>
>
> You can only go back to the root of your project when using
> getResource
>
> For the servlet 2.3 specs:
>
> "The getResource and getResourceAsStream methods take
> a String with
> a
> leading "/" as argument which gives the path of the resource
> relative to the root of
> the context. This hierarchy of documents may exist in
> the server's
> file system, in a
> web application archive file, on a remote server, or
> at some other
> location."
>
> As you can see beginning with the / is a requirement.
>
> for mine, i use getServletContext().getResource("/flow.xml");
> This refers to the /flow.xml in my root directory.
> If your Register1.asp is not in the root directory or its
> subfolders then
> you need to move it.
Hi,
Thanks for your response. I've tried that and moved the register1.asp file.
The code now looks like;
ServletContext sc = config.getServletContext();
url = sc.getResource("/register1.asp");
System.out.println(url.toString());
I must be missing something obvious though because now the problem is that
getResource() is returning a file:// url not an Http url so when I try to
open the connection, the servlet crunches again. The system prints the
content of the URL as file:e:\tomcat\webapps\Application\register1.asp. I
need an HTTP connection.
Regards
Roger
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