In a message dated 10/11/2001 6:40:25 AM Eastern Daylight Time, [email protected] writes:
> From the standpoint of making CS, what goes on at the Cathode has > no effect on the dynamics at the Anode, where silver atoms are leaving > the surface and undergoing agglomeration and hydration -- except its > role in determining the overall resistance of the circuit, which also > becomes irrelevant if you're doing current control. > > You may define "current density" differently than I do, but it seems > that you need only calculate current density for the anode. We *are* > both talking about a typical LVDC system, right? > > Anybody else have an opinion? > > Mike D. > Mike is definitely fired up today. After two years on this list, how could I have guessed that, beside bad behavior and a newbie question here and there, it would be current density that would get him to jump in more often? Well, anyway welcome aboard! I agree completely with Mike. There is only ONE current, and the dynamics at one electrode are independent of the dynamics at the other electrode. Since almost all of our process control is based on what is happening at the anode, practically speaking, it is the anode surface area that determines the current density of the process, even though there could be (and probably is) a completely different current density at the cathode. Now I'd like to change the subject. Mike, and many others have said the following (I'm using Mike's words here for convenience): "...where silver atoms are leaving the surface and undergoing agglomeration and hydration..." Assuming we agree that in an electrochemical reaction, it's silver IONS that leave the anode, can someone please explain to me what happens to make them AGGLOMERATED ATOMS that later become hydrated. Please write the reaction(s) that is (are) responsible for this change of state. Roger
