Re: Servlet as default "page" for web app

Scott Venter Mon, 05 Mar 2001 01:44:29 -0800
This can be achieved by manipulating the configuration of the web.xml file
for that particular web application. This implies a Tomcat web application
configuration, and does not require servlet code.

I have attached a sample of the web.xml


<!--starts web.xml-->

<?xml version="1.0" encoding="ISO-8859-1"?>

<!--    @author         scott venter
      @created    07 February 2001
      @version    1.0.1, September 1, 1999
      @info             CellPoint Systems www.cellpoint.com
 -->

<!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN"
    "http://java.sun.com/j2ee/dtds/web-app_2.2.dtd">

<web-app>
<!--I have set up the name for main servlet which will handle all webapp
traffic-->
    <servlet>
        <servlet-name>login</servlet-name>
        <servlet-class>webapp.Login</servlet-class>

    <init-param>
      <param-name>JDBCDriver</param-name>
      <param-value>com.internetcds.jdbc.tds.Driver</param-value>
    </init-param>

    <init-param>
      <param-name>JDBCURL</param-name>
      <param-value>jdbc:freetds:sqlserver://sqlserver/webapp</param-value>
    </init-param>

    <init-param>
      <param-name>Username</param-name>
      <param-value>sa</param-value>
    </init-param>

    <init-param>
      <param-name>Password</param-name>
      <param-value>sa</param-value>
    </init-param>

    <init-param>
      <param-name>MaxConnectionCount</param-name>
      <param-value>10</param-value>
    </init-param>
  </servlet>

<!--Here I map the login servlet to the base context of the web app:
    http://localhost:8080/webapp/ will now actually call the login
servlet -->
  <servlet-mapping>
      <servlet-name>login</servlet-name>
      <url-pattern>/</url-pattern>
 </servlet-mapping>

<!--The above configuration negates the need for a welcome-file,
    since we are directing a hit to the webapp base context directly to the
login servlet

 <welcome-file-list>
   <welcome-file>main.html</welcome-file>
 </welcome-file-list>

  -->

</web-app>

<!--ends web.xml-->



-----Original Message-----
From: A mailing list for discussion about Sun Microsystem's Java Servlet
API Technology. [mailto:[EMAIL PROTECTED]]On Behalf Of Milt
Epstein
Sent: Friday, March 02, 2001 8:04 AM
To: [EMAIL PROTECTED]
Subject: Servlet as default "page" for web app


I just started using Tomcat, and hence the 2.2 servlet spec.  But I
don't think this is anything specific to Tomcat, it seems like it just
has to do with what the 2.2 servlet spec allows.

What I'm trying to do is have a URL of the form:

http://some.domain.name/blah

go directly to a servlet, i.e. something that normally you'd get to
with a URL of the form:

http://some.domain.name/blah/servlet/blah

I've set up blah as a webapp (i.e. a context), and essentially I'd
like a servlet to be the default "page" of the webapp.  The default
page can be a static html page (e.g. index.html) or a JSP
(e.g. index.jsp), so why not a servlet?  But I've tried a few things
with the webapp's servlet names and servlet mappings in the web.xml
file, without success.

At jakarta.apache.org, I found a similar question in the FAQ-o-matic,
and it suggested having the default index page do a redirect, and/or
using Apache's mod_rewrite.  I tried the former, both with a static
html page (and a META Refresh) and a JSP (and a RequestDispatcher
forward()), and while it works, it changes the Location: shown by the
browser to:

http://some.domain.name/blah/servlet/blah

which I'd like to avoid.  I thought maybe there was something
available via the servlet spec (and/or Tomcat) that I was missing.

I'm looking into the mod_rewrite solution as well.

Thanks.

Milt Epstein
Research Programmer
Software/Systems Development Group
Computing and Communications Services Office (CCSO)
University of Illinois at Urbana-Champaign (UIUC)
[EMAIL PROTECTED]

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Re: Servlet as default "page" for web app

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