It was sort of correct. The whole thin should have been
String p1= String.valueOf(p);
if(p1.equals("null"))......
-----Original Message-----
From: Jay Burgess <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED] <[EMAIL PROTECTED]>
Date: Wednesday, April 04, 2001 8:32 AM
Subject: Re: Simple Problem....
>Your response is not correct. If p is null, then there is no object, so
>there is no equals() method to call. You'll get NullPointerException if
>you try to execute your example and p is null.
>
>Jay
>
>-----Original Message-----
>From: Poornima Visvesvaran [mailto:[EMAIL PROTECTED]]
>Sent: Wednesday, April 04, 2001 7:00 AM
>To: [EMAIL PROTECTED]
>Subject: Re: Simple Problem....
>
>
>Hi,
>
>instead of if(p!=null),
>
>use
>
>if(!(p.equals(null))
>{}
>
>It will work.
>
>Poornima Visvesvaran.
>--- "Artigas, Ricardo Y." <[EMAIL PROTECTED]> wrote:
> > Maybe the value of parameter "ID" is spaces.
> >
> > :^)
> > Ricky Y. Artigas
> > Analyst/Programmer
> > Information Technology Division
> > Easycall Communications Phils., Inc.
> > - Easycall Internet -
> > 418 Arayat St., Mandaluyong City 1550, Philippines
> > Personal WAP Site:
> > http://www.buzzed.co.uk/mobile/?rya
> > Company Website: http://www.easycall.com.ph
> > Tel.no: (+632) 5338001 ext.6574
> > Mobile:(+63) 0917-8951783
> > Pager: 141-002955
> > Email: [EMAIL PROTECTED]
> >
> >
> > > -------------------------------
> > > IMPORTANT NOTICE:
> >
> > > This message (and any attachment hereto) may
> > contain privileged and/or
> > > confidential information specific to EasyCall. If
> > you are not the intended
> > > addressee indicated in this message, you may not
> > copy or disseminate this
> > > message (or any attachment hereto) to anyone.
> > Instead, please destroy this
> > > message (and any attachment hereto), and kindly
> > notify the sender by reply
> > > email. Any information in this message (and any
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> > > do not relate to the official business of EasyCall
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> > >
> > >
> > > -----Original Message-----
> > > From: irene_plj asiamail.com
> > [SMTP:[EMAIL PROTECTED]]
> > > Sent: Wednesday, April 04, 2001 10:57 AM
> > > To: [EMAIL PROTECTED]
> > > Subject: Simple Problem....
> > >
> > > Hi all ,
> > >
> > > The problem wf the below code(part of my
> > servlet)is i always get the "if"
> > > condition even if it "p" equals null..
> > > Wat could be wrong???
> > > This is such a simple problem but i jus cannot get
> > the "else" condition
> > > when p==null.
> > > Anyone any idea why this cannot work??
> > > Thks .
> > >
> > > ******************************************
> > > ..
> > > ..
> > > try
> > > {
> > > String p=request.getParameter("ID");
> > > if(p != null)
> > > {
> > > String to=p+"@asiamail.com";
> > > }
> > > else
> > > {
> > > String to="[EMAIL PROTECTED]";
> > > }
> > >
> > > }
> > > ..
> > > ..
> > > **********************************************
> > > --
> > >
> > > _______________________________________________
> > > Get your free email from
> > http://freemail.asiamail.com
> > >
> > >
> >
>
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