Wayne, I wouldn't necessarily choose this way to look at the problem unless you had some way to meter the water flow. Of course, especially if you could not achieve the 6 amp current level, you could slow down the flow and thereby increase the ppms.
Using your values, 631 ml of water for 1 second at 6 amps we get 10.84 ppm. So, this is very close to what we calculated before. Dan
------------------------------------------- * From: * CWFugitt[SMTP:[email protected]] * Sent: * Sunday, November 19, 2006 9:15:35 PM * To: * [email protected] * Subject: * CS>Re: Mink rancher ( Stream Length and Velocity ) The stream length and velocity is interesting and relates to the process. Due to the small pipe, 3/4 inch, the length of the stream is relatively long. The cross sectional area of the 3/4 inch pipe is. .44 17 inches. This makes one gallon have a length of 522.97 inches. Thus 10 gallons has a length of 5229.7 inches. The length of the stream that passes the electrodes in 1 second is 87.17 inches. Converting this to ounces, we have 87.17 X .4417 = 38.50 cu in. 38.50 cu in = 630.9 ml ( or cm cubed ) Back to ounces = 21.33 So all one has to do it apply the Faraday calculation to one second and a reasonable accurate ppm should result. It would take a larger pipe to have a cu inch per linear inch. Slightly less than 1.25 inches ....... Actually a 2, 3 or 4 inch pipe might turn out better and reduce velocity considerably. I would prefer a 4 inch ( or so ) rectangular box made from stainless or whatever, with a plexiglass side, or maybe two sides with a good light on one side. One needs to see the electrodes very clearly. Someone check my math if they feel up to it.
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