"For the concentration of Ag+ to increase, Ag must be oxidised at the anode and something other than Ag+ reduced at the cathode. There is only water available and so H2O is reduced to form H2(g), this means that the concentration of OH- increases, but this is likely tied up in forming rings around Ag+ ions at a ratio of 6 to 1"
Ivan: Could you expand on your 6:1 ratio idea. "which further leads to the probability that free H+ concentration increases and pH lowers." Ivan: Are you saying that Ag+ ties up 6 OH- ions which then frees up H+ (from water presumably) so that the pH decreases? But we are talking about XS OH- ions produced at the cathode, not removing OH- from water by Ag+ alone. If that's what you are saying then I don't follow your reasoning. Ivan: Certainly creating a salt bridge between the two electrodes so that the pH near each electrode can be followed over time should go a long way in determining what is going on, don't you think? Roger -- The silver-list is a moderated forum for discussion of colloidal silver. To join or quit silver-list or silver-digest send an e-mail message to: [email protected] -or- [email protected] with the word subscribe or unsubscribe in the SUBJECT line. To post, address your message to: [email protected] Silver-list archive: http://escribe.com/health/thesilverlist/index.html List maintainer: Mike Devour <[email protected]>
