Understood. If you need ordered, “sloppy” (some distance) phrases, you could
OR in a {!complexphrase} query.
https://cwiki.apache.org/confluence/display/solr/Other+Parsers#OtherParsers-ComplexPhraseQueryParser
<https://cwiki.apache.org/confluence/display/solr/Other+Parsers#OtherParsers-ComplexPhraseQueryParser>
Something like:
q=({!edismax … ps=0 v=$qq}) OR {!complexphrase df=nameSearch v=$qq}
where &qq=12345 masitha
Erik
> On Jun 12, 2017, at 9:57 AM, Aman Deep Singh <[email protected]>
> wrote:
>
> Yes Erik I can use ps=0 but, my problem is that I want phrase which have
> same sequence and they can be present with in some distance
> E.g.
> If I have document masitha xyz 12345
> I want that to be boosted since the sequence is in order .That's why I have
> use ps=5
> Thanks,
> Aman Deep Singh
>
> On 12-Jun-2017 5:44 PM, "Erik Hatcher" <[email protected]> wrote:
>
> Using ps=5 causes the phrase matching to be unordered matching. You’ll
> have to set ps=0, if using edismax, to get exact order phrase matches.
>
> Erik
>
>
>> On Jun 12, 2017, at 1:09 AM, Aman Deep Singh <[email protected]>
> wrote:
>>
>> Hi,
>> I'm using a phrase query ,but it was applying the phrase boost to the
> query
>> where terms are in reverse order also ,which i don't want.Is their any way
>> to avoid the phrase boost for reverse order and apply boost only in case
> of
>> terms are in same sequence
>>
>> Solr version 6.5.1
>>
>> e.g.
>> http://localhost:8983/solr/l4_collection/select?debugQuery=o
> n&defType=edismax&fl=score,nameSearch&indent=on&mm=100%25&
> pf=nameSearch&q=12345%20masitha&qf=nameSearch&wt=xml&ps=5
>>
>>
>> while my document has value
>>
>> in the debug query it is applying boost as
>> 23.28365 = sum of:
>> 15.112219 = sum of:
>> 9.669338 = weight(nameSearch:12345 in 0) [SchemaSimilarity], result of:
>> 9.669338 = score(doc=0,freq=1.0 = termFreq=1.0
>> ), product of:
>> 7.6397386 = idf, computed as log(1 + (docCount - docFreq + 0.5) / (docFreq
>> + 0.5)) from:
>> 2.0 = docFreq
>> 5197.0 = docCount
>> 1.2656635 = tfNorm, computed as (freq * (k1 + 1)) / (freq + k1 * (1 - b +
> b
>> * fieldLength / avgFieldLength)) from:
>> 1.0 = termFreq=1.0
>> 1.2 = parameter k1
>> 0.75 = parameter b
>> 5.2576485 = avgFieldLength
>> 2.56 = fieldLength
>> 5.44288 = weight(nameSearch:masitha in 0) [SchemaSimilarity], result of:
>> 5.44288 = score(doc=0,freq=1.0 = termFreq=1.0
>> ), product of:
>> 4.3004165 = idf, computed as log(1 + (docCount - docFreq + 0.5) / (docFreq
>> + 0.5)) from:
>> 70.0 = docFreq
>> 5197.0 = docCount
>> 1.2656635 = tfNorm, computed as (freq * (k1 + 1)) / (freq + k1 * (1 - b +
> b
>> * fieldLength / avgFieldLength)) from:
>> 1.0 = termFreq=1.0
>> 1.2 = parameter k1
>> 0.75 = parameter b
>> 5.2576485 = avgFieldLength
>> 2.56 = fieldLength
>> 8.171431 = weight(*nameSearch:"12345 masitha"~5 *in 0) [SchemaSimilarity],
>> result of:
>> 8.171431 = score(doc=0,freq=0.33333334 = phraseFreq=0.33333334
>> ), product of:
>> 11.940155 = idf(), sum of:
>> 7.6397386 = idf, computed as log(1 + (docCount - docFreq + 0.5) / (docFreq
>> + 0.5)) from:
>> 2.0 = docFreq
>> 5197.0 = docCount
>> 4.3004165 = idf, computed as log(1 + (docCount - docFreq + 0.5) / (docFreq
>> + 0.5)) from:
>> 70.0 = docFreq
>> 5197.0 = docCount
>> 0.6843655 = tfNorm, computed as (freq * (k1 + 1)) / (freq + k1 * (1 - b +
> b
>> * fieldLength / avgFieldLength)) from:
>> 0.33333334 = phraseFreq=0.33333334
>> 1.2 = parameter k1
>> 0.75 = parameter b
>> 5.2576485 = avgFieldLength
>> 2.56 = fieldLength
>>
>> Thanks,
>> Aman Deep Singh
