Yes, there is overhead from the breaking of messages, something like 4-6
bytes per part (if I remember correctly) which hold indexes which are used
for the reconstruction of the message.
2008/11/8 nchin <[EMAIL PROTECTED]>
>
> Thank you very much for the reply.
>
> Ok now I know something new, i.e. there are some special characters
> that will take up two chars. But back in my mind I am wondering
> whether there is any overhead to "tell or inform" a mobile phone to
> the effect of "this is the first part of a multipart message to be
> assembled; this is the second... this is the third and last ...", etc.
> In other words, do I have to take into account the "overhead" for
> assembling info?
>
> Also, is there any plan to provide a get method to return the no. of
> parts? Like: -
> int part = getNumberOfParts(String message);
>
> Thank you very much for the kind assistance.
>
> On Nov 8, 3:54 am, Thanasis <[EMAIL PROTECTED]> wrote:
> > You are obviously talking 7bit encoded messages, right?
> >
> > All characters are encoding and counted as one character **except**
> > from the following characters:
> >
> > ~\[]{}|€
> >
> > which take double space - i.e. count as two characters.
> >
> > Does this help?
> >
> > On Nov 7, 6:32 pm, nchin <[EMAIL PROTECTED]> wrote:
> >
> >
> >
> > > I am using SMSSERVER and I understand that a big message will be sent
> > > out in multiparts. However I need to determine the big message will be
> > > broken into how many messages. I have checked the smssvr_out table but
> > > it does not give any clues how many parts a big message will be broken
> > > into.
> >
> > > Is there a object method to get the no. of parts? If not, would it be
> > > correct if I simply divide the big message into 160 characters and
> > > round up the remainder, for example: -
> >
> > > Big message = 321 character
> > > no. of parts = 321/160 = 3 parts
> >
> > > Thank you very much in advance!- Hide quoted text -
> >
> > - Show quoted text -
> >
>
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