url: http://escribe.com/health/thesilverlist/m63365.html
CS>Re: About a extraordinary experiment
From: Peter Rebaudo
Date: Fri, 10 Oct 2003 18:59:26
> Hi:
> Get a hold of this tale !
> The positive silver electrode is introduced into a DW container,
> 300cc, the other is outside the glass container.
> DW measures 1.0 u Siemens
> Voltage= 34V
> Supply: Sota constant current set a 1mA.
> After 2 days, 2.4uS
> After 5 days, 14.0 uS and a heaviest, by far, Tyndall I have ever
> seen.
> The final product have zero taste.
> The electrodes have no darkening or coating what so ever.
> There was no sediments.
> The container was glass 2" in diameter by 7.5" high
> Electrodes 12 Ga, 5.5" summerged.
> The voltage stay constant at 34V, there was no measurable current.
> I am looking forward to comments.
> Regards
> Peter R
Hi Peter,
You have requested comments, but have not responded to any.
You are technically literate. You have posted accurate data on
led's. You have downloaded Mercury - you posted a link to Roger's
web page where people could download Eureka, the predecessor of
Mercury. Roger wrote both programs.
http://escribe.com/health/thesilverlist/m61728.html
A quick check in Mercury shows the current required to liberate 14
ppm of silver in 300 ml of dw in 5 days is 14.77 uA.
Here's the data:
days = 5
hrs = 24 * days
ml = 300 ; volume of dw
mnt = 0 ; minutes
ppm = 14
Here's the result:
Cou = 6.381685
I = 1.477241E-05
sec = 432000.0
gm = 0.004200
k = 0.000658
lt = 0.300000
ml = 300.0000
mg = 4.200000
phr = 0.116666
ppm = 14.00000
hrs = 120.0000
Most dvms can easily measure 14 uA. You state the current was zero,
as expected. You know how to measure currents this low. So there was
no electrolysis. Even leakage currents would not suffice to explain
your data. Glass is a very good insulator, and would not support a
current of 14 uA.
You know the conductivity of air is zero for all practical purposes.
You also know placing the cathode outside the glass means no current
can flow, and there can be no electrolysis.
With no electrolysis, there can be no liberation of silver at the
anode.
Silver is insoluble in water. If you doubt this, please see a paper
on Frank's web site that discusses the solubility of silver in
distilled water. The statement is the first sentence in the second
paragraph:
http://www.silver-colloids.com/Papers/Solubility_Products.PDF
Yet your measurement implies the equivalent of 4.2 milligrams of
silver was released. This cannot be true. Silver is insoluble.
If it were contamination, it would be released at the start of the
experiment. The conductivity would increase rapidly, then remain
constant. It would not show a steady increase over 5 days. So it's
not contamination.
You have not done a salt test to see if silver ions are present. You
know it will prove there are none.
So this is a hoax, right?
Best Regards,
Mike Monett
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