url: http://escribe.com/health/thesilverlist/m60344.html
Re: CS>Re: Nebulizing CS for SARS Redux
From: C Creel
Date: Wed, 18 Jun 2003 07:52:17
[...]
> For example, so many things work in vitro that don't work in vivo.
> Right now, NIH scientists find that licorice is disbling the SARS
> virus. The chances it will do this in vivo are quite slim. But
> wouldn't it be grand if it did?
> It would be grand if NO worked. In theory it should. It even
> stands a good chance in practice - but only if we can create
> another delivery system that won't risk the lives of others.
> I'd be glad to introduce your idea to the SARS Task Force if you
> can come up with an idea for a safe way of administering it.
> Regards,
> Catherine
Catherine,
Your caring shows in each letter of each word you write.
A question: if they are willing to try licorice in vitro, would they
be willing to try cs?
I would recommend making it at a current density of 100 uA per
square inch or less.
I now make 425 ml of 19 ppm calculated in 6 hrs with a current
density of 87 uA per square inch. There is very little black deposit
on the anode and none on the cathode.
I find this much more effective against Shingles and cold sore
viruses than the cs I previously recommended to you made at 1.4 mA
per square inch.
Here are the equations:
hrs = 6 ; hours
mnt = 0 ; minutes
I = 335e-6 ; current in Amperes
ml = 425 ; milliliters
x = 1e6 * 107.87 / 96485 ; Faraday's electrolysis equation
sec = hrs * 3600 + mnt * 60 ; seconds
C = I * sec ; coulombs
ppm = x * C / ml ; parts per million
ppmhr = x * I * 3600 / ml ; ppm per hr
Here are the results:
Solution Variables:
hrs = +6.00000000000000
mnt = 0.00000000000000
I = +0.00033500000000
ml = +425.000000000000
x = +1117.99761620977
sec = +21600.0000000000
C = +7.23600000000000
ppm = +19.0348958844563
ppmhr = +3.17248264740938
Residuals and derived equations:
{ 0 } hrs = 6
{ 0 } mnt = 0
{ 0 } I = 0.000335
{ 0 } ml = 425
{ 0 } x = 1117.99761620977
{ 0 } sec = 21600
{ 0 } C = 7.236
{ 0 } ppm = 19.0348958844563
{ 0 } ppmhr = 3.17248264740938
Largest residual is 0
Method: Exact
Best Regards,
Mike Monett
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