Hi All,

Need one clarification on dividing/allocating the AS, RR and RS bit rates,
from the received value in the bearer modification [incoming OTA message
from the NW]

Scenario:
If DUT A and DUT B are in VT call.

After some operation DUT A receives bearer modification from the NW with DL
MBR say (400) [In the incoming OTA message]
How this DL MBR should be divided among the AS, RR and RS

Example 1:
AS: 400
RS: 5000
RR: 6000

Example 2:
AS: 389  [400 - (5000+6000)]
RS: 5000
RR: 6000

I am not clear with this calculation please help to share the inputs

*RFC 3550:*

Appendix B - Changes from RFC 1889

-  The description of the session bandwidth parameter is expanded in
Section 6.2, including a clarification that the control traffic
bandwidth is in addition to the session bandwidth for the data
traffic.


-- 

With Regards

Arun A. Tagare
+91 9449 029729
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