Maybe the value of parameter "ID" is spaces.
:^)
Ricky Y. Artigas
Analyst/Programmer
Information Technology Division
Easycall Communications Phils., Inc.
- Easycall Internet -
418 Arayat St., Mandaluyong City 1550, Philippines
Personal WAP Site: http://www.buzzed.co.uk/mobile/?rya
Company Website: http://www.easycall.com.ph
Tel.no: (+632) 5338001 ext.6574
Mobile:(+63) 0917-8951783
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Email: [EMAIL PROTECTED]
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> -----Original Message-----
> From: irene_plj asiamail.com [SMTP:[EMAIL PROTECTED]]
> Sent: Wednesday, April 04, 2001 10:57 AM
> To: [EMAIL PROTECTED]
> Subject: Simple Problem....
>
> Hi all ,
>
> The problem wf the below code(part of my servlet)is i always get the "if"
> condition even if it "p" equals null..
> Wat could be wrong???
> This is such a simple problem but i jus cannot get the "else" condition
> when p==null.
> Anyone any idea why this cannot work??
> Thks .
>
> ******************************************
> ..
> ..
> try
> {
> String p=request.getParameter("ID");
> if(p != null)
> {
> String to=p+"@asiamail.com";
> }
> else
> {
> String to="[EMAIL PROTECTED]";
> }
>
> }
> ..
> ..
> **********************************************
> --
>
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