Hi Pete,
thanks for the easy to follow instructions! I think what was (is)
confusing me is that the grid lines are not aligned 'nicely'. This is of
course because the grid lines move with the rotation of the Earth. That
little crucial fact slipped my mind :) It just seemed I wasn't looking
North anymore even though I was.
I noticed CdC 3.0 doesn't have the pole marked anymore with a '+'. I'll
log a ticket for that.
Sander
Peter Dean wrote:
> 1) Add Equatorial Grid
> 2) Show All Sky
> 3) N
> 4) Cursor on Polaris
> 5) Right-click, then Zoom + Centre
> 6) Keep Zoom + Centre'ing in until you have the required scale
>
> There are probably other ways, but the above works for me.
>
> Regards
> Pete
>
> -----Original Message-----
> From: [email protected]
> [mailto:[EMAIL PROTECTED] Behalf Of Sander Pool
> Sent: 10 April 2006 20:44
> To: [email protected]
> Subject: [skychart-discussion] Using CdC to facilitate polar alignment
>
>
>
> All,
>
> I'd like to use CdC to determine where Polaris is with regards to the
> true celestial pole for a particular place/time. I was hoping to do this
> graphically but it's harder than I thought it would be, probably because
> I'm missing something.
>
> I have set my observatory to the correct location and the time for
> tonight 9PM. I search for 'umi' to get polaris in the fov. I add the eq
> grid. For some reason the grid is not 'straight'. The 20h line is
> slanted to the right through my screen. I would like the screen to mimic
> what I see when I look up so I click 'N' to look North. Bummer, now it's
> looking at the North horizon instead of rotating the fov.
>
> Does anyone use CdC for this purpose? If so, what is your procedure? Do
> you simply take the coordinates of Polaris from the detail view:
>
> Star
> BSC 1 Alp UMi
> Visual Magnitude: 2.02
> Color Index: 0.60
> Spectral Class: F7:Ib-II
> Proper Motion in Right ascension: 0.038
> Proper Motion in Declination: -0.015
> HR: 424
> HD: 8890
> Common Name: POLARIS
> Date RA: 02h39m05.29s DE:+89°17'28.9
> J2000 RA: 02h31m48.70s DE:+89°15'51.0
> Ecliptic L: +88°39'20 B:+66°06'08
> Galactic L: +123°16'14 B:+26°25'37
> Visibility for observatory:
> Genève 2006-04-10 19h31m39s ( UT + -7h00m )
> Universal Time : 2006-04-11T02:31:39
> Sideral Time : 7h42m
> Hour Angle : 5h03m
> Azimuth :+359°08'
> Altitude :+37°38'
> Circumpolar
> Culmination : 14h33m
>
> And use that? If so, which value do you take? :)
>
> Thanks,
>
> Sander
>
> PS I used CdC 3.0.1.1 SVN. I think there may be a more recent snapshot
> out there but I doubt it behaves differently for this purpose.
>
>
>
>
> Yahoo! Groups Links
>
>
>
>
>
>
>
>
>
>
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