That is because when the transistors reach saturation the load that is
driving the equation is no longer the resistance of the water but it is the
load which the p-n junction at saturation represents that drives the
equation. Since silver ions are still entering the water the resistance of
the water continues to lower (the reciprocal of conductance) however since
the transistors are at their limit the only load felt is the resistance
across the p-n junction which will remain constant since this is the limit
of the transistor and so the voltage stays the same. I imagine the
transistors get pretty hot if left at that point for very long.
At 09:14 PM 6/27/04, you wrote:
Frankly, I don't see how the current could remain constant, and the
volts remain constant, while the conductivity is changing.
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