Morning David,

This is what ODE said.......

---------------------
 Strangely, the voltage levels off at around 4vdc and conductivity keeps
rising at a more or less linear rate while current stays rock steady.
 According to ohms law, that ain't possible.  I'm trying to figure out
what's going on.
---------------------

That statement is easy to understand.

I said a bunch of stuff trying to explain what he said, as I understand his statement.

Next you said this to explain why this is happening.

-----------------
At that point the transistors are saturated and cannot change any further. You found the lower limit of that particular transistor.
-----------------

This is totally unrelated to his statement that violates ohms law.

Next, I made this statement.....

If ...... it cannot change any further, please explain how the current remains "Rock Steady" while the
conductivity is increasing for the rest of the cycle.

I thought this to be easy to understand.

The issue is   Voltage Steady      Current Steady

Two circuit parameters STEADY,  while the conductivity is changing.

Impossible,  Violates Ohms Law.

Then you said......

At 11:00 PM 6/27/04, you wrote:
That is because when the transistors reach saturation the load that is driving the equation is no longer the resistance of the water but it is the load which the p-n junction at saturation represents that drives the equation. Since silver ions are still entering the water the resistance of the water continues to lower (the reciprocal of conductance) however since the transistors are at their limit the only load felt is the resistance across the p-n junction which will remain constant since this is the limit of the transistor and so the voltage stays the same. I imagine the transistors get pretty hot if left at that point for very long.

   In response to.......

What I said.....
At 09:14 PM 6/27/04, you wrote:
Frankly, I don't see how the current could remain constant, and the volts remain constant, while the conductivity is changing.


You are talking about how the circuit works, not circuit quantities of Volts, Current, and Resistance.

Actually, Conductance is not even one of the parameters used in the typical calculation.

If what you are saying is true, as an explanation to Odes observations, then a bunch of scientist have to have a conference and change some laws. ( now I know how and why lawyers and judges mess things up )

You can build all the fancy circuits you want, a dozen constant current circuits, a dozen regulators, a dozen IC's, and on and on and on. String them all out in one circuit, in series arrangement, power up the critter, make a batch of CS, and possibly see what Ode is seeing.

Depending entirely what you are using to LOOK at the circuit,
you will not loose a single electron in the current flow path.

The 4 Volts, and a "ROCK STEADY" current cannot exist with a load that is changing in either resistance or conductivity. ( or both as the case actually is )

Ode did not think it to be possible because it violates Ohms Law.

By the way, have you ever solved the Cube Circuit?

Draw a cube

The line segments total 12.

Redraw and replace each line segment with a resistor, all the same value

Input is upper left, output is lower right

Solve for equivalent resistance. Redraw a few equivalent circuits what doing it.

I realize this had little to do with the price of tea in China and little to do with Odes Query. But it has about as much to do with it as the internal workings of integrated circuits, transistors, regulators, ect.

For the benefit of the uninitiated who might have the courage to read this confusion, Georg Simon Ohm first figured this out in 1827. His theory was not accepted then, and it appears we don't want to accept it today. He was forced to resign his job as a teacher and lived in poverty and shame for laying the groundwork of every electrical calculation. Later his efforts were recognized when he was became a professor at the University of Munich.

I mentally pat him on the back every time I use OHMS law because of the simplicity of the ratio of the circuit parameters.

How can one get any simpler than 1 to 1 to 1 ratio?

1 Volt
1 Ohm
1 Amp

One Volt applied to one ohm produces 1 amp of current. When teaching ohms law, I use this example and several variations of it before getting into circuits where pencil or calculator are required.

Now... it amazes me that we are having trouble with this near 200 year old ONE, ONE, ONE calculation.

In my everyday work, I can do most practical calculations mentally. Talk about mental math, at IBM I had an instructor that could extract square roots mentally. That was very impressive to watch.

I sure wish he was alive today and a member of this list. Maybe he could clear up our confusion.

Wayne





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