> The above calculation is for a single elecrode. Most use 2 so to get > the actual current density of your setup you will need to divide the > calculated current density by 2 which would give a current density of > 500 uA per mm^2.
Err, George? Both electrodes are passing the same current, so I don't think you need this last step... I would think only the anode surface area need be calculated. Other than that, it makes sense. <smile> Be well, Mike D. [Mike Devour, Citizen, Patriot, Libertarian] [[email protected] ] [Speaking only for myself... ] -- The silver-list is a moderated forum for discussion of colloidal silver. To join or quit silver-list or silver-digest send an e-mail message to: [email protected] -or- [email protected] with the word subscribe or unsubscribe in the SUBJECT line. To post, address your message to: [email protected] Silver-list archive: http://escribe.com/health/thesilverlist/index.html List maintainer: Mike Devour <[email protected]>
