Greetings all! Would someone mind checking my equation?
Taking a one ounce 35% H2O2 solution and diluting down to a 3% solution is taking 11 ounces of water and adding roughly one ounce of 35% H2O2... This is ROUGHLY a 11:1 ratio, right? The formula I'm using to try to be a bit more accurate for concentrations is: For a ~ four ounce container: Amount of distilled water = y Amount of 35% H2O2 = 4- y Final Solution = 4 ounces Equation: % solution 1 X ( amount ) + % solution 2 X (amount) = % ending solution X ending amount .35(4-y) + 0y = 4 X .03 1.4 - .35y = .12 -.35y = -1.28 y = 3.65 ounces ( amount of distilled water ) amount of H2O2 = .343 ounces Right? Thanks... -- The silver-list is a moderated forum for discussion of colloidal silver. To join or quit silver-list or silver-digest send an e-mail message to: [email protected] -or- [email protected] with the word subscribe or unsubscribe in the SUBJECT line. To post, address your message to: [email protected] Silver-list archive: http://escribe.com/health/thesilverlist/index.html List maintainer: Mike Devour <[email protected]>
