----- Original Message -----
From: "coyote" <[email protected]>
To: <[email protected]>
Sent: Monday, 10 April 2000 03:17
Subject: CS>long and winding oxides and how to make strong clear LVDC
CS

Dear Ken,

I hope you don't mind me saying this, but you seem to display the very
same adherence to dogma that you suspect others of, that is, clinging
to a belief either through ignorance or bloody mindedness.

How can we have a serious discussion if you do not know the meaning of
the terms you use!

>
> To my limited understanding, a silver ion is elemental metallic
silver with an added electron giving it a positive charge. It normally
has a valency of +1 therefore will tend to compound with other
elements with a negative valence such as oxygen [O, -2].

*Yes, a silver ion is an elemental silver atom LESS one or more
electrons and as such is no longer elemental silver. There is very
little dissolved oxygen in the body of distilled water, <3ppm. O2(gas)
will NOT react with elemental silver. O2(gas) is a neutral molecule.

>
> It is reasonable to me that the added electron of the ionic form
will make that elemental silver particle even more reactive with an
atom of negative valence such as oxygen forming perhaps any or all of
the three possible oxides of silver which may carry different color
ranges beside pure black. [I find no reference to this so it's a
supposition but is supported by observation of oxide deposit formation
under electrically charged conditions]

*Oxygen does not exist as a single free O(-1 or-2) atom in water.
There may be some formation of silver oxide at the anode but this is
negligeable.
>
> Theory: Formation of oxide deposits depends upon the
interrelationship of oxygen bubbles forming on the negative electrode
[varies with vapor pressure and surface tension of the water at
various temeratures which also determines bubble size and coherent
ability] where the smaller bubbles have greater available surface area
to form oxides, oxygen dissolved in the water [both normal airborne
oxygen and ozone from ozonation purification process] and the presence
of elemental ionic silver...coupled with decreasing electrical
activity that varies with distance due to accumulated resistance in
the water.

*See above regarding O2(gas).
There is no electrical activity in the water other than at the
electrode/water interface.

>
> On the positive hydrogen emmitting pole, high vapor pressure in warm
water can result in formation of large cohesive and adhesive hydrogen
bubbles that trap silver ions on their surface tension...the inside
surface of the bubble... that transfer to the surface tension of the
water when that pole is removed making a gray floater. These bubbles
also seem to insulate the pole and slow the ellectrical activity down
to near nothing.
> Hydrogen has a + valence as does the silver ion. They cannot combine
nor can the ion readily penetrate the surface tension of the bubble.

*Anode, positive electrode, oxidising, O2(gas) production, Ag+
production.
Cathode, negative electrode, reducing, H2(gas) production, Ag+
reduction to Ag elemental silver.

 > Oxidation: Oxidation is where an element or substance combines with
oxygen to form another compound. An oxidized element is no longer in
it's elemental form but is an oxide compound of that element or IOW
that element compounded with oxygen to form an oxide [or dioxide or
trioxide etc depending on how many oxygen atoms it's valence will
'hold'] The normal oxide of silver would be Ag2O because silver has a
valence of +1 and oxygen has a valence of -2, however, under
electrolytic conditions, silver can form 1 or 2 other oxides for a
total of three as per a previous post...one of which is, 'possibly',
as a result of silver hydroxide formation going further down the
reaction chain and losing its hydrogen. [I don't know for sure exactly
what happens but it's possible that there's a voltage varience
involved and voltage does vary or 'drop' with increasing
resistance...and resistance does increase with distance through a resi
stive medium such as water]

*Wrong! Oxidation, the process of removing an electron so as to make
an element or compound more positive.
Whether two elements combine depends on the electronegativity of the
elements and the Gibbs free energy sum.
As stated above, the only electrochemical reactions in a solution
occur at the electrode/solute interface. Electrical conduction in a
solution relies entirely upon the passage of ions from one electrode
to the other. There is no electron travel other than those which are
attached to ions.

>
> There is a maximum ionic crystal size involved here too. For silver,
it is .97 angstroms. The reading of what this means is confusing to me
but I gather [and may be mistaken] that an ion larger than that can be
formed but has a reactive radius greater than a maximum stable radius
of .97 angstroms, therefore will instantly compound with any available
element that has an opposite valence such as oxygen. This tells me
that it's possible to have a larger than .97 particle but it's not
100% ionic, nor is it pure silver...but is.. a partially oxidized
silver particle or a silver ion crystal of .97 angstroms with a silver
oxide molecule or two hanging onto it.

*The ionic radius of Ag+ is 1.29 A which is close to your measurement,
and represents one atom. The rest of the statement is mistaken
supposition in my opinion. Silver ions will form stable colloid
crystals, of various sizes (and hence colours) which become solvated
with water (surrounded by a water micelle) and so resist the approach
of negatively charged molecules or ions.

> This seems to be a sort of confirmation that:
> If high currents blast off larger ion clusters, these larger
clusters will readily [partially] oxidize. The oxides have a color.
Therefore, particle size does have something to do with color, BUT,
the color is due to pigmentation from oxides not refraction. [Colors
of pigments do have reflective properties due to light frequency
absorption] And, we're no longer talking about pure silver ion
clusters. Also, if the electrical pressure is great enough, they will
blast these partially oxidizing particles straight into suspension.

*Molecules do not 'have' pigments, their colour depends soley on the
reflection, refraction, absorption and emmitance of light. This is
directly related to the particle size as proved in previous posts.
YOU are no longer talking about pure silver ion clusters, as if that
is a fact!
 Look at carbon... Carbon black is a powdery substance which absorbs
light with no reflectance or emission in the visible spectrum, hence
it looks black. However sugar, which is a large molecule containing
many carbon atoms, when dissolved in water is colourless.

> Observation: When running CS generator at 6ma, the water quickly
turns brownish and the "ion" cloud has a brownish tinge. This seems to
correlate with observations of oxide color spread when running at .7
ma where current density in volt amps is greater on the negative
oxygen emmiting pole and is reduced by distance through the resistive
medium [water] where the lighter oxide deposit is yellow. When running
at or around 2 ma, the predominant color is light yellow and gets
darker as the amperage increases. The longer it runs at any particular
current, the more intense the color but the color remains the same
color.
> Note: I have never gotten a color change in the water when running
under .6 ma. and the ion cloud is always white.

*This is entirely consistant with the theory that higher currents net
larger silver particles.

> Why does the color stick to the glass after storing for a few weeks?
[It really does]
> Theory: The partially oxidized particles being under brownian motion
are heavier than and carry less charge than the smaller pure silver
ion crystals. Therefore, they have greater inertia upon impact with
the container and literally impact with great enough force to adhere
themselves onto the glass.
> Note: Hydrogen peroxide removes the color layer readily. [No clear
idea why]

*Again, one does not need to assume the presence of silver oxide for
this to be true.
Hydrgen peroxide removes this deposit, because it is elemental silver,
and so is able to supply an electron to the bound O(-1) ion so that it
may become O(-2) ion (which is oxygens most stable ion), which then
combine to form O2(gas). In doing so it has disassociated the metalic
silver by oxidation (removed electrons) and formed Ag+ ions which can
then be measured.

>
>
> Observation: Oxide deposits, when not stirred/agitated into the mix
by thermal currents or excessive voltage/current pressures tends to
deposit along the bottom of the container with the darkest black being
under the negative pole and the lightest yellow forming under the
positive pole and a range in between. These deposits, having had thier
charges neutralized by componding, stick firmly to the glass if given
a chance..that is...aren't kept agitated and suspended mechanically,
electrically [by electrical pressures] or thermally [thermal water
currents]
> Silver ions, if left undisturbed, also follow much the same pathways
as the oxides and being juxtaposed to the forming oxides, some of them
can lose their charge and stick to the glass as well, forming a
silvery coating that's quite difficult to remove. [plate out] The ions
are smaller and lighter than the oxides and so tend to travel higher
and wider than the oxide trail, again, if not excessivly agitated. The
plate out occures to the sides of the oxide trail.

*Oxides are not necessary to explain the above.

> In conclusion according to observation and [my] theory:
> To make clear and potent CS, run at a controlled current under 1 MA
in distilled water at a temperature decreasing from 100+\- deg or
increasing to 100+\- deg by applying a tiny heat source under the
container. This induces a small thermal current that keeps the ion
cloud moving but does not disturb the heavier oxides. They will stick
to the rod or the glass of the container.
> To reduce oxide load, limit the available dissolved oxygen by
heating and/or venting the water. Some oxides will still form, but
they will mostly be limited to and stuck firmly to the rod and easily
removed. There will be virtually none in the sol.
> The low current will prevent partial oxidation of silver ion
crystals because they will be emmited below the .97 angstrom diameter
treshhold.
> But, this being a delicate low pressure process, it tends to go into
equiliblium and nearly stop, sometimes locking ions up inside hydrogen
bubbles.. Solution: remove and clean all componants including the
water [pour into clean container temporarily] when no ion cloud
activity is seen or after about an hour, then reassemble [including
the previous water] and continue. A quite gratifying pure white ion
cloud will then form.

*The fact that you can't 'see' the cloud does not mean the reaction
has stopped, it just means the particles involved are too small to
see.

*Further proof that what I have said is true... that there is little
if any silver oxide in coloured solutions, can be found in the fact
that my Ion Selective Electrode test equipement measures the activity
of silver ions only. It does not measure the activity of any other ion
(except sulphide) or compound. When the results of an (ISE) reading of
coloured CS (as produced by myself, others may have elemental particle
inclusion) is compared to the Atomic Absorption (AA) test result
(which measures total silver content, regardless of ionic nature or
compound) the results match to within the margin of error!

> k...@czen aka KD'C

Ivan.



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