not make a difference, since
 Bi is magnetically neutral.
 Saludos

 Pablo
 
 De: wien-boun...@zeus.theochem.tuwien.ac.at 
 wien-boun...@zeus.theochem.tuwien.ac.at en nombre de Fecher, Gerhard 
 fec...@uni-mainz.de
 Enviado: jueves, 30 de abril de 2015 10:05 a. m.
 Para: A Mailing list for WIEN2k users
 Asunto: Re: [Wien] Position of Atoms in AFM calculation.

 No. its wrong
 now you have Dy2PdBi instead of DyPdBi

 you need to make a suitable supercell, or use a P instead of a F cell and
 distinguish the Dy atoms in a suitable way such that you can set spins of
 opposite direction
 you also will need LDA+U, otherwise the Nd 4f states will appear at the
 Fermi energy

 A description of different types of AFM order in Heusler compounds are
 given in the Landolt Börnstein (I don't remember the issue)

 Ciao
 Gerhard

 DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
 I think the problem, to be quite honest with you,
 is that you have never actually known what the question is.

 
 Dr. Gerhard H. Fecher
 Institut of Inorganic and Analytical Chemistry
 Johannes Gutenberg - University
 55099 Mainz
 and
 Max Planck Institute for Chemical Physics of Solids
 01187 Dresden
 
 Von: wien-boun...@zeus.theochem.tuwien.ac.at [
 wien-boun...@zeus.theochem.tuwien.ac.at] im Auftrag von Murugan
 Sundareswari [sundare65w...@gmail.com]
 Gesendet: Donnerstag, 30. April 2015 15:42
 An: A Mailing list for WIEN2k users
 Betreff: [Wien] Position of Atoms in AFM calculation.

 Dear wien 2k users
  I am working on the compound DyPdBi. this compound is anti ferromagnetic
 upto 3.5K(experimental report). crystal structure is MgAgAs  (216) .Dy
 (0,0,0),
 Pd (0.75,0.75,0.75) and Bi(0.25,0.25,0.25)
 I performed PBEsol calculation  for above mentioned positions without
 considering AFM.  I plotted band and DOS.
  Now i want to do AFM calculation again. I followed the steps given
 ,before trying with new compound i did for Cr, NiO.
  In my structure file   for AFM calculation the position of each compound
 is as follows
 Dy 1 (000) and Dy2 (0.5,0.5,0.5 )
 Pd(0.25,0.25,0.25) Bi (0.75,0.75,0.75) . Am i correct . i am not sure of
 the positions.
 some one please confirm or correct me.
 Thanks in advance.












 9
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Re: [Wien] Position of Atoms in AFM calculation.

2015-04-30 Thread Fecher, Gerhard
No. its wrong
now you have Dy2PdBi instead of DyPdBi

you need to make a suitable supercell, or use a P instead of a F cell and 
distinguish the Dy atoms in a suitable way such that you can set spins of 
opposite direction
you also will need LDA+U, otherwise the Nd 4f states will appear at the Fermi 
energy 

A description of different types of AFM order in Heusler compounds are given in 
the Landolt Börnstein (I don't remember the issue)

Ciao
Gerhard

DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
I think the problem, to be quite honest with you,
is that you have never actually known what the question is.


Dr. Gerhard H. Fecher
Institut of Inorganic and Analytical Chemistry
Johannes Gutenberg - University
55099 Mainz
and
Max Planck Institute for Chemical Physics of Solids
01187 Dresden

Von: wien-boun...@zeus.theochem.tuwien.ac.at 
[wien-boun...@zeus.theochem.tuwien.ac.at] im Auftrag von Murugan Sundareswari 
[sundare65w...@gmail.com]
Gesendet: Donnerstag, 30. April 2015 15:42
An: A Mailing list for WIEN2k users
Betreff: [Wien] Position of Atoms in AFM calculation.

Dear wien 2k users
 I am working on the compound DyPdBi. this compound is anti ferromagnetic upto 
3.5K(experimental report). crystal structure is MgAgAs  (216) .Dy (0,0,0),
Pd (0.75,0.75,0.75) and Bi(0.25,0.25,0.25)
I performed PBEsol calculation  for above mentioned positions without 
considering AFM.  I plotted band and DOS.
 Now i want to do AFM calculation again. I followed the steps given ,before 
trying with new compound i did for Cr, NiO.
 In my structure file   for AFM calculation the position of each compound is as 
follows
Dy 1 (000) and Dy2 (0.5,0.5,0.5 )
Pd(0.25,0.25,0.25) Bi (0.75,0.75,0.75) . Am i correct . i am not sure of the 
positions.
some one please confirm or correct me.
Thanks in advance.












9
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Re: [Wien] Position of Atoms in AFM calculation.

2015-04-30 Thread delamora
Gerhard,
No, Murugan is right, it is DyPdBi
Although I found in the structure base find it
a=b=c=6.643
Dy: 0,0,0
Pd: 3/4,3/4,3/4
Bi: 1/2,1/2,1/2 and Murugan has 1/4,1/4,1/4
In terms of frustration this difference does not make a difference, since Bi is 
magnetically neutral.
Saludos

Pablo

De: wien-boun...@zeus.theochem.tuwien.ac.at 
wien-boun...@zeus.theochem.tuwien.ac.at en nombre de Fecher, Gerhard 
fec...@uni-mainz.de
Enviado: jueves, 30 de abril de 2015 10:05 a. m.
Para: A Mailing list for WIEN2k users
Asunto: Re: [Wien] Position of Atoms in AFM calculation.

No. its wrong
now you have Dy2PdBi instead of DyPdBi

you need to make a suitable supercell, or use a P instead of a F cell and 
distinguish the Dy atoms in a suitable way such that you can set spins of 
opposite direction
you also will need LDA+U, otherwise the Nd 4f states will appear at the Fermi 
energy

A description of different types of AFM order in Heusler compounds are given in 
the Landolt Börnstein (I don't remember the issue)

Ciao
Gerhard

DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
I think the problem, to be quite honest with you,
is that you have never actually known what the question is.


Dr. Gerhard H. Fecher
Institut of Inorganic and Analytical Chemistry
Johannes Gutenberg - University
55099 Mainz
and
Max Planck Institute for Chemical Physics of Solids
01187 Dresden

Von: wien-boun...@zeus.theochem.tuwien.ac.at 
[wien-boun...@zeus.theochem.tuwien.ac.at] im Auftrag von Murugan Sundareswari 
[sundare65w...@gmail.com]
Gesendet: Donnerstag, 30. April 2015 15:42
An: A Mailing list for WIEN2k users
Betreff: [Wien] Position of Atoms in AFM calculation.

Dear wien 2k users
 I am working on the compound DyPdBi. this compound is anti ferromagnetic upto 
3.5K(experimental report). crystal structure is MgAgAs  (216) .Dy (0,0,0),
Pd (0.75,0.75,0.75) and Bi(0.25,0.25,0.25)
I performed PBEsol calculation  for above mentioned positions without 
considering AFM.  I plotted band and DOS.
 Now i want to do AFM calculation again. I followed the steps given ,before 
trying with new compound i did for Cr, NiO.
 In my structure file   for AFM calculation the position of each compound is as 
follows
Dy 1 (000) and Dy2 (0.5,0.5,0.5 )
Pd(0.25,0.25,0.25) Bi (0.75,0.75,0.75) . Am i correct . i am not sure of the 
positions.
some one please confirm or correct me.
Thanks in advance.












9
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Re: [Wien] Position of Atoms in AFM calculation.

2015-04-30 Thread delamora
Dear Murugan,

The Cr example has BCC symmetry, your compound is FCC.

You have to be more explicit in your letter.


I looked at the structure;

DyPd make a ZnS structure, that is, it is diamond-like. Bi is 
non-magnetic.

Dy will certainly have a magnetic moment, but Pd?

Dy makes a FCC structure with interconnected tetrahedra, the 111 planes 
are triangular, this makes the antiferromagnetic order what is called 
geometical frustration

en.wikipedia.org/wiki/Geometrical_frustration

so you have a difficult but interesting problem that cannot be treated easily 
with the WIEN2k code because it is a non-collinear magnetic system.

On the other hand you make some assumptions;

You choose a direction and put the alternative planes in alternating spin 
directions.

You can choose 100 or 111. 100 is simpler to handle;

With the supercell program you take the unit cell and just save as P. After, 
the Dy at 0yz you set it as up, and the one at 0.5yz as dn.

I hope that this does not create a frustration to you...


Pablo


De: wien-boun...@zeus.theochem.tuwien.ac.at 
wien-boun...@zeus.theochem.tuwien.ac.at en nombre de Murugan Sundareswari 
sundare65w...@gmail.com
Enviado: jueves, 30 de abril de 2015 08:42 a. m.
Para: A Mailing list for WIEN2k users
Asunto: [Wien] Position of Atoms in AFM calculation.

Dear wien 2k users
 I am working on the compound DyPdBi. this compound is anti ferromagnetic upto 
3.5K(experimental report). crystal structure is MgAgAs  (216) .Dy (0,0,0),
Pd (0.75,0.75,0.75) and Bi(0.25,0.25,0.25)
I performed PBEsol calculation  for above mentioned positions without 
considering AFM.  I plotted band and DOS.
 Now i want to do AFM calculation again. I followed the steps given ,before 
trying with new compound i did for Cr, NiO.
 In my structure file   for AFM calculation the position of each compound is as 
follows
Dy 1 (000) and Dy2 (0.5,0.5,0.5 )
Pd(0.25,0.25,0.25) Bi (0.75,0.75,0.75) . Am i correct . i am not sure of the 
positions.
some one please confirm or correct me.
Thanks in advance.












9
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Wien@zeus.theochem.tuwien.ac.at
http://zeus.theochem.tuwien.ac.at/mailman/listinfo/wien
SEARCH the MAILING-LIST at:  
http://www.mail-archive.com/wien@zeus.theochem.tuwien.ac.at/index.html