Hi friends,
Already I had posted a doubt regarding how to run a servlet program
The reply was to add a class path or the jar file and the jdk classes.zip
I tried running with
javac -classpath c:\jsdk2.0\lib\jsdk.jar;c:\jdk1.1.8\lib\classes.zip
SimpleServlet.java
and the servlet was compiled and i got the corresponding class file
Question:
Do i have to use this command every time i compile a servlet
Can't i declare the class path somewhere else
I have tried typing
classpath c:\jsdk2.0\lib\jsdk.jar;c:\jdk1.1.8\lib\classes.zip in the
autoexec.bat
Please do give the exact solution
Thanx in advance
--
V.T.R. Ravi Kumar
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