Hello Sluggers:
Here's a frustrating one Sluggers...
A system monitoring program periodically needs to generate a
list of filename with each files timestamps prepended to it:
--------sample output----------------
15:15,151500.data
15:46,154501.data
16:45,154501.data
16:55,061500.data
...
-------------------------------------
The files live in <directory> and the names have to match pattern: <pattern>.
The following works well in most situations:
ls -l <dir>/<pattern> | awk '{print $8 "," $9}'
But with more than 4000 files in a directory, ls generates the following error:
bash: /bin/ls: Argument list too long
Using find in the following manner seemed to work beautifully:
find <dir> -name <pattern> -printf "%AH:%AM,%f\n"
However, the find -format specification outputs data based on
file *access* time instead of file *creation* times.
This data is useless if the files are accessed by some other
program (say, a backup system).
Is there a way of generating the required list using command line tools
in just one pass? (or Perl)
Regards,
Sonam
--
Electronic Commerce
Corporate Express Australia Ltd.
Phone: +61-2-9335-0725 Fax: +61-2-9335-0753
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