Hello Al,

I don't understand Bearden's theories at all.

I am trying to learn. 

I have looked at the schematics of the MMG, and read some of the
descriptions of how the thing works, but my understanding is limited.

Do you only talk with Mensa members?

JOH

-----Original Message-----
From: [email protected] [mailto:[email protected]] 
Sent: Tuesday, October 21, 2003 12:24 AM
To: [email protected]
Cc: [email protected]
Subject: Re: CS>Re: About a extraordinary experiment


Please list the one's for me that you understand first, and detail for me
why it is that you understand each of them to be valid... Then We can
proceed with the discussion, relative to your level of understanding JOH...
That is..., JOH, Besides the fact that they have been conceived of,
constructed, and are presently tangible & repeatable proofs of theory.

With Patience,
Al
----- Original Message -----
From: <[email protected]>
To: <[email protected]>
Sent: Saturday, October 18, 2003 11:50 PM
Subject: RE: CS>Re: About a extraordinary experiment


> Hello A.F.,
>
> Which of Bearden's experiments are you going to do?
>
> Thanks in advance,
>
> JOH
>
> -----Original Message-----
> From: [email protected] [mailto:[email protected]]
> Sent: Thursday, October 16, 2003 7:17 PM
> To: [email protected]
> Cc: [email protected]
> Subject: Re: CS>Re: About a extraordinary experiment
>
>
> Hi Mike :)
>
> Please go look up Dr. Thomas Bearden on the web. There may well be 
> some factors your overlooking with classic entropy-based theory. In 
> two days Iwill have duplicated this experiment pretty closely... I'll 
> post the results.
>
> Regards,
> A.F.
>
>
> ----- Original Message -----
> From: "Mike Monett" <[email protected]>
> To: <[email protected]>
> Sent: Saturday, October 11, 2003 8:26 PM
> Subject: CS>Re: About a extraordinary experiment
>
>
> > url: http://escribe.com/health/thesilverlist/m63365.html
> > CS>Re: About a extraordinary experiment
> > From: Peter Rebaudo
> > Date: Fri, 10 Oct 2003 18:59:26
> >
> >   > Hi:
> >
> >   > Get a hold of this tale !
> >
> >   > The positive  silver electrode is introduced into a  DW container,
> >   > 300cc, the other is outside the glass container.
> >
> >   > DW measures 1.0 u Siemens
> >   > Voltage= 34V
> >   > Supply: Sota constant current set a 1mA.
> >   > After 2 days, 2.4uS
> >   > After 5 days, 14.0 uS and a heaviest, by far, Tyndall I  have ever
> >   > seen.
> >   > The final product have zero taste.
> >   > The electrodes have no darkening or coating what so ever.
> >   > There was no sediments.
> >   > The container was glass 2" in diameter by 7.5" high
> >   > Electrodes 12 Ga, 5.5" summerged.
> >   > The voltage stay constant at 34V, there was no measurable 
> > current.
> >
> >   > I am looking forward to comments.
> >
> >   > Regards
> >
> >   > Peter R
> >
> >   Hi Peter,
> >
> >   You have requested comments, but have not responded to any.
> >
> >   You are  technically  literate.  You have  posted  accurate  data on
> >   led's. You  have downloaded Mercury - you posted a  link  to Roger's
> >   web page  where  people could download  Eureka,  the  predecessor of
> >   Mercury. Roger wrote both programs.
> >
> >     http://escribe.com/health/thesilverlist/m61728.html
> >
> >   A quick  check in Mercury shows the current required to  liberate 14
> >   ppm of silver in 300 ml of dw in 5 days is 14.77 uA.
> >
> >   Here's the data:
> >
> >   days = 5
> >   hrs  = 24 * days
> >   ml   = 300 ; volume of dw
> >   mnt  = 0 ; minutes
> >   ppm  = 14
> >
> >   Here's the result:
> >
> >   Cou = 6.381685
> >   I   = 1.477241E-05
> >   sec = 432000.0
> >   gm  = 0.004200
> >   k   = 0.000658
> >   lt  = 0.300000
> >   ml  = 300.0000
> >   mg  = 4.200000
> >   phr = 0.116666
> >   ppm = 14.00000
> >   hrs = 120.0000
> >
> >   Most dvms can easily measure 14 uA. You state the current  was zero,
> >   as expected. You know how to measure currents this low. So there was
> >   no electrolysis. Even leakage currents would not suffice  to explain
> >   your data.  Glass is a very good insulator, and would not  support a
> >   current of 14 uA.
> >
> >   You know the conductivity of air is zero for all practical purposes.
> >   You also know placing the cathode outside the glass means no current
> >   can flow, and there can be no electrolysis.
> >
> >   With no  electrolysis, there can be no liberation of  silver  at the
> >   anode.
> >
> >   Silver is insoluble in water. If you doubt this, please see  a paper
> >   on Frank's  web  site  that discusses the  solubility  of  silver in
> >   distilled water.  The statement is the first sentence in  the second
> >   paragraph:
> >
> >     http://www.silver-colloids.com/Papers/Solubility_Products.PDF
> >
> >   Yet your  measurement  implies the equivalent of  4.2  milligrams of
> >   silver was released. This cannot be true. Silver is insoluble.
> >
> >   If it  were contamination, it would be released at the start  of the
> >   experiment. The  conductivity  would increase  rapidly,  then remain
> >   constant. It  would not show a steady increase over 5 days.  So it's
> >   not contamination.
> >
> >   You have not done a salt test to see if silver ions are present. You
> >   know it will prove there are none.
> >
> >   So this is a hoax, right?
> >
> > Best Regards,
> >
> > Mike Monett
> >
> >
> > --
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>
>