I am one of these 5 day/week listmembers, so I got the whole load of Crowcroft
material this morning.  I am pleased at how well you all answered his salvo -
nice job!  Let me say that I make CS using the LVDC method and I have learned
a lot from the recommendations on the list.  I and my family have been blessed
thus far with good health, but I use CS to doctor us for various minor
problems.

Since I am keen to understand the science of CS production, I paid extra
attention to the electrochemistry discussion.  I found Ivan Anderson's
comments especially helpful.

I take it that no one disagrees with the basic electrochemical reaction
Crowcroft has diagrammed, except Ivan states that the free electrons are
mostly consumed in neutralizing/reducing Ag+ rather than in producing H2 gas. 
Apparently Crowcroft thinks that OH- ions produced at the cathode can react
with Ag+ to form a silver oxide.  Is this reaction possible, even assuming
that an appreciable quantity of OH- is produced?  I suppose this would
liberate more hydrogen if it happens.  By the way, I never see any visible gas
production at the cathode of my LVDC setup.

However, what DOES happen to the free electrons?  

If they were primarily used in reducing Ag+ at the cathode as Ivan suggests,
then there would be little or no Ag+ remaining in in the cell at the end of
the reaction.  Or, does it happen like this: a small particle (not atom)of
silver loses an electron as it is removed from the anode, it ultimately
regains the electron at the cathode, and remains in suspension as a neutral
particle of silver (or, if too large, falls to the bottom of the cell).

I'd love to hear any further facts or theory along these lines to help me fill
in my gaps.

Alonzo
[email protected]

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