Thank you John for the information on the ccd I will post a note on 
the qcuiag board asking for info.

You took a lot of time typing the reply to me thanks I will print it 
out and try to make sense of it all.

Can you just check my calc on the 4mm and the 7.5mm please I got into 
a state over the final answer with the degrees and arcmins.

Thank you Martin




--- In [email protected], John Mahony 
<[EMAIL PROTECTED]> wrote:
> --- Martin Farmer <[EMAIL PROTECTED]> wrote:
> > 
> > I have a couple of questions that the group could possibly help 
me 
> > with these involve the Eyepiece menu and adding your own
> > 
> > I have the following eyepiece selection :-
> >  
> >  Focal Length
> >  Field of View
> >
> > Vixen
> >  13mm
> >  65�
> >  
> > Vixen
> >  40mm
> >  42�
> >  
> > Vixen
> >  4mm
> >  45�
> >  
> > TAL
> >  40mm
> >  45�
> >  
> > TAL
> >  25mm
> >  52�
> >  
> > TAL
> >  7.5mm
> >  52�  
> > 
> > I have a 1200mm focal length tube and I have put into the field 
of 
> > vision colum the following values:- 
> > 
> > 13mm = 42
> > 
> > 40mm  = 84
> 
>                                                                     
 
> > 4mm   =9
> > 
> > 40mm =90
> > 
> > 25mm = 65
> > 
> > 7.5mm=19
> > 
> > 
> > Are these the right figures to go into the Field of Vision box 
for 
> > these eyepieces, 
> 
> I checked the first two and they're correct, so assuming you used 
the same
> method for all, they should all be correct.
> 
> >Also I am confused on the CCD Field of what to put 
> > in there I have a Philips TouCam and the specification of the CCD 
is 
> > as follows:-
> > 
> > � Image size: Diagonal 4.5mm (Type 1/4)
> > 
> > � Number of effective pixels: 659 (H) � 494 (V) approx. 330K 
pixels
> > 
> > � Total number of pixels: 692 (H) � 504 (V) approx. 350K pixels
> > 
> > � Chip size: 4.60mm (H) � 3.97mm (V)
> > 
> > � Unit cell size: 5.6�m (H) � 5.6�m (V)
> > 
> > 
> > What do I put from this information into the CCD options please.
> 
> You need to convert the chip size into arcminutes (at the focal 
plane).  The
> starting point for making sense of scope optics is that two stars 
1� apart in
> the sky will focus to points in the focal plane that are 1� apart, 
as measured
> from the primary (ie, as seen from a distance of 1200mm).  A full 
circle is
> 360�, and a full circle of radius 1200mm would have a circumference 
of
> 1200*2*pi ~= 7540mm, so the two star images would be 7540/360 ~= 
21mm apart. 
> Thus the chip width of 4.6mm is 4.6/21 degrees at the focal plane, 
or about 13
> arcminutes.  The height is (3.97/21)*60 ~= 11'.  This assumes 
you're imaging at
> prime focus (no barlow, etc).
> 
> But you might want to check those numbers against images of actual 
star fields.
>  Multiplying the pixel size of 5.6� square by the 659X494 pixel 
numbers gives a
> chip size of about 3.7mm X 2.8mm, smaller than the chip size listed 
above.  So
> either there are parts of the chip surface around the perimeter not 
used for
> imaging (likely), or the pixels are larger than 5.6�, and 5.6 is 
only the size
> of the light sensitive part of each pixel (also possible).  A little
> experimentation should show the true size of the field.  Or ask on 
QCUIAG.
> 
> BTW the chip is 659X494 pixels, but I believe the actual image 
output from a
> Toucam is only 640X480 pixels.  This gives an aspect ratio of 4:3, 
so the
> actual used total light sensitive part of the chip surface (and the 
field of
> view) should have a 4:3 ratio (that's what tipped me off that 
something was
> wrong with the numbers). 
> 
> -John   
> 
> 
> 
> 
> 
> 
> 
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