Hi Venkat,

RTCP bandwidth is not part of AS value.
If UE indicates the AS = 41, then overall b/w value allocated to UE during 
session is 44 [3 mbps is for RTCP (RR+RS)]

Also it depends on UE also, in case if UE indicates explicitly the RR=0 and 
RS=0, then no B/W will be allocated to RTCP.

-Bharath

From: venkat ramana [mailto:venkatramana...@gmail.com]
Sent: Tuesday, September 05, 2017 10:11 PM
To: Ranganatha, Bharath (Nokia - IN/Bangalore) <bharath.rangana...@nokia.com>
Cc: sip-implementors@lists.cs.columbia.edu; Arun Tagare <arun.taga...@gmail.com>
Subject: Re: [Sip-implementors] Dividing the AS, RR and RS values from NW 
allocated DL_MBR

Hi Bharat,

Thank you for the feedback. Yes, overall RTCP bandwidth is 5% of AS value.

But this RTCP bandwidth is in addition to AS value or part of AS value.

If AS 41, bandwidth available for RTP 41 and 2.05 for RTCP or

Bandwidth available for RTP is 38.95 and RTCP 2.05?


Regards,
Venkat Ramana

On 05-Sep-2017 9:26 PM, "Ranganatha, Bharath (Nokia - IN/Bangalore)" 
<bharath.rangana...@nokia.com<mailto:bharath.rangana...@nokia.com>> wrote:
Hi Arun,

You need to look in the SDP body for the bandwidth allocated in to the 
respective video codec..
Based on that you can calculate the RR and RS with below logic.

If UE indicates AS parameter 41 mbps, then
RS Parameter = 1.25% of AS parameter = 512 kbps
RR Parameter = 3.75% of AS Parameter = 1537 kbps

Same logic applies in your case too...


Reg,
-Bharath

-----Original Message-----
From: 
sip-implementors-boun...@lists.cs.columbia.edu<mailto:sip-implementors-boun...@lists.cs.columbia.edu>
 
[mailto:sip-implementors-boun...@lists.cs.columbia.edu<mailto:sip-implementors-boun...@lists.cs.columbia.edu>]
 On Behalf Of Arun Tagare
Sent: Saturday, September 02, 2017 11:27 AM
To: 
sip-implementors@lists.cs.columbia.edu<mailto:sip-implementors@lists.cs.columbia.edu>
Subject: [Sip-implementors] Dividing the AS, RR and RS values from NW allocated 
DL_MBR

Hi All,

Need one clarification on dividing/allocating the AS, RR and RS bit rates, from 
the received value in the bearer modification [incoming OTA message from the NW]

Scenario:
If DUT A and DUT B are in VT call.

After some operation DUT A receives bearer modification from the NW with DL MBR 
say (400) [In the incoming OTA message] How this DL MBR should be divided among 
the AS, RR and RS

Example 1:
AS: 400
RS: 5000
RR: 6000

Example 2:
AS: 389  [400 - (5000+6000)]
RS: 5000
RR: 6000

I am not clear with this calculation please help to share the inputs

*RFC 3550:*

Appendix B - Changes from RFC 1889

-  The description of the session bandwidth parameter is expanded in Section 
6.2, including a clarification that the control traffic bandwidth is in 
addition to the session bandwidth for the data traffic.


--

With Regards

Arun A. Tagare
+91 9449 029729
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