Hi Alan Yes of course, use the right focal length Say at 200mm Width of field = 57.3*(22.2/200)=6.36° = 381.6 arc minutes Hight of field = 57.3*(14.8/200)=4.24° = 254.4 arc minutes put the result in arc minutes in the right case in CDC finder mark configuration
Claude --- In [email protected], "dwango121" <arobinson...@...> wrote: > > Would I be able to use the same formula to calculate the FOV of my 18-200mm > f/3.5-6.3 lens with my 1000D? > > Thanks, > Alan > > --- In [email protected], "sky2orion" <sky2orion@> wrote: > > > > Hello > > Yes you must calculate the effective field with the instrument where > > you attach the eos1000 > > example If you use a ED80 with 600mm focal length > > Width of field = 57.3*( Width of CMOS chip / Instrument focal length) > > Hight of field =57.3 *(Hight of CMOS chip / Instrument focal length) > > > > so Field's High =57.3*(14.8/600) = 1.41°=84.6 arc minutes > > Filed length = 57.3*(22.2/600) =2.12°=127.2 arc minutes > > the results that you enter in the given fields. > > > > I hope it can help you (sorry for my bad English) > > > > Claude > > France > > 46°12'N > > 5°23'E > > > > > > > > --- In [email protected], "dwango121" > > <arobinson121@> wrote: > > > > > > Hi Everyone, > > > > > > My first post... > > > > > > I have downloaded and am using 3.0.1.4 beta and I wanted to create a > > > finder mark/frame for my EOS 1000D. The chip size is 22.2mm x 14.8mm. I > > > entered these into Width/Height in the CCD Retangle tab but when I add > > > a new finder circle on the chart it seems very small. Am I doing > > > anything wrong. Do I need to tell it what scope I am using it with > > > (ED80)? > > > > > > Thanks, > > > Al > > > > > >
