You can only go back to the root of your project when using getResource
For the servlet 2.3 specs:
"The getResource and getResourceAsStream methods take a String with
a
leading "/" as argument which gives the path of the resource
relative to the root of
the context. This hierarchy of documents may exist in the server's
file system, in a
web application archive file, on a remote server, or at some other
location."
As you can see beginning with the / is a requirement.
for mine, i use getServletContext().getResource("/flow.xml");
This refers to the /flow.xml in my root directory.
If your Register1.asp is not in the root directory or its subfolders then
you need to move it.
-Tim
-----Original Message-----
From: Varley, Roger [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 8:15 AM
To: [EMAIL PROTECTED]
Subject: Re: Your Message Sent on Tue, 19 Mar 2002 15:35:33 -0000
>
> You should use something like
>
> ServletContext ct = config.getServletContext();
>
> URL url=ct.getResource("/WEB-INF/foo/bar/bletch")
>
> This avoid hard coding in a path in to your servlet, which
> avoids all sorts of
> .. problems.
>
Thanks for your response but this doesn't work. If I try
ServletContext sc = config.getServletContext();
URL url = sc.getResource("../../ipscgibin/Register1.asp");
URLConnection uc = url.openConnection();
then the servlet crashes with a null pointer exception and Tomcat outputs
the message
"Unsafe Path e:\tomcat\webapps\Application /../../iscgibin/Register1.asp" So
it would appear that using a relative path with getResource() doesn't step
up the web site hierachy. I can get around the problem with creating a new
URL object using an absoloute path, but this means I have to mainain two
versions of the servlet, one for our test site and one for production which
doesnt seem a very good way and maintaining a properties file seems a bit of
an overkill. Surely there must be a simple way of specifying a relative path
that steps out of the Tomcat/servlet structure onto the wwwroot hierachy.
Regards
Roger
> >
> >Hi
> >
> >I'm using Tomcat 3.2 and IIS on Windows NT. I have a servlet that is
> >accessed by the url wwwroot/Application/servlet/ServletName and is
> >physically located at
> e:\tomcat\Application\WEB-INF\classes\ServletName.
> >Within the servlet I want to open a URLConnection and I want
> to build the
> >URL object specifying a relative path to
> wwwroot/cgibin/program_name. I
> >can't work out how the Tomcat path fits into the web
> hierachy so I get the
> >right number of "/../../'s" into my path. How do I specify the path?
> >
> >url = new URL("../../cgibin/programe_name") doesn't appear to work.
> >
> >Regards
> >Roger
> >
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