In a message dated 4/4/01 7:26:59 AM EST, [email protected] writes:

<< Subj:     Re: CS>Model to Explain Charge Buildup for LVDC CS 
Electrochemical Reactions
 Date:  4/4/01 7:26:59 AM EST
 From:  [email protected] (Ivan Anderson)
 Reply-to:  [email protected]
 To:    [email protected]
 
 
 ----- Original Message -----
 From: <[email protected]>
 
 > Ivan: To keep things as simple as possible, the following discussion
 pertains
 > to the initial few minutes of CS electrolysis. It seems to me that if
 salt is
 > added to water, the ionic species responsible for carry the charge
 changes
 > from silver ions (in the case when no salt is present) to Na+ and Cl-
 which
 > then carry all of the charge between the two silver electrodes. If
 NaCl is
 > carrying ~100% of the charge, how can a charge buildup occur for Ag+
 ions
 > when they no longer play a significant charge carrying role?
 
 Roger as the Na+ and Cl- are present as separate ions, and all the
 reactions take place at the electrode solvent interface, the oxidation
 of  Ag ----> Ag+ (0.8V) will procede before the oxidation of
 Cl-  ----> Cl (1.4V).

Ivan: Cl- can STILL carry the charge without undergoing a reduction to 
chlorine gas. At the electrode surface, the half cell reaction requiring the 
lowest EMF will proceed which, generally speaking, will NOT be the reduction 
of chloride to chlorine gas..    
 
 > In the former case (no salt is present), Ag+ cations are just
 beginning to be
 > produced at the anode so there is very little Ag+ available to
 transfer
 > charge to the cathode, AND other than OH- (at ~10^-7 moles/liter),
 there are
 > no significant amounts of other anionic species available to carry the
 charge
 > from the cathode to the anode. Consequently, a charge buildup occurs
 similar
 > to what happens in a with the "no salt bridge" Zn/H2 battery. When
 salt is
 > added to the water, a charge buildup cannot occur because Na+ and Cl-
 are
 > available to carry charge between the cathode and anode respectively.
 
But for every Ag+ ion that enters solution some other species is gaining
an electron and charge neutrality is preserved.

Ivan: No doubt you are correct. How about,

2H2O + 2e --------> H2(g) + 2OH-   E = 0.81

as mentioned previously?

However, at least during the early part of the CS electrolysis, there may be 
an excess of positive ions (Ag+) near the anode, and an excess of negative 
ions(OH-) near the cathode, similar to the two beaker charge buildup in the 
Zn/H2 example I used previously. 

However what happens when Ag+ ions are added from an outside source, such as 
plasma arc, the net charge must increase then?

Ivan: I think we are talking about an entirely different mechanism, one that 
does not involve half cell reactions. If SOME silver ions are produced in the 
plasma (and an earlier literature search I did indicated that there is too 
little energy generated from our HVAC power supplies to produce silver ions 
in the gas. Rather the plasma contains mostly gaseous silver that condenses 
in the water as neutral CS particles.) then the following reaction is 
possible,

(1) [Ag+] + H2O ------>   AgOH(s) + [H+]

Perhaps reaction(1) explains the frequent the low pH associated with the 
production of HVAC CS by the arc method.    
 
Roger 


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